a: =>2x^3=58-4=54

=>x^3=27

=>x=3

b; =>(5-x)^5=2^5

=>5-x=2

=>x=3

c: =>(5x-6)^3=4^3

=>5x-6=4

=>5x=10

=>x=2

d: (3x)^3=(2x+1)^3

=>3x=2x+1

=>x=1

1=>2x³=54
=>x³=27  =>x=3
2=>(5-x)⁵=2⁵
=>5-x=2
=>x=3
3=>(5x-6)³=4³
=>5x-6=4
=>5x=10=>x=2
4=>3x=2x+1
=>x=1

`2027-100(x+32)=3^8 :3^5`

`=>2027-100(x+32)=3^3`

`=>2027-100(x+32)=27`

`=>100(x+32)=2027-27`

`=>100(x+32)=2000`

`=>x+32=2000:100`

`=>x+32=20`

`=>x=20-32`

`=>x=-12`

Các bạn giúp mk nha gấp lắm luôn đó nha🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗

= 81

a: \(16^x< 32^4\)

=>\(2^{4x}< 2^{20}\)

=>4x<20

=>\(x< 5\)

=>0<=x<5

=>\(x\in\left\{0;1;2;3;4\right\}\)

b: \(9< 3^x< 81\)

=>\(3^2< 3^x< 3^4\)

=>2<x<4

=>x=3

c: \(25< 5^x< 125\)

=>\(5^2< 5^x< 5^3\)

=>2<x<3

mà x là số tự nhiên

nên \(x\in\varnothing\)

\(27\cdot5^3\cdot3^3\cdot32^{-1}:125=3^3\cdot5^3\cdot3^3\cdot\dfrac{1}{32}:5^3=\dfrac{3^6}{32}=\dfrac{3^6}{2^5}\)

\(5^{x+1}=125\)

\(5^{x+1}=5^3\)

\(x+1=3\)

\(x=2\)

b, \(5^{2x-3}-2.5^2=5^2.3\)

    \(5^{2x-3}=5^2.\left(3+2\right)\)

    \(5^{2x-3}=5^3\)

    \(2x-3=3\)

     \(x=3\)

c, \(2^x=32\)

    \(2^x=2^5\)

    \(x=5\)

Chúc em học tốt.

a.1+3+5+7+...+2x+1=225

[(2x+1-1):2+1]x(2x+1+1):2=225

(x+1)x(2x+2):2=225

(x+1)x(x+1)=225

(x+1)²=225

(x+1)²=15²

x+1=15

x=14

_______________

b. 130-[5.(9-x)+43]=47

    5.(9-x)+43=83

  5.(9-x)=40

9-x=8

x=1

_______________

c.16^x<32⁴

2^4x<2²⁰

=>x∈{0;1;2;3;4}

a: =>(x+1)^2=225

=>x+1=15

=>x=14

b: =>[5*(9-x)+43]=130-47=83

=>5(9-x)=40

=>9-x=8

=>x=1

c: =>2^4x<2^20

=>4x<20

=>0<x<5