`@` `\text {Ans}`

`\downarrow`

`a,`

`5.125.25 \div 5^6`

`=`\(5\cdot5^3\cdot5^2\div5^6\)

`=`\(5^{1+3+2-6}=5^{6-6}=5^0=1\) 

`b,`

\(2^{14}\div\left(2^6\cdot32\right)\)

`=`\(2^{14}\div\left(2^6\cdot2^5\right)\)

`=`\(2^{14}\div2^{11}=2^3\)

`c,`

`3.3^5\div 27`

`=`\(3\cdot3^5\div3^3\)

`=`\(3^{1+5-3}\)

`=`\(3^3\) 

`d,`

\(2^{15}\div\left(2^6\cdot32\right)=2^{15}\div\left(2^6\cdot2^5\right)=2^{15}\div2^{11}=2^4\)

`e,`

\(3^2\cdot27\div81=3^2\cdot3^3\div3^4=3\)

`g,`

\(100\cdot1000\cdot10000-10^9=10^2\cdot10^3\cdot10^4-10^9\)

`=`\(10^9-10^9=0\)

`h,`

\(125^4\div5^9=\left(5^3\right)^4\div5^9=5^{12}\div5^9=5^3\)

a) 1

b) 8

c) 27

d) 16

e) 3

g) 0

h) 125

a. 130

b. 50

c.301

tìm x

a. 2

b. 5

tính

chữ số tận cùng 0

mk chỉ lm nhiêu đó thui. sorry

a) 3.3³+7⁴⁹:7⁴⁷ = 3⁴ + 7² = 130

a) 5.( 12- x ) - 20= 30 

5.( 12 - x) = 50 

12 -x =10 

x = 2

a) S = 3+6+9+...+ 2016 

= ( 2016 + 3) . 674 = tự tính!

a) Ta có theo lần lượt mũ 7 : t1 = 7; t2 = 9; t3 = 3 ; t4 = 1; t5 = 7;....

=> 7⁹ tận cùng là 7 

=> tận cùng của 7⁹ + 3 là 0

a) a = 1 + 2 + 2² + 2³ + ... + 2²⁰¹⁶

b = 2²⁰¹⁷ - 1 

Để so sánh ta chỉ cần triển khai a ra = cách đặt thừa số mũ 2....

 Tíc nhé, mình đang bị âm điểm, mỗi câu mình làm 1 ý,.........

\(a)3\times3^3+7^{49}\div7^{47}=3^4+7^2=130\)

\(a)5\times\left(12-x\right)-20=30\)

\(\Rightarrow5\times\left(12-x\right)=50\)

\(\Rightarrow12-x=10\)

\(\Rightarrow x=2\)

\(a)S=3+6+9+...+2016\)

\(\Rightarrow\left(2016+3\right)\times674=1360806\)

\(a)\)Ta có lần lượt mũ: 

\(7\div t1=7;t2=9;t3=3;t4=1;t5=7;...\)

\(\Rightarrow7^9\)tận cùng là \(7\)

\(\Rightarrow\)tận cùng của \(7^9+3\)là \(0\)

\(a)a=1+2+2^2+2^3+...+2^{2016}\)

\(b=2^{2017}-1\)

Để so sánh ta chỉ cần chuyển khai \(a\)ra \(=\)cách đặt thừa số mũ ...

\(\left(\dfrac{2}{3}\right)^3.\left(\dfrac{-3}{4}\right)^2.\left(-1\right)^{2013}=\dfrac{8}{27}.\dfrac{9}{16}.\left(-1\right)=-\dfrac{1}{6}\)

\(\left(\dfrac{1}{5}\right)^{15}.\left(\dfrac{1}{4}\right)^{20}=\dfrac{1}{5^{12}}.\dfrac{1}{4^{20}}=5^{-12}.4^{-20}=125^{-4}.1024^{-4}=\left(125.1024\right)^{-4}=128000^{-4}\)

\(\dfrac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}=\dfrac{2^{12}.3^{10}+2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}=\dfrac{2^{12}.3^{10}+2^{12}.2^{10}.5}{2^{12}.3^{12}+2^{11}.3^{11}}=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}\left(2.3+1\right)}=\dfrac{2.6}{3.7}=\dfrac{4}{7}\)

\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)

a: =>6/x=3/8

hay x=16

b: =>x/27=1/9

nên x=3

c: =>4/x=4/3

nên x=3

d: =>3/x-5=-4/x+2

=>3x+2=-4x+20

=>7x=18

hay x=18/7

.....

\(A=\dfrac{12^{15}\cdot3^4-4^5\cdot3^9}{27^3\cdot2^{10}-32^3\cdot3^9}\\ =\dfrac{\left(2^2\cdot3\right)^{15}\cdot3^4-\left(2^2\right)^5\cdot3^9}{\left(3^3\right)^3\cdot2^{10}-\left(2^5\right)^3\cdot3^9}\\ =\dfrac{2^{30}\cdot3^{15}\cdot3^4-2^{10}\cdot3^9}{3^9\cdot2^{10}-2^{15}\cdot3^9}\\ =\dfrac{3^9\cdot2^{10}\left(2^{20}\cdot3^{10}\right)}{3^9\cdot2^{10}\left(1-2^5\right)}\\ =\dfrac{\left(2^2\right)^{10}\cdot3^{10}}{1-32}\\ =\dfrac{\left(2^2\cdot3\right)^{10}}{-31}\\ =\dfrac{-12^{10}}{31}\)

\(B=\dfrac{3}{1^2\cdot2^2}+\dfrac{5}{2^2\cdot3^2}+...+\dfrac{99}{49^2\cdot50^2}\\ =\dfrac{2^2-1^2}{1^2\cdot2^2}+\dfrac{3^2-2^2}{2^2\cdot3^2}+...+\dfrac{50^2-49^2}{49^2\cdot50^2}\\ =\dfrac{1}{1^2}-\dfrac{1}{2^2}+\dfrac{1}{2^2}-\dfrac{1}{3^2}+...+\dfrac{1}{49^2}-\dfrac{1}{50^2}\\ =1-\dfrac{1}{2500}\\ =\dfrac{2499}{2500}\)

2.3^x=10.3¹²+8.27⁴

2.3^x=10.3¹²+8.3¹²

2.3^x=3¹²(10+8)

2.3^x=3¹².18

3^x=3¹².18:2

3^x=3¹².9

3^x=3¹².3²

3^x=3¹⁴

=>x=14