\(3^4.3^{x+1}=3^{20}\)
\(3^{x+5}=3^{15+5}\)
\(=>x=15\)
Vậy x=15
\(81\cdot3^{x+1}=3^{20}\)
\(3^4\cdot3^x\cdot3=3^{20}\)
\(3^5\cdot3^x=3^{20}\)
\(3^x=3^{20}:3^5=3^{15}\)
\(\Rightarrow x=15\)
a) 81 . 3x+1 = 320
=> 34 . 3x+1 = 320
=> 34 . 3x . 3= 320
=> 34 . 3 . 3x = 320
=> 35 . 3x = 320
=> 3x = 320 : 35
=> 3x = 315
=> x = 15