Cho mih hỏi 
Dấu " } " trong biểu thức ở chỗ nào vậy?

Cậu ơi  , cái đoạn trừ 89 í , cậu có ghi sai không ạ , tớ thấy nó cứ sai sai ở đâu í

\(5871:\left[928-\left(247-82.5\right)\right]\\ =5871:\left[928-\left(247-410\right)\right]\\ =5871:\left[928-\left(-163\right)\right]\\ =5871:1091\\ =\dfrac{5871}{1091}\)

5871/1091

5871:[928−(247−82.5)]

=5871:[928−(247−410)]

=5871:[928−(−163)]

=5871:1091

=\(\dfrac{5871}{1091}\)

\(=\dfrac{5871}{928-\left(247-410\right)}=\dfrac{5871}{928-247+410}\)

\(=\dfrac{5871}{1091}\)

\(5871:\left[928-\left(247-82\cdot5\right)\right]\)

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=\dfrac{5871}{1091}\)

=5871:(928+163)

=5871:1091

=5871/1091

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=\frac{5871}{1091}\)

tíc mình nha

247-410 sao chia được

5781 : [ 928 - ( 247 - 82 . 5 )

5781 : [ 928 - 164,5 ]

5781 : 763,5 =7,571709234

5871⁰ : [928 - (247 - 82).5] + 2175⁰

= 1 : (928 - 165.5) + 1

= 1 : (928 - 825) + 1

= 1 : (-103) + 1

= 102/103

ai giúp đi

\(=5871:\left[928-165\cdot5\right]\\ =5871:\left[928-825\right]=5871:103=57\)

\(=5871:\left[928-165.5\right]=5871:\left[928-825\right]=5871:103=57\)

a,=5871:[928-165.5]

   = 5871:[928-825]

   = 5871:103

   =  57

5871:{928-[(-82)+247].5}

=5871:{928-165.5}

=5871:{928-825}

=5871:103

=57

 5871:{928-[(-82)+247)].5}

=5871:{928-165}.5

=5871:763.5

=5871:3816

=???????

5871:{928-[(-82)+247].5}

= 5871:{928-165.5}

= 5871:{928-825}

= 5871:103

= 57