J= 1/2.5 + 9/5.7 + 4/14.9 + 8/18.13 + 12/2619
G=3/2.5+3/5.7+3/7.9+...+3/2015.2017
H=3/2.5+3/5.7+3/7.9+...+3/2015.2017
(3/3.6+3/3.9+...+3/30.33). x+2/5=7/8
(1/8+1/24+1/48+1/440). x=5/9
x:3/4+2,5=15%+16
khó wá giúp mình với huhu
G=\(\frac{3}{2.5}+\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{2015.2017}\)
G=\(3.\left(\frac{1}{2.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{2015.2017}\right)\)
G=\(3.\left(\frac{1}{2}.\frac{1}{5}+\frac{1}{5}.\frac{1}{7}+\frac{1}{7}.\frac{1}{9}+...+\frac{1}{2013}.\frac{1}{2015}+\frac{1}{2015}.\frac{1}{2017}\right)\)
G=\(3.\left(\frac{1}{2}+\frac{1}{2017}\right)\)
G=1.5
Anh ko bik có đúng ko nữa lâu quá rồi. Em thông cảm nhé
30.4^7.3^99-5.14^5-2^12/5^4.6^14.9^7-12.8^5.7^6
B=(30.4^7.3^29-5.14^5.2^12)/(54.6^14.9^7-12.8^5.7^5)
Giúp mk gấp nha 😊
Tính
a)S1=\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b)S2=\(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
c)S3=\(\frac{1}{10.9}+\frac{1}{18.13}+\frac{1}{26.17}+...+\frac{1}{802.405}\)
\(S1=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{99.101}\)
\(S1=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-....-\frac{1}{101}=\frac{1}{1}-\frac{1}{101}=\frac{100}{101}\)
\(S2=\frac{5}{1.3}+\frac{5}{3.5}+....+\frac{5}{99.101}\)
\(S2=\frac{5}{2}.\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-.....-\frac{1}{101}\right)=\frac{5}{2}.\left(\frac{1}{1}-\frac{1}{101}\right)=\frac{5}{2}\cdot\frac{100}{101}=\frac{250}{101}\)
Tính các tổng sau
1 :D = 1.3 +2.3+3.4+........+99.100
2 . E= 1.3 +3.5+5.7+.........+97.99
3.F= 2.4 + 4.6+ 6+8+..........+98.1009
4. G=1.4+2.5+3.6+........+97.100
Giúp mình nhé . Mình cần gấp
Tính giá trị biểu thức:
B= \(\dfrac{\left(-2\right)^{24}.3^5-4^{12}.9^2}{8^8.3^5}+\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{301.303}\)
\(B=\dfrac{2^{24}\cdot3^5-2^{24}\cdot3^4}{2^{24}\cdot3^5}+1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{301}-\dfrac{1}{303}\)
\(=\dfrac{2^{24}\cdot3^4\left(3-1\right)}{2^{24}\cdot3^5}+\dfrac{302}{303}\)
\(=\dfrac{2}{3}+\dfrac{302}{303}=\dfrac{202+302}{303}=\dfrac{504}{303}\)
=168/101
A.3^x=243 B.4^x=4096 C. 5^3-x=25 D.8^2x-3=512 E.2214-5.7^2x-3=499 J. 2^x+3+2^x+1=80
a: 3^x=243
=>3^x=3^5
=>x=5
b: 4^x=4096
=>4^x=4^5
=>x=5
c: 5^3-x=25
=>3-x=2
=>x=1
d: =>2x-3=3
=>2x=6
=>x=3
j: =>2^x*8+2^x*2=80
=>2^x=8
=>x=3
Bài 1 Tính
a)(-6-8).(-9+4)
b)(8.4-2):(-5)
c)-8.9-(-9+21)
d)-5.7+(-32):8-(-15+54)
e)78:(-6.5+36)
f)15:(-5).(-3)-12
g)45-15:+3-18:6+12
Ai nhanh nhất mình tích nha
a)=(-14).(-5)
=70
b)=(32-2):(-5)
=30:(-5)
=-6
c)=-72-12
=-84
d)=-35+(-4)-39
=-39-39
=-78
e)=78:(-30+36)
=78:6
=13
f)=-3.(-3)-12
=9-12
=-3
g)=45-5-2+12
=40-2+12
=38+12
=50
mình giải luôn chứ mik hông chép đề đâu nha^^
a) (-6 - 8) . (-9 + 4)
= (-14) . (-5)
= 70.
b) (8. 4 - 2) : (-5)
= (32 - 2) : (-5)
= 30 : (-5)
= -6.
c) -8. 9 - (-9 + 21)
= -8. 9 - 12
= -72 - 12
= -84.
d) -5. 7 + (-32) : 8 - (-15 + 54)
= -5. 7 + (-32) : 8 - 39
= -35 + (-32) : 8 - 39
= -35 + (-4) - 39
= -39 - 39
= -78.
e) 78 : (-6. 5 + 36)
= 78 : (-30 + 36)
= 78 : 6
= 13.
f) 15 : (-5). (-3) - 12
= -3. (-3) - 12
= 9 - 12
= -3.
g) 45 - 15 : +3 - 18 : 6 + 12
= 45 - 5 - 18 : 6 + 12
= 45 - 5 - 3 + 12
= 40 - 3 + 12
= 37 + 12
= 49.
bài 1
a)(-6-8).(-9+4)=14.(-5)=-70
b)(8.4-2):(-5)=30:(-5)=-6
c)-8.9-(-9+21)
= -8.9-12
= -72-12
= -84
d)-5.7+(-32):8-(-15+54)
= -5.7+(-32):8-39
=-35+(-4)-39
=39+(-39)
=0
e)78:(-6.5+36)
=78:6
=13
f)15:(-5).(-3)-12
=-3.(-3)-12
=9-12
=-3
g)45-15:3-18:+6+12
=45-5-3+12
=40-3+12
=37+12
=49
bài 1
a,-1/8 - (320% + 9/5 ) . (1/4 - 1/8
b,4/3.5 + 4/5.7 + 4/7.9 + ......+4/99.100
bài 2
a,x+ 3/22 = 27/121.11/9
Đặt \(A=\frac{4}{3.5}+\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{99.101}\)
\(\Rightarrow\frac{1}{2}A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{99.101}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{3}-\frac{1}{101}\)
\(\Rightarrow\frac{1}{2}A=\frac{101}{303}-\frac{3}{303}\)
\(\Rightarrow\frac{1}{2}A=\frac{98}{303}\)
\(\Rightarrow A=\frac{98}{303}\div\frac{1}{2}\)
\(\Rightarrow A=\frac{199}{303}\)
\(x+\frac{3}{22}=\frac{27}{121}.\frac{11}{9}\)
\(\Leftrightarrow x+\frac{3}{22}=\frac{27.11}{121.9}\)
\(\Leftrightarrow x+\frac{3}{22}=\frac{3.1}{11.1}\)
\(\Leftrightarrow x+\frac{3}{22}=\frac{3}{11}\)
\(\Leftrightarrow x=\frac{3}{11}-\frac{3}{22}\)
\(\Leftrightarrow x=\frac{6}{22}-\frac{3}{22}\)
\(\Leftrightarrow x=\frac{3}{22}\)