(6^3.8^4):12^3

=> ( 216 . 4096 ) : 1728

=> 884736 : 1728 = 512

\(\left(6^3\times8^4\right)\div12^3\)

\(=\left(216\times4096\right)\div1728\)

\(=884736\div1728\)

\(=512\)

(6³×8⁴)÷12³

=(216×4096)÷1728

=884736÷1728

=512

ko biey

( 6^3 x 8^4 ) : 12^3

= 6^3 x 8^4 = 4

=> 4 : 12^3

=> 1

chắc chắn 100%

a) \(3^6.3^7\) \(=3^{13}\)

b) \(x^{10}:x^6:x\)

\(=x^{10}:x^7\)\(=x^3\)

c) \(a^5.a^9=a^{14}\)

\(a,=3^{6+7}=3^{13}\\ b,=x^{10-6-1}=x^3\\ c,=a^{5+9}=a^{14}\\ d,=2^3\cdot2^{15}\cdot2^{16}=2^{34}\\ e,=5^6\cdot5^5\cdot5^5=5^{16}\\ f,=a^{10+4-12}=a^2\)

d) \(2^3.8^5.16^4\)

\(=2^3.\left(2^3\right)^5.\left(2^4\right)^4\)

\(=2^3.2^{15}.2^{16}\)

\(=2^{34}\)

e) \(25^3.5^5.3125\)

\(=\left(5^2\right)^3.5^5.5^5\)

\(=5^6.5^5.5^5\)

\(=5^{16}\)

f) \(a^{10}.a^4:a^{12}\)

\(=a^{14}:a^{12}\)

\(=a^2\)

a) \(5^2.21-5^2.16\)

= \(5^2.\left(21-16\right)\)

= \(5^2.5\)

= \(5^3\)

\(a,\) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}+\left(2.3\right)^9.2^3.3.5}{2^{12}.3^{12}-\left(2.3\right)^{11}}\)
\(=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{\left(2^{12}.3^{10}\right)\left(1+5\right)}{\left(2^{11}.3^{11}\right)\left(2.3-1\right)}\)
\(=\frac{\left(2^{12}.3^{10}\right).6}{\left(2^{11}.3^{11}\right).5}\)
\(=\frac{2.6}{3.5}\)
\(=\frac{2.2}{5}\)
\(=\frac{4}{5}\)
\(b,\) \(\frac{2^{15}.9^4}{6^3.8^3}\)
\(=\frac{2^{15}.3^8}{2^3.3^3.2^9}\)
\(=\frac{2^{15}.3^8}{2^{12}.3^3}\)
\(=2^3.3^5\)
\(=8.243\)
\(=1944\)
Chúc bạn học tốt ^^


 

a) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{\left(2^2\right)^6.\left(3^2\right)^5+6^9.120}{\left(2^3\right)^4.3^{12}-6^{11}}=\frac{2^{12}.3^{10}+6^9.120}{2^{12}.3^{12}-6^{11}}=\frac{6^{10}.4+6^{10}.20}{6^{12}-6^{11}}=\frac{6^{10}.\left(4+20\right)}{6^{11}.\left(6-1\right)}=\frac{6^{11}.4}{6^{11}.5}=\frac{4}{5}\)

b) \(\frac{2^{15}.9^4}{6^3.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^3.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^3.3^3.2^9}=\frac{2^{15}.3^8}{2^{12}.3^3}=2^3.3^5=1944\)

c) \(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(4.2\right)^{10}+4^{10}}{\left(2^3\right)^4+4^6.4^5}=\frac{4^{10}.2^{10}+4^{10}}{2^{12}+4^6.4^5}=\frac{4^{10}.\left(2^{10}+1\right)}{4^6+4^6.2^{10}}=\frac{4^{10}.\left(2^{10}+1\right)}{4^6.\left(1+2^{10}\right)}=\frac{4^{10}}{4^6}=4^4=256\)