a.Ta có:
\(\dfrac{14}{18}=\dfrac{7}{9}=\dfrac{7\times5}{9\times5}=\dfrac{35}{45}\)
\(\dfrac{21}{35}=\dfrac{3}{5}=\dfrac{3\times9}{5\times9}=\dfrac{27}{45}\)
\(\Rightarrow\dfrac{14}{18}>\dfrac{21}{35}\)

14/8 = 35/45 , 21/35 = 27/45

nên 14/18>21/35

(HT)

\(\dfrac{90}{126}=\dfrac{5}{7}\)

\(\Rightarrow\dfrac{90}{126}< \dfrac{6}{7}\) (Vì \(\dfrac{5}{7}< \dfrac{6}{7}\))

\(\dfrac{35}{49}=\dfrac{5}{7}\)

\(\Rightarrow\dfrac{90}{126}=\dfrac{35}{49}\) (Vì \(\dfrac{5}{7}=\dfrac{5}{7}\))

\(\dfrac{90}{126}\) = \(\dfrac{90:18}{126:18}\) = \(\dfrac{5}{7}\) so sánh \(\dfrac{5}{7}< \dfrac{6}{7}\) nên \(\dfrac{90}{126}< \dfrac{6}{7}\)

\(\dfrac{90}{126}=\dfrac{5}{7}\) và \(\dfrac{35}{49}\) = \(\dfrac{35:7}{49:7}=\dfrac{5}{7}\) so sánh \(\dfrac{5}{7}=\dfrac{5}{7}\) nên \(\dfrac{90}{126}=\dfrac{35}{49}\)

`40/35= 8/7`

`8=8->40/35=8/7`

\(\frac{16}{48}=\frac{16:16}{48:16}=\frac{1}{3}\);\(\frac{14}{35}=\frac{14:7}{35:7}=\frac{2}{5}\)

\(\frac{1}{3}=\frac{1\cdot5}{3\cdot5}=\frac{5}{15}\);    \(\frac{2}{5}=\frac{2\cdot3}{5\cdot3}=\frac{6}{15}\)

a) 

\(\dfrac{6}{12}=\dfrac{6:6}{12:6}=\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{2}=\dfrac{1\times2}{2\times2}=\dfrac{2}{4}\)

Mà \(\dfrac{2}{4}< \dfrac{3}{4}\)

Vậy \(\dfrac{6}{12}< \dfrac{3}{4}\).

b)

\(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)

Mà \(\dfrac{2}{5}< \dfrac{4}{5}\)

Vậy \(\dfrac{2}{5}< \dfrac{8}{10}\).

c)

\(\dfrac{40}{35}=\dfrac{40:5}{35:5}=\dfrac{8}{7}\)

Mà \(\dfrac{8}{7}>\dfrac{6}{7}\)

Vậy \(\dfrac{40}{35}>\dfrac{6}{7}\).

d)

\(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)

Mà \(\dfrac{1}{2}< \dfrac{5}{2}\)

Vậy \(\dfrac{8}{16}< \dfrac{5}{2}\).

a: 90/126=5/7<6/7

b: 70/84=5/6

35/42=5/6

=>70/84=35/42

a)\(\dfrac{90}{126}=\dfrac{5}{7}< \dfrac{6}{7}\Leftrightarrow\cdot\dfrac{90}{126}< \dfrac{6}{7}\)

b)\(\dfrac{70}{84}=\dfrac{5}{6};\dfrac{35}{42}=\dfrac{5}{6}\Leftrightarrow\cdot\dfrac{70}{84}=\dfrac{35}{42}\)

20/35 rút gọn thành 4/7>3/7

=>20/35>3/7 nhé

\(\dfrac{4}{7}>\dfrac{3}{7}\)

\(\dfrac{20}{35}=\dfrac{20:5}{35:5}=\dfrac{4}{7}\)

\(\dfrac{4}{7}>\dfrac{3}{7}nên\dfrac{20}{35}>\dfrac{3}{7}\)

3 5   :   3 4   =   3 5   x   4 3   =   12 15   =   4 5