1/3x + 3/4x - 75% = -5 1/4

=> x - 3/4 = -21/4

=> x = -21/4 + 3/4

=> x = -9/2

60%x + 5/6x = -76

=> 3/5x + 5/6x = -76

=> 43/30x = -76

=> x = -76 : 43/30

=> x = -2280/43

\(\frac{1}{3}x+\frac{3}{4}x-75\%=-5\frac{1}{4}\)

\(\frac{13}{12}x-\frac{3}{4}=-\frac{21}{4}\)

\(\frac{13}{12}x=-\frac{9}{2}\)

\(x=-\frac{54}{13}\)

\(60\%.x+\frac{2}{3}x=-76\)

\(\frac{3}{5}x+\frac{2}{3}x=-76\)

\(\frac{19}{15}x=-76\)

\(x=-60\)

Có cần ghi lời giải luôn ko bạn.

cần...........thanks bạn trước nhé

tớ không biết nhưng bạn có thẻ bấm dúng cho tớ không vì chúng ta la bạn bè mà

<=>\(\left(\frac{x+1}{77}+1\right)+\left(\frac{x+2}{76}+1\right)=\left(\frac{x+3}{75}+1\right)+\left(\frac{x+4}{74}+1\right)\)

<=> \(\frac{x+1+77}{77}+\frac{x+2+76}{76}=\frac{x+3+75}{75}+\frac{x+4+74}{74}\)

<=> \(\frac{x+78}{77}+\frac{x+78}{76}=\frac{x+78}{75}+\frac{x+78}{74}\)

<=> \(\frac{x+78}{77}+\frac{x+78}{76}-\frac{x+78}{75}-\frac{x+78}{74}\)

<=> \(\left(x+78\right)\left(\frac{1}{77}+\frac{1}{76}-\frac{1}{75}-\frac{1}{74}\right)\)

Vì \(\frac{1}{77}+\frac{1}{76}-\frac{1}{75}-\frac{1}{74}\ne0\) nên phương trình trên <=> x + 78 = 0

<=> x = -78

Tập nghiệm của phương trình trên là S= \(\left\{-78\right\}\)

Chúc bạn học tốt !

Ta có: \(\frac{x+1}{79}+\frac{x+4}{76}=-\frac{x+7}{73}-\frac{x+9}{71}-4\)

\(\Leftrightarrow\frac{x+1}{79}+\frac{x+4}{76}+\frac{x+7}{73}+\frac{x+9}{71}+4=0\)

\(\Leftrightarrow\frac{x+1}{79}+1+\frac{x+4}{76}+1+\frac{x+7}{73}+1+\frac{x+9}{71}+1=0\)

\(\Leftrightarrow\frac{x+80}{79}+\frac{x+80}{76}+\frac{x+80}{73}+\frac{x+80}{71}=0\)

\(\Leftrightarrow\left(x+80\right)\left(\frac{1}{79}+\frac{1}{76}+\frac{1}{73}+\frac{1}{71}\right)=0\)

Vì \(\frac{1}{79}+\frac{1}{76}+\frac{1}{73}+\frac{1}{71}>0\)

nên x+80=0

hay x=-80

Vậy: x=-80

ko có kết quả sao bạn

  \(a.\) \(3\frac{3}{4}+\left(4\frac{2}{4}-3\frac{1}{2}\right):\frac{3}{4}\)

\(=\frac{15}{4}\left(\frac{18}{4}-\frac{7}{2}\right):\frac{3}{4}\)

\(=\frac{15}{4}+\frac{4}{4}:\frac{3}{4}=\frac{15}{4}+\frac{4}{3}\)

\(=\frac{15}{4}+\frac{4}{3}=\frac{61}{12}\)

\(b.\) \(7\cdot\frac{2}{3}-\frac{2}{5}:\frac{1}{2}-\frac{2}{3}\)

\(=\frac{7}{3}-\frac{2}{5}\cdot2-\frac{2}{3}\)

\(=\frac{7}{3}-\frac{4}{5}-\frac{2}{3}=\frac{35-12-10}{15}\)

\(=\frac{13}{15}\)

\(c.\) \(68,7-100:20+70,8\)

\(=68,7-5+70,8\)

\(=63,7+70,8\)

\(=134,5\)

\(d.\)\(\left(5915+445:5\right)-76\cdot25\)

\(=\left(5915+89\right)-1900\)

\(=6004-1900=4104\)

a)=\(\frac{15}{4}+\left(\frac{18}{4}-\frac{7}{2}\right)\)/ \(\frac{3}{4}\)

=\(\left(\frac{33}{4}-\frac{14}{4}\right)\)/ \(\frac{3}{4}\)

= \(\frac{19}{4}\cdot\frac{4}{3}\)

=\(\frac{19}{3}\)

b) = \(\frac{2}{3}\cdot\left(7-1\right)-\frac{2}{5}\cdot\frac{2}{1}\)

= \(\frac{2}{3}\cdot6-\frac{4}{5}\)

= 1-\(\frac{4}{5}\)

