2√2 + √32 -1/3 √450 +2/7 √392
7\3 + 1\2 + -16\32
65\91 + -33\55
36\-84 + 109\450
4/20 + 16\42 + 6\10 + -3\5 + 2\21 + -10\21 + 3\10
5\12 + 3\-16 + 3\4
giải hộ mik với nha
X:2+32 187=69 392
X=?
x : 2 = 69 392 - 32 187
x : 2 = 37 205
x = 37 205 x 2
x = 74 410
vậy x = ...
X : 2 = 69 392 - 32 187
X : 2 = 37 205
X = 37 205 x 2
X = 74 410
Vậy x = 74 410
Bài1:Thực hiện phép tính:
a,(2^4.3.5^2):{450:[450-(4.5^3-2^3.5^2)]}
b,3^3.5^2-20{90-[164-2.(7^8:7^6+7^0)]}
c,[(18^7:18^6-17).2022-1986].5.1^2022-13^2.2020^0
Bài2:Tìm x:
a,(2^x+1)^2+3.(2^2+1)=2^2.10
b,3.(x-7)+2.(x+5)=41
(GIÚP MIK VỚI Ạ)
Bài 1.
\(a,\left(2^4\cdot3\cdot5^2\right):\left\{450:\left[450-\left(4\cdot5^3-2^3\cdot5^2\right)\right]\right\}\)
\(=\left(16\cdot3\cdot25\right):\left\{450:\left[450- \left(4\cdot125-8\cdot25\right)\right]\right\}\)
\(=\left(48\cdot25\right):\left\{450:\left[450-\left(500-200\right)\right]\right\}\)
\(=1200:\left[450:\left(450-300\right)\right]\)
\(=1200:\left(450:150\right)\)
\(=1200:3\)
\(=400\)
\(---\)
\(b,3^3\cdot5^2-20\left\{90-\left[164-2\cdot\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=27\cdot25-20\left\{90-\left[164-2\cdot\left(7^2+1\right)\right]\right\}\)
\(=675-20\left\{90-\left[164-2\cdot\left(49+1\right)\right]\right\}\)
\(=675-20\left[90-\left(164-2\cdot50\right)\right]\)
\(=675-20\left[90-\left(164-100\right)\right]\)
\(=675-20\left(90-64\right)\)
\(=675-20\cdot26\)
\(=675-520\)
\(=155\)
\(---\)
\(c,\left[\left(18^7:18^6-17\right)\cdot2022-1986\right]\cdot5\cdot1^{2022}-13^2\cdot2020^0\)
\(=\left[\left(18-17\right)\cdot2022-1986\right]\cdot5\cdot1-169\cdot1\)
\(=\left(1\cdot2022-1986\right)\cdot5-169\)
\(=\left(2022-1986\right)\cdot5-169\)
\(=36\cdot5-169\)
\(=180-169\)
\(=11\)
Bài 2.
\(a) (2^x+1)^2+3\cdot(2^2+1)=2^2\cdot10\\\Rightarrow (2^x+1)^2+3\cdot(4+1)=4\cdot10\\\Rightarrow (2^x+1)^2+3\cdot5=40\\\Rightarrow (2^x+1)^2+15=40\\\Rightarrow (2^x+1)^2=40-15\\\Rightarrow (2^x+1)^2=25\\\Rightarrow (2^x+1)^2= (\pm 5)^2\\\Rightarrow \left[\begin{array}{} 2^x+1=5\\ 2^x+1=-5 \end{array} \right.\\ \Rightarrow \left[\begin{array}{} 2^x=4\\ 2^x=-6 (vô.lí) \end{array} \right. \\ \Rightarrow 2^x=2^2\\\Rightarrow x=2\)
Vậy \(x=2\).
\(---\)
\(b)3\cdot(x-7)+2\cdot(x+5)=41\\\Rightarrow 3\cdot x+3\cdot(-7)+2\cdot x+2\cdot5=41\\\Rightarrow 3x-21+2x+10=41\\\Rightarrow (3x+2x)+(-21+10)=41\\\Rightarrow 5x-11=41\\\Rightarrow 5x=41+11\\\Rightarrow 5x=52\\\Rightarrow x=\dfrac{52}{5}\)
Vậy \(x=\dfrac{52}{5}\).
\(Toru\)
Bình đọc cuốn sách dày 450 trang trong 3 ngày. Ngày 1 Bình đọc được 32% tổng số trang sách. Ngày 2 Bình đọc được số trang sách bằng 7/10 số trang ngày 3 đọc. Tính số trang mỗi ngày đọc được?
