a) x/7 = 6/21 b) -5/y = 20/28
Tìm các số nguyên x và y, biết:
a)\(\dfrac{x}{7}=\)\(\dfrac{6}{21}\) b)\(\dfrac{-5}{y}\)= \(\dfrac{20}{28}\)
c)\(\dfrac{-4}{8}=\)\(\dfrac{-7}{y}\)
Lời giải:
a. $\frac{x}{7}=\frac{6}{21}$
$x=\frac{6}{21}.7$
$x=2$
b.
$\frac{-5}{y}=\frac{20}{28}$
$y=-5:\frac{20}{28}$
$y=-7$
c.
$\frac{-4}{8}=\frac{-7}{y}$
$y=-7:\frac{-4}{8}$
$y=14$
a, \(\dfrac{x}{7}=\dfrac{6}{21}\Leftrightarrow\dfrac{3x}{21}=\dfrac{6}{21}\Rightarrow x=2\)
b, \(\dfrac{-5}{y}=\dfrac{20}{28}\Leftrightarrow\dfrac{20}{-4y}=\dfrac{20}{28}\Leftrightarrow y=-7\)
c, \(\dfrac{-4}{8}=-\dfrac{7}{y}\Rightarrow-4y=-56\Leftrightarrow y=14\)
a) Ta có: \(\dfrac{x}{7}=\dfrac{6}{21}\)
nên \(x=\dfrac{6\cdot7}{21}=\dfrac{42}{21}=2\)
b) Ta có: \(\dfrac{-5}{y}=\dfrac{20}{28}\)
nên \(y=\dfrac{-5\cdot28}{20}=\dfrac{-140}{20}=-7\)
c) Ta có: \(\dfrac{-4}{8}=\dfrac{-7}{y}\)
nên \(y=\dfrac{-7\cdot8}{-4}=\dfrac{-56}{-4}=14\)
tìm số nguyên x,y,z ;
a) 6/5 = 18/x
b) 3/4 = -21/x
c) x/4 = 21/28
d) -8/2x = 3/-9
e) -4/11 = x/22 = 40/z
f) - 3/4 = x/20 = 21 / y
g) -4/8 = x/-10 = -7/y = z/-24
h) x/4 = 9/x
\(a.\dfrac{6}{5}=\dfrac{18}{x}\Rightarrow x=\dfrac{18\cdot5}{6}=15\\ \text{Vậy}\text{ }x=15.\)
\(b.\dfrac{3}{4}=\dfrac{-21}{x}\Rightarrow x=\dfrac{-21\cdot4}{3}=28\\ \text{ }\text{ }\text{ }\text{ }\text{Vậy }x=28.\)
\(c.\dfrac{x}{4}=\dfrac{21}{28}\Rightarrow x=\dfrac{21\cdot4}{28}=3\\ \text{Vậy }x=3.\)
\(d.\dfrac{-8}{2x}=\dfrac{3}{-9}\Rightarrow x=\dfrac{-8\cdot\left(-9\right)}{3}:2=12\\ \text{Vậy }x=12.\)
\(e.\dfrac{-4}{11}=\dfrac{x}{22}=\dfrac{40}{z}\\ \Rightarrow x=\dfrac{-4\cdot22}{11}=-8\\ \Rightarrow z=\dfrac{22\cdot40}{-8}=-110\\ \text{Vậy }x=-8;z=-110.\)
\(f.\dfrac{-3}{4}=\dfrac{x}{20}=\dfrac{21}{y}\\ \Rightarrow x=\dfrac{-3\cdot20}{4}=-15\\ \Rightarrow y=\dfrac{21\cdot20}{-15}=-28\\ \text{Vậy }x=-15;y=-28.\)
\(g.\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\\ \Rightarrow x=\dfrac{-4\cdot\left(-10\right)}{8}=5\\ \Rightarrow y=\dfrac{-7\cdot\left(-10\right)}{5}=14\\ \Rightarrow z=\dfrac{-7\cdot\left(-24\right)}{14}=12\\ \text{Vậy }x=5;y=14;z=12.\)
\(h.\dfrac{x}{4}=\dfrac{9}{x}\\ \Rightarrow x\cdot x=9\cdot4\\ \Rightarrow x\cdot x=36\\ \Rightarrow x\cdot x=6\cdot6\\ \text{Vậy }\text{cả hai }x=6.\)
a) 7/-25+8/25 ; 4/5+4/-18 ; 7/21+9/-36
b) 12/20-2/5 ; 2/3-(-5/6) ; 6-3/20
c)2/21*(-7/3) ; 27/28*(-21) ; -15/7*(-14/25)
a) \(\dfrac{7}{-25}+\dfrac{8}{25}=\dfrac{-7}{25}+\dfrac{8}{25}=\dfrac{1}{25}\)
\(\dfrac{4}{5}+\dfrac{4}{-18}=\dfrac{4}{5+\left(-18\right)}=\dfrac{4}{-13}=\dfrac{-4}{13}\)
\(\dfrac{7}{21}+\dfrac{9}{-36}=\dfrac{1}{3}+\dfrac{1}{-4}=\dfrac{1}{3+\left(-4\right)}=\dfrac{1}{-1}=1\)
