1/2.x+3/5.(x-2)=3

1/2.x+3/5.x-3/5.2=3

(1/2+3/5).x-6/5=15/5

(5/10+6/10).x=15/5+6/5

11/10.x =21/5

         x = 21/5:11/10

         x = 21/5.10/11

         x= 42/11

vậy x=42/11

1/2 . x + 3/5 . ( x - 2 ) = 3 

1/2 . x + 3/5 . x - 3/5 . 2 = 3

( 1/2 + 3/5 ) . x - 6/5 = 15/5

( 5/10 + 6/10 ) . x = 15/5 + 6/5

11/10 . x = 21/5

           x = 21/5 : 11/10

           x = 21/5 . 10/11

          x = 42 / 11

Vậy x = 42/11

Đúng nha Chích Cute

\(\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

\(\frac{1}{2}x+\frac{3}{5}x-\frac{3}{5}\cdot2=3\)

\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)

\(\frac{11}{10}x-\frac{6}{5}=3\)

\(\frac{11}{10}x=3+\frac{6}{5}\)

\(\frac{11}{10}x=\frac{21}{5}\)

\(x=\frac{21}{5}:\frac{11}{10}\)

\(x=\frac{42}{11}\)

=1 nha

Em tách ra 1-2 bài/1 câu hỏi để mọi người hỗ trợ nhanh nhất nha!

1.

a)\(A=\sqrt{3}\left(2\sqrt{27}-6\sqrt{\dfrac{1}{3}}+\dfrac{3}{2}\sqrt{12}\right)\)

\(\Leftrightarrow A=\sqrt{3}\left(6\sqrt{3}-2\sqrt{3}+3\sqrt{3}\right)=\sqrt{3}\cdot7\sqrt{3}\)

\(\Leftrightarrow A=21\)

\(B=\dfrac{x+\sqrt{x}}{\sqrt{x}}+\dfrac{x-4}{\sqrt{x}+2}\left(x>0\right)\\ \Leftrightarrow B=\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{\sqrt{x}}+\dfrac{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}{\sqrt{x}+2}\\ \Leftrightarrow B=\sqrt{x}+1+\sqrt{x}-2=2\sqrt{x}-1\)

b) Để \(A=B\)

\(\Leftrightarrow2\sqrt{x}-1=21\\ \Leftrightarrow2\sqrt{x}=22\\ \Leftrightarrow\sqrt{x}=11\\ \Leftrightarrow x=121\)

3.

a)\(A=\left(\sqrt{5}-\sqrt{2}\right)^2+\sqrt{40}\)

\(\Leftrightarrow A=7-2\sqrt{10}+2\sqrt{10}\\ \Leftrightarrow A=7\)

\(B=\left(\dfrac{x-\sqrt{x}}{\sqrt{x}-1}-\dfrac{\sqrt{x}+1}{x+\sqrt{x}}\right):\dfrac{\sqrt{x}+1}{\sqrt{x}}\left(x>0;x\ne1\right)\\ \Leftrightarrow B=\left(\dfrac{\sqrt{x}\left(\sqrt{x}-1\right)}{\sqrt{x}-1}-\dfrac{\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}+1\right)}\right)\cdot\dfrac{\sqrt{x}}{\sqrt{x}+1}\\ \Leftrightarrow B=\left(\sqrt{x}-\dfrac{1}{\sqrt{x}}\right)\cdot\dfrac{\sqrt{x}}{\sqrt{x}+1}\\ \Leftrightarrow B=\dfrac{\sqrt{x}-1}{\sqrt{x}+1}\)

b) Để \(A=B\)

\(\dfrac{\sqrt{x}-1}{\sqrt{x}+1}=7\Leftrightarrow\sqrt{x}-1=7\sqrt{x}+7\\ \Leftrightarrow6\sqrt{x}=-8\\ \Leftrightarrow\sqrt{x}=-\dfrac{4}{3}\\ \Leftrightarrow x=\dfrac{16}{9}\)

4.

a)\(A=\left(2\sqrt{75}-5\sqrt{27}-\sqrt{192}+4\sqrt{48}\right):\sqrt{3}\)

\(\Leftrightarrow A=\left(10\sqrt{3}-15\sqrt{3}-8\sqrt{3}+16\sqrt{3}\right):\sqrt{3}\\ \Leftrightarrow A=10-15-8+16=3\)

\(P=\left(\dfrac{\sqrt{x}}{2+\sqrt{x}}+\dfrac{\sqrt{x}}{2-\sqrt{x}}\right):\dfrac{\sqrt{x}}{2+\sqrt{x}}\left(x>0;x\ne4\right)\\ \Leftrightarrow P=\dfrac{\sqrt{x}\left(2-\sqrt{x}\right)+\sqrt{x}\left(2+\sqrt{x}\right)}{\left(2+\sqrt{x}\right)\left(2-\sqrt{x}\right)}\cdot\dfrac{2+\sqrt{x}}{\sqrt{x}}\\ \Leftrightarrow P=\dfrac{2\sqrt{x}-x+2\sqrt{x}+x}{\sqrt{x}\left(2-\sqrt{x}\right)}=\dfrac{4}{2-\sqrt{x}}\)

b) Để \(A=P\)

\(\Leftrightarrow\dfrac{4}{2-\sqrt{x}}=3\\ \Leftrightarrow6-3\sqrt{x}=4\\ \Leftrightarrow3\sqrt{x}=2\\ \Leftrightarrow\sqrt{x}=\dfrac{2}{3}\\ \Leftrightarrow x=\dfrac{4}{9}\)

5.

a)\(A=\sqrt{8+2\sqrt{15}}+\sqrt{8-2\sqrt{15}}\)

\(\Leftrightarrow A=\sqrt{\left(\sqrt{3}+\sqrt{5}\right)^2}+\sqrt{\left(\sqrt{3}-\sqrt{5}\right)^2}\\ \Leftrightarrow A=\sqrt{3}+\sqrt{5}+\sqrt{3}-\sqrt{5}=2\sqrt{3}\)

\(B=\dfrac{1}{\sqrt{x}+2}+\dfrac{1}{2-\sqrt{x}}\left(x\ge0;x\ne4\right)\\ \Leftrightarrow B=\dfrac{2-\sqrt{x}+\sqrt{x}+2}{4-x}=\dfrac{4}{4-x}\)

b) Để \(A=B\Leftrightarrow\dfrac{4}{4-x}=2\sqrt{3}\)

\(\Leftrightarrow2\sqrt{3}\left(4-x\right)=4\\ \Leftrightarrow8\sqrt{3}-2\sqrt{3}x=4\\ \Leftrightarrow2\sqrt{3}x=8\sqrt{3}-4\\ \Leftrightarrow\sqrt{3}x=4\sqrt{3}-2\\ \Leftrightarrow x=\dfrac{4\sqrt{3}-2}{\sqrt{3}}=\dfrac{12-2\sqrt{3}}{3}\)

Tick nha

x:54+x:16=217

x:(54+16)=217

x:70=217

x   =217*70

x   =15190

x:[16=54] =217

x ; 70 =217

x =217 nhân 70 = 15190

x = 15190

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