cho B=4/3+7/32+10/33+...+91/330
chứng minh rằng B<11/4
Cho: A = 3 + 32 + 33 + ..... + 330
Chứng minh: A ⋮ 13
A ⋮ 52
\(A=3\left(1+3+3^2\right)+...+3^{28}\left(1+3+3^2\right)\)
\(=13\left(3+...+3^{28}\right)⋮13\)
CHỨNG MINH RẰNG
A= 88+220 chia hết cho 17
B= 2+ 22+23+24+...+260 chia hết cho 3; cho 7; cho 15
C= 1+3+32+33+...+31991 chia hết cho 13; cho 41
D=3+32+33+34+...+32010 chia hết cho 4;cho 13
A = 8⁸ + 2²⁰
= (2³)⁸ + 2²⁰
= 2²⁴ + 2²⁰
= 2²⁰.(2⁴ + 1)
= 2²⁰.17 ⋮ 17
Vậy A ⋮ 17
Chứng minh rằng:
A = 1/3 + 1/32 + 1/33 + ..........+ 1/399 < 1/2
B = 3/12x 22 + 5/22 x 32 + 7/32 x 42 +............+ 19/92 x 102 < 1
C = 1/3 + 2/32 + 3/33 + 4/34 +.........+ 100/3100 ≤ 0
\(A=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{99}}\)
\(\Rightarrow\dfrac{A}{3}=\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\)
\(\Rightarrow A-\dfrac{A}{3}=\dfrac{2A}{3}=\left(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{99}}\right)-\left(\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow\dfrac{2A}{3}=\left(\dfrac{1}{3^2}-\dfrac{1}{3^2}\right)+\left(\dfrac{1}{3^3}-\dfrac{1}{3^3}\right)+...+\left(\dfrac{1}{3^{99}}-\dfrac{1}{3^{99}}\right)+\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)=\dfrac{1}{3}-\dfrac{1}{3^{100}}\)
\(\Rightarrow2A=3\cdot\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow\text{A}=\dfrac{1-\dfrac{1}{3^{99}}}{2}\)
\(\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{2.3^{99}}< \dfrac{1}{2}\)
Giúp Mình mấy bài này với nhe!!!
1. Cho Y = 1+3+32+33+.....+398
Chứng tỏ rằng Y⋮13.
2. Cho A = 1+3+32+33.....+32018+32019
Chứng tỏ rằng A⋮4.
3. 2.(x+4)+5=65 (Tìm x).
4.Cho A = 119+ 118+117+.....+11+1. Chứng minh rằng A⋮5. Phần A nha!!!
B) Chứng minh rằng với mọi số tự nhiên n thì n2+n+1 không chia hết cho 4.
5. a) 96-3.(x+1)=42 ( Tìmx )
b) 15x-9x+2x=72
c) 3x+2+3x=10
6. a) 125-3.(x+8)=77
b) (7x-11)3= 22.52- 73
c) 5x+1+5x+2= 750
d) (2x-1)2018= (2x-1)2019.
\(1,Y=\left(1+3+3^2\right)+\left(3^3+3^4+3^5\right)+...+\left(3^{96}+3^{97}+3^{98}\right)\\ Y=\left(1+3+3^2\right)\left(1+3^3+...+3^{96}\right)\\ Y=13\left(1+3^3+...+3^{96}\right)⋮13\\ 2,A=\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{2018}+3^{2019}\right)\\ A=\left(1+3\right)\left(1+3^2+...+3^{2019}\right)\\ A=4\left(1+3^2+...+3^{2019}\right)⋮4\\ 3,\Leftrightarrow2\left(x+4\right)=60\Leftrightarrow x+4=30\Leftrightarrow x=36\)
chứng minh rằng 16^10+32^7 chia hết cho 33
\(16^{10}+32^7=\left(2^4\right)^{10}+\left(2^5\right)^7=2^{40}+2^{35}=2^{35}.2^5+3^{35}=2^{35}.\left(2^5+1\right)=2^{35}.33\)
chia hết cho 33
tick nhé
Bài 6. Cho B = 3 + 32 +33 + ...+ 3120 . Chứng minh rằng: a) B chia hết cho 3; b) B chia hết cho 4; c) B chia hết cho 13.
\(B=3+3^2+3^3+...+3^{120}\)
Dễ thấy \(B\)chia hết cho \(3\)do là tổng của các số hạng chia hết cho \(3\).
\(B=3+3^2+3^3+...+3^{120}\)
\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{119}+3^{120}\right)\)
\(=3\left(1+3\right)+3^3\left(1+3\right)+...+3^{119}\left(1+3\right)\)
\(=4\left(3+3^3+...+3^{119}\right)⋮4\)
\(B=3+3^2+3^3+...+3^{120}\)
\(=\left(3+3^2+3^3\right)+...+\left(3^{118}+3^{119}+3^{120}\right)\)
\(=3\left(1+3+3^2\right)+...+3^{118}\left(1+3+3^2\right)\)
\(=13\left(3+...+3^{118}\right)⋮13\)
Cho B 3 32 33 ... 3120 . Chứng minh rằng:
a) B chia hết cho 3
b) B chia hết cho 4
c) B chia hết cho 13
a) \(B\)là tổng các số hạng chia hết cho \(3\)nên chia hết cho \(3\).
b) \(B=3+3^2+...+3^{120}\)
\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{119}+3^{120}\right)\)
\(=3\left(1+3\right)+3^3\left(1+3\right)+...+3^{119}\left(1+3\right)\)
\(=4\left(3+3^3+...+3^{119}\right)⋮4\)
c) \(B=3+3^2+...+3^{120}\)
\(=\left(3+3^2+3^3\right)+...+\left(3^{118}+3^{119}+3^{120}\right)\)
\(=3\left(1+3+3^2\right)+...+3^{118}\left(1+3+3^2\right)\)
\(=13\left(3+3^4+...+3^{118}\right)⋮13\)
7\3 + 1\2 + -16\32
65\91 + -33\55
36\-84 + 109\450
4/20 + 16\42 + 6\10 + -3\5 + 2\21 + -10\21 + 3\10
5\12 + 3\-16 + 3\4
giải hộ mik với nha
Câu 1: Chứng minh rằng 2 + 1/2 +1/3 + 1/4 +...+ 1/67 > 5
Câu 2: Cho B = 1/22 +1/32 +...+ 1/902
Chứng minh 42/91 < B < 1