\(\frac{2^6\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)
giúp tui
Những câu hỏi liên quan
Bài 6 ; tính nhanh:
a, A =\(1993^{1^{2\times3\times4\times......\times1994}}\)
b, B =\(1994^{\left(225-1^2\right)\times\left(225-2^2\right).......\left(225-50^2\right)}\)
c, C =\(\frac{2^{10}\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)
a,\(A=1993^{1^{2\times3\times4\times...\times1994}}=1993^1=1993\)
b,\(B=1994^{\left(225-1^2\right)\times\left(225-2^2\right).....\left(225-50^2\right)}\)
\(=1994^{\left(225-1^2\right)\times\left(225-2^2\right)...\left(225-15^2\right)...\left(225-50^2\right)}\)
\(=1994^{\left(225-1^2\right)\times\left(225-2^2\right)...\left(225-225\right)...\left(225-50^2\right)}\)
\(=1994^{\left(225-1^2\right)\times\left(225-2^2\right)...\times0\times...\left(225-50^2\right)}\)
\(=1994^0=1\)
c, \(C=\frac{2^{10}\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)
\(=\frac{2^{10}\times3^6\times\left(1\times3^{25}+2^{30}\times1\right)}{2^{11}\times3^6\times\left(1\times3^{25}+2^{30}\times1\right)}\)
\(=\frac{2^{10}}{2^{11}}=\frac{1}{2}\)
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Bài 5 : Tính nhanh :
a, A =\(1993^{1^{2\times3\times4\times.....\times1994}}\)
b, B = \(1994^{\left(225-1^2\right)\times\left(225-2^2\right)\times....\times\left(225-50^2\right)}\)
c, C =\(\frac{2^{10}\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)
d, D = \(\left(1+2+2^2+2^3+.....+2^{2003}+2^{2004}\right)-2^{2005}\)
Ta có : D = (1 + 2 + 22 + 23 + ....... + 22004) - 22005
Đặt A = 1 + 2 + 22 + 23 + ....... + 22004
=> 2A = 2 + 22 + 23 + ....... + 22005
=> 2A - A = 22005 - 1
=> A = 22005 - 1
Thay vào ta có : D = (1 + 2 + 22 + 23 + ....... + 22004) - 22005
=> D = 22005 - 1 - 22005
=> D = -1
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cậu làm còn thiếu bước kìa Nguyễn Việt Hoàng
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\(\dfrac{4^{10}\times9^6+3^{12}\times8^5}{6^{13}\times4-2^{16}\times3^{12}}\)
\(\dfrac{2^4\times2^6}{\left(2^5\right)^2}-\dfrac{2^5\times15^3}{6^3\times10^2}\)
\(\dfrac{\left(-2\right)^{10}\times3^{31}+2^{40}\times\left(-3\right)^6}{\left(-2\right)^{11}\times\left(-3\right)^{31}+2^{41}\times3^6}\)
giải chi tiết giúp mình nhé
bài 1: Tính:
a, A= \(\frac{7\times4^5\times3^{11}+2^{13}\times9^5}{6^{10}+2^{12}\times3^{10}}\)
b, G= \(\frac{11\times3^{22}\times3^7-9^{15}}{\left(2-3^{14}\right)^2}\)
Bài 10: Tính:
a, A = \(\frac{7\times4^5\times3^{11}+2^{13}\times9^5}{6^{10}+2^{12}\times3^{10}}\)
b, G = \(\frac{11\times3^{22}\times3^7-9^{15}}{\left(2-3^{14}\right)^2}\)
\(A=\frac{7x\left(2x2\right)^5x3^{11}+2^{13}x\left(3x3\right)^5}{\left(2x3\right)^{10}+2^{12}x3^{10}}\)
\(A=\frac{7x2^{10}x3^{11}+2^{13}x3^{10}}{2^{10}x3^{10}+2^{12}x3^{10}}\)
tự làm tiếp
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Tính \(\frac{5\times\left(2^2\times3^2\right)^9-\left(2^2\right)^6-2\left(2^2\times3\right)^{14}\times3^4}{5\times2^{28}\times3^{18}-2^{29}\times3^{18}}\)
SGK Kết nối tri thức với cuộc sống - Trang 87
24 tháng 8 2023 lúc 11:44
Tính (theo mẫu).Mẫu: dfrac{2}{5}times3dfrac{2}{5}timesdfrac{3}{1}dfrac{2times3}{5times1}dfrac{6}{5}Ta có thể viết gọn như sau:dfrac{2}{5}times3dfrac{2times3}{5}dfrac{6}{5}a) dfrac{9}{11}times8 b) dfrac{4}{5}times1 c) dfrac{15}{8}times0
Đọc tiếp
Tính (theo mẫu).
Mẫu: \(\dfrac{2}{5}\times3=\dfrac{2}{5}\times\dfrac{3}{1}=\dfrac{2\times3}{5\times1}=\dfrac{6}{5}\) Ta có thể viết gọn như sau: \(\dfrac{2}{5}\times3=\dfrac{2\times3}{5}=\dfrac{6}{5}\) |
a) \(\dfrac{9}{11}\times8\) b) \(\dfrac{4}{5}\times1\) c) \(\dfrac{15}{8}\times0\)
a) \(\dfrac{9}{11}\times8=\dfrac{9\times8}{11}=\dfrac{72}{11}\)
b) \(\dfrac{4}{5}\times1=\dfrac{4\times1}{5}=\dfrac{4}{5}\)
c) \(\dfrac{15}{8}\times0=\dfrac{15\times0}{8}=\dfrac{0}{8}=0\)
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a: 9/11*8=(9*8)/11=72/11
b: 4/5*1=(4*1)/5=4/5
c: 15/8*0=(15*0)/8=0/8=0
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\(\frac{2^{12}\times3^{12}+6^9}{4^6\times3^{12}+6^{11}}\)
CẦN GẤP CÁC BẠN NHA!!!!!!!
\(\frac{2^{12}.3^{12}+6^9}{4^6.3^{12}+6^{11}}\)
= \(\frac{2^{12}.3^{12}+6^9}{2^{12}.3^{12}+6^{11}}\)
= \(\frac{6^{12}+6^9}{6^{12}+6^{11}}\)
= \(\frac{6^9\left(6^3+1\right)}{6^9\left(6^3+6^2\right)}\)
= \(\frac{217}{252}\)
= \(\frac{31}{36}\)
Hk tốt
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\(\frac{2^{12}\times3^{12}+6^9}{4^6\times3^{12}+6^{11}}=\frac{2^{12}\times3^{12}+6^9}{\left(2^2\right)^6\times3^{12}+6^{11}}\)
\(=\frac{2^{12}\times3^{12}+6^9}{2^{12}\times3^{12}+6^{11}}=\frac{6^{12}+6^9}{6^{12}+6^{11}}\)
\(=\frac{6^9\left(6^3+1\right)}{6^9\left(6^3+6^2\right)}=\frac{6^3+1}{6^3+6^2}\)
\(=1+\frac{1}{36}=\frac{37}{36}\)
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Tìm x :\(\dfrac{11\times3^{22}\times3^7-9^{15}}{\left(2\times3^{14}\right)^2}=6^x\)
\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=6^x\)
\(\Rightarrow\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}=6^x\)
\(\Leftrightarrow\dfrac{3^{29}\left(11-3\right)}{2^2.3^{28}}=6^x\)
\(\Leftrightarrow\dfrac{3.8}{4}=6^x\)
\(\Leftrightarrow6^1=6^x\)
\(\Leftrightarrow x=1\)
Vậy..
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