b) \(\dfrac{12}{20}-\dfrac{2}{5}=\dfrac{12}{20}+\left(\dfrac{-2}{5}\right)=\dfrac{3}{5}+\dfrac{-2}{5}=\dfrac{3+\left(-2\right)}{5}=\dfrac{1}{5}\)
\(\dfrac{2}{3}-\dfrac{-5}{6}=\dfrac{2}{3}+\dfrac{5}{6}=\dfrac{4}{6}+\dfrac{5}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)
\(6-\dfrac{3}{20}=6+\dfrac{-3}{20}=\dfrac{60}{60}+\dfrac{-9}{60}=\dfrac{51}{60}\)
c) \(\dfrac{2}{21}.\dfrac{-7}{3}=\dfrac{2.\left(-1\right)}{7.3}=\dfrac{-2}{21}\)
\(\dfrac{27}{28}.\left(-21\right)=\dfrac{27.\left(-21\right)}{28}=\dfrac{-567}{28}\)
\(\dfrac{-15}{7}.\dfrac{-14}{25}=\dfrac{-3.\left(-2\right)}{1.5}=\dfrac{6}{5}\)
Tìm x, y, z biết rằng
VD: x/10 = y/6 = z/21 và 5x + y - 2z = 28
Áp dụng tính chất dãy tỉ số bằng nhau
Ta có:
x/10 = y/6 = 7/21 = 5x + y - 2z/5 : 10 + 6 - 2 . 21 = 28/14=2
=> x/10 = 2 => x = 10 . 2 = 20
y / 6 = 2 =» 6 . 2 = 12
z / 21 =2 =» x = 21 . 2 = 42
Vậy x= 20 y=12 z=42
Làm hộ mình câu này :)
x/2 = y/3= z/4 và x + 2y - 3z =-20
\(\frac{X}{2}=\frac{Y}{3}=\frac{Z}{4}\)\(=\frac{X}{2}=\frac{2Y}{6}=\frac{3Z}{12}\)\(=\frac{X+2Y-3Z}{2+6-12}\)\(=5\)
\(=>X=2.5=10\)
\(=>y=3.5=15\)
\(=>z=4.5=20\)
vậy.....
gửi Trần hải mi:
6:
a) .... khi và chỉ khi x . 21 = 6.7 hay 21x = 42. Từ đó suy ra x 42 : 21 = 2
b) .... khi và chỉ khi ( - 5 ) . 28 = y .20 hay 20y = - 140. Từ đó suy ra y = ( - 140 ) : 20 = - 7. Vậy x = - 7
7:
a) 6
b) 20
c) -7
d) - 6
1 tim cac so nguyen x,y biet x/7=6/21 -5/y=20/28 1/2=x/12 x/8=-28/32 3/y=12/24 3/4=15/y 2 viet 3 phan so bang phan so -10/15
Tìm các số x và y biết
1) 4/x= y/21=28/49. 2) x/2=3/y. 3)42/54=7/x
4) 2/3 =y/15. 5)6/10 = 3/x =y/20
\(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}=\dfrac{28:7}{49:7}=\dfrac{4}{9}\\ Vậy:x=\dfrac{4.9}{4}=9\\ y=\dfrac{4.21}{9}=\dfrac{28}{3}\)
\(\dfrac{x}{2}=\dfrac{3}{y}\\ \Leftrightarrow x.y=2.3=6\\ Vậy:\left[{}\begin{matrix}\left(x;y\right)=\left(1;6\right)=\left(6;1\right)\\\left(x;y\right)=\left(2;3\right)=\left(3;2\right)\end{matrix}\right.\)
\(3,\\ \dfrac{42}{54}=\dfrac{42:6}{54:6}=\dfrac{7}{9}\\ \dfrac{42}{54}=\dfrac{7}{x}=\dfrac{7}{9}\\ Vậy:x=\dfrac{7.9}{7}=9\)
Tìm số nguyên x và y , biết :
a) \(\frac{x}{7}\) = \(\frac{6}{21}\)b) \(\frac{-5}{y}\)= \(\frac{20}{28}\)
Hoàng Thị Thanh Trúc
a,
\(\frac{x}{7}=\frac{6}{21}\Rightarrow x=\frac{6.7}{21}=2\)
b,
\(\frac{-5}{y}=\frac{20}{28}\Rightarrow y=\frac{\left(-5\right).28}{20}=-7\)
tìm x,y
\(\frac{x}{7}=\frac{6}{21}\)
\(\frac{-5}{y}=\frac{20}{28}\)
\(\frac{x}{7}=\frac{6}{21}\)
\(\Rightarrow x=\frac{7.6}{21}\)
\(\Rightarrow x=2\)
\(-\frac{5}{y}=\frac{20}{28}\)
\(\Rightarrow y=\frac{-5.28}{20}\)
\(\Rightarrow y=-7\)