tính
A=\(\left(1-\sqrt{7}\right).\dfrac{\sqrt{7}+7}{2\sqrt{7}}\)
B=\(3\sqrt{3}+4\sqrt{12}-5\sqrt{27}\)
C=\(\sqrt{32}-\sqrt{50}+\sqrt{18}\)
D=\(\sqrt{72}+\sqrt{4\dfrac{1}{2}}-\sqrt{32}-\sqrt{162}\)
E=\(\dfrac{1}{2}\sqrt{48}-2\sqrt{75}-\dfrac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\dfrac{1}{3}}\)
1 Tính
a \(\sqrt{36}-\sqrt{100}\)
b Tìm x để biểu thức \(\sqrt{\dfrac{2}{2x-1}}\) có nghĩa
2 Thực hiện phép tính
a) A = \(\left(15\sqrt{180}-5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
b) B = \(\sqrt{32}-\sqrt{50}-16\sqrt{\dfrac{1}{8}}\)
bài 1 thực hiện pt
a)\(\sqrt{75}-2\sqrt{27}+\sqrt{48}\)
b)\(\dfrac{\left(12\sqrt{50}-8\sqrt{200}+\dfrac{7}{3}\sqrt{450}\right)}{\sqrt{10}}\)
c)\(\sqrt{8+2\sqrt{7}}-\sqrt{11-4\sqrt{7}}\)giải hộ mik
6) (3\(\sqrt{2}\) -\(\sqrt{3}\))(\(\sqrt{3}\)+3\(\sqrt{2}\))
7) \(\sqrt{72}\)+\(\sqrt{4\dfrac{1}{2}}\) - \(\sqrt{32}\) - \(\sqrt{162}\)
\(2\sqrt{8\sqrt{3}}-\sqrt{2\sqrt{3}}-\sqrt{9\sqrt{12}}\)
\(\sqrt{3}+\sqrt{7-4\sqrt{3}}\)
\(\sqrt{\left(\sqrt{7}-4\right)^2}-\sqrt{28}+\sqrt{63}\)
\(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
\(\sqrt{3}-2\sqrt{48}+3\sqrt{75}-4\sqrt{108}\)
Bài 1 : Rút gọn :
a)b)1/√5-2 +1−√5+2
b,3√2-2√8+1/2√32−√50
c)√7+√5√7−√5+√7−√5√7+√57+57−5+7−57+5
d) (√14−√71−√2+√15−√51−√3)1√7−√5
Anh em giúp mình nhớ mai mình kiểm tra rồi nhé
\(\left(\frac{2\sqrt{32}}{\sqrt{3}}-1\right):\left(7-\frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}}\right)\)
a, \(\sqrt{200}-\sqrt{32}+\sqrt{72}\)
b, \(4\sqrt{20}-3\sqrt{125}+5\sqrt{45}-15\sqrt{\dfrac{1}{5}}\)
c, \(\left(2\sqrt{8}+3\sqrt{5}-7\sqrt{2}\right)\left(72-5\sqrt{20}-2\sqrt{2}\right)\)
Cho ΔABC vuông tại A thỏa mãn \(BC^2=\left(\sqrt{3}+1\right).AC^2+\left(\sqrt{3}-1\right).AB.AC\).Tính số đo góc ACB
A.450 B.150 C.600 D.300