1)

3*(x+1)-12=15                        4*(x-3)+12=40

=> 3*(x+1)=27                       => 4*(x-3)=28

=> x+1=9                              => x-3=7

=> x=8                                  => x=10

tui nhầm ở câu cuối đó 6 * 19 * 4 + 3 * 81* 8

mình nhầm câu cuối 6*19*4+3*81*8

\(l,\\ 2^x=1=2^0\\ Vậy:x=0\\ m,\\ 3^x=81=3^4\\ Vậy:x=4\\ n,\\ 3^x=37=3^3\\ Vậy:x=3\\ o,\\ 9^x=3^4=\left(3^2\right)^2=9^2\\ Vậy:x=2\)

l) x = 0

m) x = 4

n) x = 3

o) x = 2

l) \(2^x=1\)

\(\Rightarrow2^x=2^0\)

\(\Rightarrow x=0\)

m) \(3^x=81\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

n) \(3^x=27\)

\(\Rightarrow3^x=3^3\)

\(\Rightarrow x=3\)

o) \(9^x=3^4\)

\(\Rightarrow9^x=\left(3^2\right)^2\)

\(\Rightarrow9^x=9^2\)

\(\Rightarrow x=2\)

\(B=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{2019}\right)\left(1-\frac{1}{2020}\right)\)

\(B=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{2018}{2019}\cdot\frac{2019}{2020}\)

Số nào xuất hiện 2 lần thì thay thế những số đó bằng số 1.

\(B=\frac{1}{2020}\)

B = \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2019}\right).\left(1-\frac{1}{2020}\right)\)

    = \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2018}{2019}.\frac{2019}{2020}\)

    = \(\frac{1.2.3...2019}{2.3.4..2020}\)(Nếu có 2 thừa số giống nhau lặp lại ở tử số và mẫu số thì rút gọn coi như triệt tiêu hết và không có gì)

   =  \(\frac{1}{2020}\)

\(B=\left(1-\frac{1}{2}\right)....\left(1-\frac{1}{2020}\right)\)

\(B=\frac{1}{2}.\frac{2}{3}....\frac{2019}{2020}\)

\(B=\frac{1.2.3...2019}{2.3.4....2020}\)

\(B=\frac{1}{2020}\)

Vậy B = 1/2020

2^n.4=128

2^n=128:4

2^n=32

2^n=2^5

Suy ra n=5

3^n+1.9=81

3^n+1=81:9

3^n+1=9

3^n+1=3^2

Suy ra n=1

15^n-2=9^2:3^4

15^n-2=3^4:3^4

15^n-2=3^0

15^n-2=1

15^n-2=15^0

Suy ra n=2

co gi ko hieu thi hoi nha

a) 2ⁿ . 4 = 128

<=> 2ⁿ . 2² = 2⁷

<=> 2ⁿ⁺² = 2⁷

<=> n+2 = 7

n = 7 - 2

n = 5

b) 3ⁿ⁺¹ . 9 = 81

<=> 3ⁿ⁺¹ . 3² = 3⁴

<=> 3ⁿ⁺¹⁺² = 3⁴

<=> n+3 = 4

n = 4 - 3

n = 1

c) 15^n-2 = 9² : 3⁴

15^n-2 = 1

<=> 15^n-2 = 15⁰

<=> n-2 = 0

n = 0 + 2

n = 2

a) \(6⋮\left(x-1\right)\left(đkxđ:x\ne1;x\inℕ\right)\)

\(\Rightarrow x-1\in U\left(6\right)=\left\{1;2;3;6\right\}\)

\(\Rightarrow x\in\left\{2;3;4;7\right\}\)

b) \(14⋮\left(2x+3\right)\left(đkxđ:x\ne-\dfrac{3}{2};x\inℕ\right)\)

\(\Rightarrow2x+3\in U\left(14\right)=\left\{1;2;7;14\right\}\)

\(\Rightarrow x\in\left\{-1;-\dfrac{1}{2};2;\dfrac{9}{2}\right\}\)

\(\Rightarrow x\in\left\{-2\right\}\)

\(a,6⋮\left(x-1\right)\\ \Rightarrow\left(x-1\right)\inƯ\left(6\right)=\left\{\pm1;\pm2;\pm3;\pm6\right\}\\ Ta.có:x-1=-6\Rightarrow x=-5\left(loại\right)\\ x-1=-3\Rightarrow x=-2\left(loại\right)\\ x-1=-2\Rightarrow x=-1\left(loại\right)\\ x-1=-1\Rightarrow x=0\left(nhận\right)\\ x-1=1\Rightarrow x=2\left(nhận\right)\\ x-1=2\Rightarrow x=3\left(nhận\right)\\ x-1=3\Rightarrow x=4\left(nhận\right)\\ x-1=6\Rightarrow x=7\left(nhận\right)\\ Vậy:x\in\left\{0;2;3;4;7\right\}\)

a)\(4x\left(x-5\right)-\left(x-1\right)\left(4x-3\right)=5\)

    \(4x^2-20x-\left(4x^2-7x+3\right)=5\)

    \(4x^2-20x-4x^2+7x-3=5\)

     \(-13x=8\)

      \(x=-\frac{8}{13}\)

b)\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)

     \(48x^2-32x+5+3x-48x^2-7+112x=81\)

     \(83x-2=81\)

     \(x=1\)

=>(x+1)²=2²

=>x+1=2

=>x=2-1=1

Vậy x=1

          (x+1)²=4

=>      (x+1)² - 2²=0

(X+1)^2=4

(X+1)^2=2^2

=>X+1=2

X=2-1

X=1

VẬY X=1

a) \(\left(x+5\right)^3=64\)

\(\Leftrightarrow\left(x+5\right)^3=4^3\)

\(\Leftrightarrow x+5=4\)

\(\Leftrightarrow x=-1\)

Vậy x = - 1

b) \(x:\left(-\frac{3}{5}\right)^2=-\frac{3}{5}\)

\(\Leftrightarrow x=\left(-\frac{3}{5}\right)^2.\left(-\frac{3}{5}\right)\)

\(\Leftrightarrow x=\left(-\frac{3}{5}\right)^3\)

\(\Leftrightarrow x=-0,216\)

Vậy x = - 0, 216

c) \(\left(\frac{4}{7}\right)^4.x=\left(\frac{4}{7}\right)^6\)

\(\Leftrightarrow x=\left(\frac{4}{7}\right)^6:\left(\frac{4}{7}\right)^4\)

\(\Leftrightarrow x=\left(\frac{4}{7}\right)^2\)

\(\Leftrightarrow\text{x}=\frac{16}{49}\)

Vậy x = 16/49

d) \(\left(-\frac{1}{3}\right)^3x=\frac{1}{81}\)

\(\Leftrightarrow-\frac{1}{27}x=\frac{1}{81}\)

\(\Leftrightarrow x=\frac{1}{81}:\left(-\frac{1}{27}\right)\)

\(\Leftrightarrow x=-\frac{1}{3}\)

Vậy x = - 1/3