(1/4+1/7)x1/3 (1/4-1/7)x1/3
Tính bằng 2 cách nha
Tính bằng hai cách
(1/4+1/7)x1/3
(1/4+1/7)x1/3
C1:
(1/4+1/7)x1/3=11/28x1/3
=11/84
C2:
(1/4=1/7)x1/3=1/3x1/4+1/3x1/7
=1/12+1/21
=11/84
cho mk nhé, có fb kb vs mk đi nè <3 <3
3:tính bằng hai cách
(1/4+1/7)x1/3
trình bầy đầy đủ nha
\(\left(\dfrac{1}{4}+\dfrac{1}{7}\right)\times\dfrac{1}{3}\\ =\left(\dfrac{7}{28}+\dfrac{4}{28}\right)\times\dfrac{1}{3}\\ =\dfrac{11}{28}\times\dfrac{1}{3}\\ =\dfrac{11}{84}\)
C1:
\(\left(\dfrac{1}{4}+\dfrac{1}{7}\right)\times\dfrac{1}{3}\\ =\left(\dfrac{7}{28}+\dfrac{4}{28}\right)\times\dfrac{1}{3}\\ =\dfrac{11}{28}\times\dfrac{1}{3}\\ =\dfrac{11}{84}\)
C2:
\(\left(\dfrac{1}{4}+\dfrac{1}{7}\right)\times\dfrac{1}{3}\\ =\dfrac{1}{4}\times\dfrac{1}{3}+\dfrac{1}{7}\times\dfrac{1}{3}\\ =\dfrac{1}{12}+\dfrac{1}{21}\\ =\dfrac{7}{84}+\dfrac{4}{84}\\ =\dfrac{11}{84}\)
(1/4 + 1/7) x 1/3
= 11/28 x 1/3
= 11/84
(1/4 + 1/7) x 1/3
= 1/4 x 1/3 + 1/7 x 1/3
= 1/12 + 1/21
= 11/84
Bài 1. Tính bằng cách thuận tiện nhất:
a)(1/3+1/5)x1/4 b)5/3 x 4/5 x 6/7 c) 2/5 x 3/7 + 2/5 x 4/7
a: =8/15x1/4=2/15
b: \(=\dfrac{5}{3}\cdot\dfrac{4}{5}\cdot\dfrac{6}{7}=\dfrac{24}{21}=\dfrac{8}{7}\)
c: \(=\dfrac{2}{5}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{2}{5}\)
Tính bằng cách hợp lý nhất 1 1/3 x 1 1/4 x1/5 x 1 1/6 x 1/1/7 x1 1/8 =
1 1/3 x 1 1/4 x 1 1/5 x 1 1/6 x 1 1/7 x 1 1/8 = 4/3 x 5/4 x 6/5 x 7/6 x 8/7 x 9/8 = 4x5x6x7x8x9/3x4x5x6x7x8 = 9/3 = 3
1\(\frac{1}{2}\)x1\(\frac{1}{3}\)x1\(\frac{1}{4}\)x1\(\frac{1}{5}\)x1\(\frac{1}{6}\)x1\(\frac{1}{7}\)x1\(\frac{1}{7}\)x1\(\frac{1}{8}\)x 1\(\frac{1}{9}\)x 1\(\frac{1}{10}\)tính bằng cách thuận tiện nhất
tính bằng cách thuận tiện nhất
\(1\frac{1}{2}x1\frac{1}{3}x1\frac{1}{4}=\)
giúp mik nha
\(1\frac{1}{2}\times1\frac{1}{3}\times1\frac{1}{4}\)
=\(\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\)
=3-3\4-4x\(\frac{5}{2}\)
=\(\frac{5}{2}\)
\(1\frac{1}{2}.1\frac{1}{3}.1\frac{1}{4}=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}=2.\frac{5}{4}=\frac{5}{2}\)
1) Tính NHa
a)563x23+23x38-23
b)7/11+3/4+4/11+1/4-1và2/5
c)(1-1/2)x1-1/3)x1-1/4)x......(1-1/10)
d)2/7x3/9+2/7x2/3
a) 563 x 23 + 23 x 28 - 23
= 23 x (563 + 28 - 1)
= 23 x 600
= 19200
b) \(\frac{7}{11}+\frac{3}{4}+\frac{4}{11}+\frac{1}{4}-1\frac{2}{5}=\left(\frac{7}{11}+\frac{4}{11}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)-\frac{7}{5}=2-\frac{7}{5}=\frac{3}{5}\)
c) \(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times...\times\left(1-\frac{1}{10}\right)=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times....\times\frac{9}{10}\)
\(=\frac{1\times2\times3\times...\times9}{2\times3\times4\times...\times10}=\frac{1}{10}\)
d) \(\frac{2}{7}\times\frac{3}{9}+\frac{2}{7}\times\frac{2}{3}=\frac{2}{7}\times\left(\frac{3}{9}+\frac{2}{3}\right)=\frac{2}{7}\times1=\frac{2}{7}\)
a ) \(563\cdot23+23\cdot28-23\)
\(=23\cdot\left(563+28-1\right)\)
\(=23\cdot600\)
\(=19200\)
b ) \(\frac{7}{11}+\frac{3}{4}+\frac{4}{11}+\frac{1}{4}-1\frac{2}{5}=\left(\frac{7}{11}+\frac{4}{11}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)-\frac{7}{5}=2-\frac{7}{5}=\frac{3}{5}\)
c ) \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{10}\right)=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{9}{10}\)
\(=\frac{1\cdot2\cdot3\cdot...\cdot9}{2\cdot3\cdot4\cdot...\cdot10}=\frac{1}{10}\)
d ) \(\frac{2}{7}\cdot\frac{3}{9}+\frac{2}{7}\cdot\frac{2}{3}=\frac{2}{7}\cdot\left(\frac{3}{9}+\frac{2}{3}\right)=\frac{2}{7}\cdot1=\frac{2}{7}\)
Bài 7: (Đề 2) Tính nhanh
\(1\dfrac{1}{2}x1\dfrac{1}{3}x1\dfrac{1}{4}x...x1\dfrac{1}{999}\)
\(...=\dfrac{3}{2}x\dfrac{4}{3}x\dfrac{5}{4}x\dfrac{6}{5}x\dfrac{7}{6}....x\dfrac{1000}{999}\)
\(=\dfrac{1}{2}x\dfrac{1000}{1}=500\)
=3/2x4/3x5/4x....x1000/999
=1/2x1000=500
mình chưa chắc là đúng đâu nhé
Nếu phương trình sau:x^2-2x-1=0 có 2 nghiệm x1,x2(x1<x2) thì hãy tính giá trị các đại lượng sau mà ko giải PT(bài này làm theo định lí Vi-et)
1.((x1^2+2)/x1)+((x2^2+2)/x2)
2.(x2/(x2^2-3))+(x1/(x1^2-3))
3.(x1^2/(x1.x2^2-1))+(x2^2/(x1^2.x2-1))
4.(x1/(3.x1.x2^2-1)+(x2/3.x1^2.x2-1)
5.(1/x1)-(1/x2)
6.(x1/(x2-1))+(x2/(x1-1))
7.((3x1-7)/x2)-((3x2-7)/x1)
Mọi người giúp mình với