= \(\frac{1}{5}\)

c) = 68.7 - 5 + 70.8 

= 63.7 + 70.8

=134.5

d) = (5915 - 89) -76*25

= 5826 - 1900

= 3926

XIN LỖI MK LÀM NHẦM CÂU B):

\(b.\)\(7\cdot\frac{2}{3}-\frac{2}{5}:\frac{1}{2}-\frac{2}{3}\)

\(=\frac{14}{3}-\frac{2}{5}\cdot2-\frac{2}{3}\)

\(=\frac{14}{3}-\frac{4}{5}-\frac{2}{3}\)

\(=\frac{70-12-10}{15}=\frac{48}{15}=\frac{16}{5}\)

Bài làm

a) \(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x-4}\)

\(\Leftrightarrow\frac{3x+2}{3x-2}-\frac{6}{3x+2}=\frac{9x^2}{\left(3x-2\right)\left(3x+2\right)}\)

\(\Leftrightarrow\frac{(3x+2)\left(3x+2\right)}{(3x-2)\left(3x+2\right)}-\frac{6\left(3x-2\right)}{(3x+2)\left(3x-2\right)}=\frac{9x^2}{\left(3x-2\right)\left(3x+2\right)}\)

\(\Rightarrow\left(3x+2\right)^2-\left(18x-12\right)=9x^2\)

\(\Leftrightarrow9x^2+12x+4-18x+12x-9x^2=0\)

\(\Leftrightarrow6x+4=0\)

\(\Leftrightarrow x=-\frac{4}{6}\)

\(\Leftrightarrow x=-\frac{2}{3}\)

Vậy x = -2/3 là nghiệm.

@Tao Ngu :))@ 9x-4 không tách thành (3x+4)(3x-4) được đâu bạn. Chỗ đó phải là: 9x²-4

Bài thiếu đkxđ của x \(\hept{\begin{cases}3x-2\ne0\\2+3x\ne0\end{cases}\Leftrightarrow\hept{\begin{cases}3x\ne2\\3x\ne-2\end{cases}\Leftrightarrow}\hept{\begin{cases}x\ne\frac{2}{3}\\x\ne\frac{-2}{3}\end{cases}\Leftrightarrow}x\ne\pm\frac{2}{3}}\)

b) Bạn kiểm tra lại đề bài

c) \(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8}{16x^2-1}\left(x\ne\pm\frac{1}{4}\right)\)

\(\Leftrightarrow\frac{3}{1-4x}-\frac{2}{4x+1}+\frac{8}{16x^2-1}=0\)

\(\Leftrightarrow\frac{-3}{4x+1}-\frac{2}{4x+1}+\frac{8}{\left(4x+1\right)\left(4x-1\right)}=0\)

\(\Leftrightarrow\frac{-3\left(4x-1\right)}{\left(4x-1\right)\left(4x+1\right)}-\frac{2\left(4x-1\right)}{\left(4x-1\right)\left(4x+1\right)}+\frac{8}{\left(4x-1\right)\left(4x+1\right)}=0\)

\(\Leftrightarrow\frac{-12x+3}{\left(4x-1\right)\left(4x+1\right)}-\frac{8x-2}{\left(4x-1\right)\left(4x+1\right)}+\frac{8}{\left(4x-1\right)\left(4x+1\right)}=0\)

\(\Leftrightarrow\frac{-12x+3-8x+2+8}{\left(4x-1\right)\left(4x+1\right)}=0\)

=> -20x+13=0

<=> -20x=-13

<=> \(x=\frac{13}{20}\left(tmđk\right)\)

mình ko bít

=0,04  nhá

cho mình xin cách giải bạn ơi

a) Ta có:

\(\begin{array}{l}\frac{x}{3} = \frac{y}{4} \Rightarrow \frac{x}{3}.\frac{1}{5} = \frac{y}{4}.\frac{1}{5} \Rightarrow \frac{x}{{15}} = \frac{y}{{20}};\\\frac{y}{5} = \frac{z}{6} \Rightarrow \frac{y}{5}.\frac{1}{4} = \frac{z}{6}.\frac{1}{4} \Rightarrow \frac{y}{{20}} = \frac{z}{{24}}\end{array}\)

Vậy  \(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}}\) (đpcm)

b) Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}} = \frac{{x - y + z}}{{15 - 20 + 24}} = \frac{{ - 76}}{{19}} =  - 4\)

Vậy x = 15 . (-4) = -60; y = 20. (-4) = -80; z = 24 . (-4) = -96

x/2=y/5 ; y/3=z/4 ; z/6=t/11

<=> \(\frac{x}{6}=\frac{y}{15}=\frac{z}{20}\); z/6=t/11

<=> \(\frac{x}{36}=\frac{y}{90}=\frac{z}{120}=\frac{t}{220}\)

Áp dụng t/c dãy tỉ số bằng nhau ta có

\(\frac{x}{36}=\frac{y}{90}=\frac{z}{120}=\frac{t}{220}=\frac{2x+y-z+\frac{t}{2}}{2.36+90-120+\frac{220}{2}}=\frac{-76}{152}=\frac{-1}{2}\)

Từ đó => ddc x,y,z