a,210-5(x-11)=200
b,(2x+1):7=2^2+3^2
c,450:[41-(2x-5]=3^2.5
d,(5x-9).7+3=80
\(a,210-5\left(x-11\right)=200\\ \Rightarrow5\left(x-11\right)=10\\ \Rightarrow x-11=2\\ \Rightarrow x=13.\\ b,\left(2x+1\right):7=2^2+3^2\\ \Rightarrow\left(2x+1\right):7=4+9\\ \Rightarrow\left(2x+1\right):7=13\\ \Rightarrow2x+1=91\\ \Rightarrow2x=90\\ \Rightarrow x=45.\\ c,450:\left[41-\left(2x-5\right)\right]=3^2.5\\ \Rightarrow450:\left[41-\left(2x-5\right)\right]=45\\ \Rightarrow41-\left(2x-5\right)=10\\ \Rightarrow2x-5=31\\ \Rightarrow2x=36\\ \Rightarrow x=18.\\ d,\left(5x-9\right).7+3=80\\ \Rightarrow\left(5x-9\right).7=77\\ \Rightarrow5x-9=11\\ \Rightarrow5x=20\\ \Rightarrow x=4.\)
a) \(210-5\left(x-11\right)=200\)
\(5.\left(x-11\right)=210-200\)
\(5.\left(x-11\right)=10\)
\(x-11=10:5\)
\(x-11=2\)
\(x=2+11\)
\(x=13\)
b) \(\left(2x+1\right):7=2^2+3^2\)
\(\left(2x+1\right):7=13\)
\(2x+1=13.7\)
\(2x=91-1\)
\(2x=90\)
\(x=90:2\)
\(x=45\)
c) \(450:\left[41-\left(2x-5\right)\right]=3^2.5\)
\(450:\left[41-\left(2x-5\right)\right]=45\)
\(\left[41-\left(2x-5\right)\right]=450:45\)
\(\left[41-\left(2x-5\right)\right]=10\)
\(2x-5=41-10\)
\(2x-5=31\)
\(2x=31+5\)
\(2x=36\)
\(x=36:2\)
\(x=18\)
d) \(\left(5x-9\right).7+3=80\)
\(\left(5x-9\right).7=80-3\)
\(5x-9=77:7\)
\(5x-9=11\)
\(5x=11+9\)
\(5x=20\)
\(x=20:5\)
\(x=4\)
1/ 600 : { 450 : [450 - ( 4* 5 mủ 3 -2 mủ 3 * 5 ) ] }
2/ 3 mủ 2 *10 mủ 3 - [13 mủ 2 - ( 5 mủ 2 * 4 + 2 mủ 2 * 15) ]* 10 mủ 3
3/1506 - {5 mủ 2 * 2 mủ 3 - 11 [ 7 mủ 2 - 5 * 2 mủ 3+ 8(11 mủ 2 - 12 ) ] }
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\(\frac{450}{7}x\frac{2}{5}=\)
\(\frac{450}{7}x\frac{1}{3}\)
1)\(\frac{450}{7}x\frac{2}{5}\)
=\(\frac{900}{35}\)=\(\frac{900:5}{35:5}=\frac{180}{7}\)
2)
\(\frac{450}{7}x\frac{1}{3}=\frac{450}{21}=\frac{450:3}{21:3}=\frac{150}{7}\)
\(\frac{450}{7}\)\(x\)\(\frac{2}{5}\)= \(\frac{180}{7}\)
\(\frac{450}{7}x\frac{1}{3}=\frac{150}{7}\)
Chúc bạn học tốt .k cho mk nhé
\(\frac{450}{7}.\frac{2}{5}=\frac{90}{7}.2=\frac{180}{7}\)
\(\frac{450}{7}.\frac{1}{3}=\frac{150}{7}.1=\frac{150}{7}\)
x+5.2-(32+16.3;16-15)=0
2448;[119-(x-6)=24
20-[7.(x-3)+4]=2
x;[(1800+600);30]=560;(315-35)
[(1250-25);15];x=(450-60);130
bài5
a, 20 - [30 - (5 - 1)2 ]
b, 71 + 50 : [5 + 3. (57 - 6.7)]
c, 4.{270 : [50 - (25 + 45 : 5)]}
d. 411 - [(107 + 3) : 5 - 22 ]
e, 450 - 5. [32. (75 : 73 - 41) - 12] + 18
f, 102 - 150 : [18 - 2. (10 - 8)2 ] + 10180
a: \(20-\left[30-\left(5-1\right)^2\right]\)
\(=20-\left[30-4^2\right]\)
\(=20-14=6\)
b: \(71+\dfrac{50}{5+3\left(57-6\cdot7\right)}\)
\(=71+\dfrac{50}{5+3\cdot\left(57-42\right)}\)
\(=71+\dfrac{50}{5+3\cdot15}=71+\dfrac{50}{50}=72\)
c: \(4\cdot\left\{270:\left[50-\left(2^5+45:5\right)\right]\right\}\)
\(=4\cdot\left\{270:\left[50-32-9\right]\right\}\)
\(=4\cdot\left\{\dfrac{270}{50-41}\right\}=4\cdot\dfrac{270}{9}=4\cdot30=120\)
d: \(411-\left[\dfrac{\left(107+3\right)}{5}-2^2\right]\)
\(=411-\left[\dfrac{110}{5}-4\right]\)
=410-22+4
=410-18
=392
e: \(450-5\left[3^2\left(7^5:7^3-41\right)-12\right]+18\)
\(=450-5\left[9\cdot\left(7^2-41\right)-12\right]+18\)
\(=450-5\cdot\left[9\cdot8-12\right]+18\)
=468-5*60
=468-300
=168
f:
\(102-150:\left[18-2\cdot\left(10-8\right)^2\right]+1018^0\)
\(=102-150:\left[18-2\cdot4\right]+1\)
\(=103-\dfrac{150}{18-8}=103-15=88\)