\(\dfrac{0.5+0.\left(3\right)-0.1\left(6\right)}{2.5+1.\left(6\right)-0.8\left(3\right)}\)

\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{6}}{\dfrac{5}{2}+\dfrac{5}{3}-\dfrac{5}{6}}=\dfrac{1}{5}\)

a) 0,16 + 1,3

= \(\frac{4}{25}+\frac{13}{10}\)

= \(\frac{40}{250}+\frac{325}{250}\)

= \(\frac{73}{50}\)

b) 1,3 + 0,12 . \(2\frac{8}{11}\)

= \(\frac{13}{10}+\frac{3}{25}\times\frac{30}{11}\)

= \(\frac{13}{10}+\frac{18}{55}\)

= \(\frac{143}{110}+\frac{36}{110}\)

= \(\frac{179}{110}\) 

c) 0,6 + 1,6

= \(\frac{3}{5}+\frac{8}{5}\)

= \(\frac{11}{5}\)

d) 3,6 + 1,36 \(\times\)\(2\frac{1}{5}\)

= \(\frac{18}{5}+\frac{34}{25}\times\frac{11}{5}\)

= \(\frac{18}{5}+\frac{374}{125}\)

= \(\frac{450}{125}+\frac{374}{125}\)

= \(\frac{824}{125}\)

                                     0,(3)=\(\frac{3}{9}\)

                                     0,1(6)=\(\frac{1}{6}\)

                                     1,(6)=\(\frac{10}{6}\)

                                     0,8(3)=\(\frac{5}{6}\)

                                                                     tick nha

\(a,=\dfrac{4}{33}+\dfrac{1}{3}=\dfrac{5}{11}\\ b,=\dfrac{1}{6}-\dfrac{5}{3}+\dfrac{1}{2}=-1\)

\(=\dfrac{1}{5}\)