\(\frac{2^3\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}\)

\(=\frac{2^3\cdot5^2\cdot11\cdot11\cdot7}{2^3\cdot5^2\cdot5\cdot7\cdot7\cdot11}\)

\(=\frac{11}{5\cdot7}=\frac{11}{35}\)

ta có 2^3*5^2*11^2*(7/2)^3*5^3*7^2*11

=(2^3*(7/2)^3*7^2)*(5^2*5^3)*(11^2*11)

=(2^3*7^3/2^3*7^2)*5^5*11^3

=7^5*5^5*11^3

=17+21: [36-(2^2.3+2.11-70^0)]

=17+21:[36-(4.3+22-1)]

=17+21:(36-33)

=17+21:3

=17+7

=24

17+21:[36-(2² .3 +2.11-70⁰)]

=17+21:[36-(4 .3 +2.11-1)]

=17+21:[36-(12 +22-1)]

=17+21:[36-(34-1)]

=17+21:(36-33)

=17+21:3

=17+7

=24

giúp e đg cần gấp ạa

\(a^2.a^3.a^7.b^2.b\)

\(=a^{2+3+7}.b^{2+1}\)

\(=a^{12}.b^3\)

\(a^2.a^3.a^7.b^2.b=\left(a^2.a^3.a^7\right)\left(b^2.b\right)=\left(a^{2+3+7}\right)\left(b^{2+1}\right)=a^{12}.b^3\)

7^2 x 3 - 5^2 x 3

= 3 x ( 7^2 - 5^2 )

= 3 x ( 49 - 25 )

= 3 x 24

= 72 

7\(^2\)x3-5\(^2\)x3

=49x(-22)x3

=-3234

7². 3 - 5² . 3

= 49.3 - 25.3

= 3.(49 - 25)

= 3.24

= 72

\(2^8:2^2+3^3:3^3\)

=64+1

=65

\(2^8:2^2+3^3:3^3\)

= \(2^{8-2}+3^{3-3}\)

= \(2^6+3^0\)

= 64 + 1

= 65

cho mình hỏi 3 mũ 3 chia 3 bằng bao nhiêu

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