Tính chia
-12x^5y^3 : 8x^3y^2
-6x^3y^3 : ( -3x^3y^4)
Tính
1(3x-5y).(3x+5y)
2(2x-3y).(4x^2+6xy+9y^2)
3(4x+3y).(16x^2-12xy+9y^2)
4)8x^3+12x^2+6x+1
5)27x^3+54x^2y+36xy^2+8y^3
(6x^5y^2 - 9x^4y^3 + 12x^3y^4) : 3x^3y^2
C=3x^2y-2xy^2+x^3y^3+3xy^2-2^2y-2x^3y^3
D=15x^2y^3+7y^2-8x^3y^2-12x^2+11x^3y^2-12x^2y^3
E=3x^5+1/3xy^4+3/4x^2y^3-1/2x^5y+2xy^4-x^2y^3
tìm bậc
3x^2y^2+12x^2y^3+6x^3y^4= ?
8x^3-27=?
x^2-3x+xy-3y=?
x^2+6x+9-y^2=?
giúp mình với mn ơi đang cần gấpppp
1)4x^5y^2-8x^4y^2+4x^3y^2 2)5x^4y^2-10x^3y^2+5x^2y^2 3)12x^2-12xy+3y^2 4)8x^3-8x^2y+2xy^2 5)20x^4y^2-20x^3y^3+5x^2y^4
1) \(4x^5y^2-8x^4y^2+4x^3y^2\)
\(=4x^3y^2\left(x^2-2x+1\right)\)
\(=4x^3y^2\left(x^2-2\cdot x\cdot1+1^2\right)\)
\(=4x^3y^2\left(x-1\right)^2\)
2) \(5x^4y^2-10x^3y^2+5x^2y^2\)
\(=5x^2y^2\left(x^2-2x+1\right)\)
\(=5x^2y^2\left(x^2-2\cdot x\cdot1+1^2\right)\)
\(=5x^2y^2\left(x-1\right)^2\)
3) \(12x^2-12xy+3y^2\)
\(=3\left(4x^2-4xy+y^2\right)\)
\(=3\left[\left(2x\right)^2-2\cdot2x\cdot y+y^2\right]\)
\(=3\left(2x-y\right)^2\)
4) \(8x^3-8x^2y+2xy^2\)
\(=2x\left(4x^2-4xy+y^2\right)\)
\(=2x\left[\left(2x\right)^2-2\cdot2x\cdot y+y^2\right]\)
\(=2x\left(2x-y\right)^2\)
5) \(20x^4y^2-20x^3y^3+5x^2y^4\)
\(=5x^2y^2\left(4x^2-4xy+y^2\right)\)
\(=5x^2y^2\left[\left(2x\right)^2-2\cdot2x\cdot y+y^2\right]\)
\(=5x^2y^2\left(2x-y\right)^2\)
1: 4x^5y^2-8x^4y^2+4x^3y^2
=4x^3y^2(x^2-2x+1)
=4x^3y^2(x-1)^2
2: \(=5x^2y^2\left(x^2-2x+1\right)=5x^2y^2\left(x-1\right)^2\)
3: \(=3\left(4x^2-4xy+y^2\right)=3\left(2x-y\right)^2\)
4: \(=2x\left(4x^2-4xy+y^2\right)=2x\left(2x-y\right)^2\)
5: \(=5x^2y^2\left(4x^2-4xy+y^2\right)=5x^2y^2\left(2x-y\right)^2\)
tìm bậc của các đa thức sau
a.C=\(3x^2y-2xy^2+x^3y^3+3xy^2-2x^3y^3\)
b.D=15\(x^2y^3+7y^2-8x^3y^2-12x^2+11x^3y^2-12x^2y^3\)
c.E=\(3x^5y+\frac{1}{3}xy^4+\frac{3}{4}x^2y^3-\frac{1}{2}x^5y+2xy^4-x^2y^3\)
Chia đa thức cho đơn thức
a, (8x^4 - 4x^3 +x^2) : 2x^2
b, 2x^4 - x^3 + 3x^2) : (-1/3x^2)
c, (-18x^3y^5 + 12x^2y^2 - 6xy^3) : 6xy
d,(3/4x^3y^6 + 6/5x^4y^5 - 9/10x^5y) : (-3/5x^3y)
giúp mìn với ạ
\(a.\left(8x^4-4x^3+x^2\right):2x^2=4x^2-2x+\frac{1}{2}\)
\(b.\left(2x^4-x^3+3x^2\right):\left(-\frac{1}{3x^2}\right)=-6x^6+3x^5-9x^4\)
\(c.\left(-18x^3y^5+12x^2y^2-6xy^3\right):6xy=-3x^2y^4+2xy-y^2\)
\(d.\left(\frac{3}{4x^3y^6}+\frac{6}{5x^4y^5}-\frac{9}{10x^5y}\right):-\frac{3}{5x^3y}=-\frac{5}{4y^5}-\frac{2}{xy^4}-\frac{3}{2x^2}\)
Tính giá trị biểu thức: N=8x^3-12x^2y+6xy^2 -y^3+12x^2=12xy+3y^2+6x-3y+11 với 2x-y=9
a) x^2+2xy+y^2-16
b) 3x^2+5x-3xy-5y
c) 4x^2-6x^3y-2x^2+8x
d) x^2-4-2xy+y^2
e) x^3-4x^2-12x+27
g) 3x^2-18x+27
h) x^2-y^2-z^2-2yz
k) 4x^2(x-6)+9y^2(6-x)
l)6xy+5x-5y-3x^2-3y^2
a) x^2+2xy+y^2-16
=(x+y)2-16
=(x+y-4)(x+y+4)
b) 3x^2+5x-3xy-5y
=(3x2-3xy)+(5x-5y)
=3x(x-y)+5(x-y)
=(x-y)(3x+5)
c) 4x^2-6x^3y-2x^2+8x
ko bik hoặc sai đề
d) x^2-4-2xy+y^2
=(x-y)2-4
=(x-y+2)(x-y-2)
e) x^3-4x^2-12x+27
=sai đề
g) 3x^2-18x+27
=3(x2-6x+9)
=3(x-3)2
h) x^2-y^2-z^2-2yz
=x2-(y2+z2+2yx)
=x2-(y+z)2
=(x-y-z)(x+y+z)
k) 4x^2(x-6)+9y^2(6-x)
=4x2(x-6)-9y2(x-6)
=(x-6)(4x2-9y2)
=(x-6)(2x-3y)(2x+3y)
l)6xy+5x-5y-3x^2-3y^2
=(5x-5y)+(-3x2+6xy-3y2)
=5(x-y)-3(x2-2xy+y2)
=5(x-y)-3(x-y)2
=(x-y)(5-3(x-y))
=(x-y)(5-3x+3y)