a: Đề sai rồi bạn

b: \(\dfrac{\left(1.16-x\right)\cdot5.25}{\left(10+\dfrac{5}{9}-7-\dfrac{1}{4}\right)\cdot\dfrac{36}{17}}=\dfrac{3}{4}\)

\(\Leftrightarrow21\left(1.16-x\right)=3\cdot\dfrac{36}{17}\cdot\left(3+\dfrac{5}{9}-\dfrac{1}{4}\right)\)

\(\Leftrightarrow21\left(1.16-x\right)=\dfrac{108}{17}\cdot\dfrac{108+20-9}{36}\)

\(\Leftrightarrow21\cdot\left(1.16-x\right)=21\)

=>1,16-x=1

hay x=0,16

a, Đề sai hả bạn ??

b, \(\dfrac{\left(1,16-x\right).5,25}{\left(10\dfrac{5}{9}-7\dfrac{1}{4}\right).2\dfrac{2}{17}}=75\%\)

\(\dfrac{\left(1,16-x\right).5,25}{\left(\dfrac{95}{9}-\dfrac{29}{4}\right).\dfrac{36}{17}}=\dfrac{75}{100}\)

\(\dfrac{\left(1,16-x\right).5,25}{\left(\dfrac{380}{36}-\dfrac{261}{36}\right).\dfrac{36}{17}}=\dfrac{3}{4}\)

\(\dfrac{\left(1,16-x\right).5,25}{\dfrac{119}{36}.\dfrac{36}{17}}=\dfrac{3}{4}\)

\(\dfrac{\left(1,16-x\right).5,25}{7}=\dfrac{3}{4}\)

=> \(\left[\left(1,16-x\right).5,25\right].4=3.7\)

\(\left[\left(1,16-x\right).5,25\right].4=21\)

( 1,16 - x ) . 5,25 = 21/4

1,16 - x = 21/4 : 5,25

1,16 - x = 1

x = 1,16 - 1

x = 0,16

Vậy x = 0,16

c, \(\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+...+\dfrac{1}{19.21}\right).420-\left[0,4.\left(7,5-2,5x\right)\right]:0,25=212\)

\(\dfrac{1}{2}.\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+...+\dfrac{2}{19.21}\right).420-\left[0,4.\left(7,5-2,5x\right)\right]:0,25=212\)

\(\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{21}\right).420-\left[0,4.\left(7,5-2,5x\right)\right]:0,25=212\)

\(\dfrac{1}{2}.\dfrac{20}{21}.420-\left[0,4.\left(7,5-2,5x\right)\right]:0,25=212\)

\(200-\left[0,4.\left(7,5-2,5x\right)\right]:0,25=212\)

\(0,4.\left(7,5-2,5x\right):0,25=200-212\)

\(0,4.\left(7,5-2,5x\right):0,25=-12\)

0,4 . ( 7,5 - 2,5x ) = -12 . 0,25

0,4 . ( 7,5 - 2,5x ) = -3

7,5 - 2,5x = -3 :0,4

7,5 - 2,5x = -7,5

2,5x = 7,5-(-7,5)

2,5x = 15

x = 6

Vậy x = 6

Vậy x = 51

7 . 5x : (9 - 6\(\dfrac{13}{21}\)) = 2\(\dfrac{13}{25}\)

7 . 5x : 2\(\dfrac{8}{21}\) = 2\(\dfrac{13}{25}\)

7 . 5x = 2\(\dfrac{13}{25}\) . 2\(\dfrac{8}{21}\)

7 . 5x = 6

5x = 6 : 7

5x = 6 . \(\dfrac{1}{7}\)

5x = \(\dfrac{6}{7}\)

x=4/5

\(\dfrac{21}{24}\cdot\dfrac{2}{11}:\dfrac{9}{8}=\dfrac{21}{24}\cdot\dfrac{2}{11}\cdot\dfrac{8}{9}=\dfrac{16}{99}\)

\(\dfrac{17}{9}\cdot\dfrac{5}{6}:\dfrac{12}{13}=\dfrac{17}{9}\cdot\dfrac{5}{6}\cdot\dfrac{13}{12}=\dfrac{1105}{648}\)

a)\(\dfrac{14}{99}\)

b)\(\dfrac{1105}{648}\)

\(\dfrac{16}{99};\dfrac{1105}{648}\)

a)

x^2-16/25=0

x^2-4^2/5^2=0

=>x-4/5=0

x=0+4/5

x=0/5

1

a)103/35

b)-3/13

lấy máy tính tính cho nhanh dùng cái lệnh solve đó

a) Ta có: \(\dfrac{2}{3}x-1=\dfrac{3}{2}\)

\(\Leftrightarrow x\cdot\dfrac{2}{3}=\dfrac{5}{2}\)

hay \(x=\dfrac{5}{2}:\dfrac{2}{3}=\dfrac{5}{2}\cdot\dfrac{3}{2}=\dfrac{15}{4}\)

b) Ta có: \(\left|5x-\dfrac{1}{2}\right|-\dfrac{2}{7}=25\%\)

\(\Leftrightarrow\left|5x-\dfrac{1}{2}\right|=\dfrac{1}{4}+\dfrac{2}{7}=\dfrac{15}{28}\)

\(\Leftrightarrow\left[{}\begin{matrix}5x-\dfrac{1}{2}=\dfrac{15}{28}\\5x-\dfrac{1}{2}=\dfrac{-15}{28}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}5x=\dfrac{29}{28}\\5x=\dfrac{-1}{28}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{29}{140}\\x=\dfrac{-1}{140}\end{matrix}\right.\)

c) Ta có: \(\dfrac{x-3}{4}=\dfrac{16}{x-3}\)

\(\Leftrightarrow\left(x-3\right)^2=64\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=8\\x-3=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-5\end{matrix}\right.\)

d) Ta có: \(\dfrac{-8}{13}+\dfrac{7}{17}+\dfrac{21}{31}\le x\le\dfrac{-9}{14}+4-\dfrac{5}{14}\)

\(\Leftrightarrow\dfrac{3246}{6851}\le x\le3\)

\(\Leftrightarrow x\in\left\{1;2;3\right\}\)

ko biết =))