a)

(-4) . 32 . (-25) . 11

= (-4).(-25) . (32.11)

= 100 . 352

= 35200

b)

-86 . 46 - 46 . 27 + 46 . 23

= 46. ( -86 - 27 + 23)

= 46. (-90) = -4140

Chúc em học tốt!!!

a)

(-4) . 32 . (-25) . 11

= (-4).(-25) . (32.11)

= 100 . 352

= 35200

P/s tham khảo nha

b)

-86 . 46 - 46 . 27 + 46 . 23

= 46. ( -86 - 27 + 23)

= 46. (-90) = -4140

P/s tham khảo nha

a)5.(-8).2.(-3)

=[5.(-2)].[(-8).(-3)]

=-10.24

=-240

b)(45-135+72)-(45+72)

=45-135+72-45-72

=(45-45)+(72-72)-135

=0+0-135

=-135

c)3.(-5)².2+2.(-5)-20

=3.25.2+2(-5)-20

=75.2+(-10)-20

=150+(-30)

=120

d)86.(-46)+46.27-46.41

=86.(-1).46+46.27-46.41

=-86.46+46.27-46.41

=46(-86+27-41)

=46(-100)

-4600

e)34(15-10)-15(34-10)

=34.15-34.10-15.34+15.10

=(34.15-15.34)+(15.10-34.10)

=[34(15-15)]+[10(15-34)]

=34.0+10(-9)

=0+(-90)

=-90

69+114-94=89

=69+114-94

=89

ĐÂY MÀ LÀ TOÁN LỚP 1 Á ???/

hm....lúc mình học có mấy bài này đâu nhỉ? mà thôi pick đúng cho mình nhé!

(10+59)+(27+87)-(48+46)

=69+114-94

=277

a+46

=59+46

=105

27 : x =  62 - 59

27 : x =  3

x = 29 : 3

x = 9

X x 3 = 46 - 16

X x 3 = 30

X = 30 : 3

X = 10

\(a,\Leftrightarrow27:x=3\)

\(\Leftrightarrow x=27:3\)

\(\Leftrightarrow x=9\)

\(b,\Leftrightarrow x\times3=30\)

\(\Leftrightarrow x=10\)

27:x= 62-59

=>27:x=3

=>x=29:3

x=9

x*3+16=46

=>x*3 = 46 - 16

=>X*3 = 30

=>x = 30 : 3

=> x =10

Lời giải:

$[2(70-x)+72]:2=46$

$(140-2x+72):2=46$

$212-2x=46.2=92$

$2x=212-92=120$

$x=120:2=60$

ai tích mình mình tích lại cho

a) \(A=1-\dfrac{2002}{2003}\)

\(A=\dfrac{1}{2003}\)

b) \(B=\dfrac{179}{30}-\left(\dfrac{59}{30}-\dfrac{3}{5}\right)\)

\(B=\left(\dfrac{179}{30}-\dfrac{59}{30}\right)-\dfrac{3}{5}\)

\(B=\dfrac{120}{30}-\dfrac{3}{5}\)

\(B=4-\dfrac{3}{5}\)

\(B=\dfrac{17}{5}\)

c) \(C=\left(\dfrac{46}{5}-\dfrac{1}{11}\right).11\)

\(C=\dfrac{501}{55}.11\)

\(C=\dfrac{501}{5}\)

a) \(A=1-\dfrac{2002}{2003}=\dfrac{2003}{2003}-\dfrac{2002}{2003}=\dfrac{1}{2003}\)

b) \(B=\dfrac{179}{30}-\left(\dfrac{59}{30}-\dfrac{3}{5}\right)=\dfrac{179}{30}-\dfrac{59}{30}+\dfrac{3}{5}=4+\dfrac{3}{5}=\dfrac{23}{5}\)

c) \(C=\left(\dfrac{46}{5}-\dfrac{1}{11}\right)\cdot11=\dfrac{46}{5}\cdot11-\dfrac{1}{11}\cdot11=\dfrac{506}{5}-1=\dfrac{501}{5}\)

a)

\(A=1-\dfrac{2002}{2003}\\ \Rightarrow A=\dfrac{2003}{2003}-\dfrac{2002}{2003}\\ \Rightarrow A=\dfrac{1}{2003}\)

b)

\(B=\dfrac{179}{30}-\left(\dfrac{59}{30}-\dfrac{3}{5}\right)\\ \Rightarrow B=\dfrac{179}{30}-\dfrac{59}{30}+\dfrac{3}{5}\\ \Rightarrow B=\left(\dfrac{179}{30}-\dfrac{59}{30}\right)+\dfrac{3}{5}\\ \Rightarrow B=\dfrac{120}{30}+\dfrac{3}{5}\\ \Rightarrow B=4+\dfrac{3}{5}\\ \Rightarrow B=\dfrac{20}{5}+\dfrac{3}{5}\\ \Rightarrow B=\dfrac{23}{5}\)

c)

\(C=\left(\dfrac{46}{5}-\dfrac{1}{11}\right)\cdot11\\ C=\left(\dfrac{506}{55}-\dfrac{5}{55}\right)\cdot11\\ \Rightarrow C=\dfrac{501}{55}\cdot11\\ \Rightarrow C=\dfrac{501}{5}\)