3) \(-12+2x-9+x=0\\ -21+3x=0\\ 3x=21\\ x=7\)

4)
\(11+\left(15-x\right)=1\)
\(15-x=1-11\)
\(15-x=-10\)
\(x=15-\left(-10\right)\)
\(x=25\)

5) 
\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(x-9=-20\)
\(x=-20+9\)
\(x=-11\)
 

\(3.-12+\left(2x-9\right)+x=0.\)

\(\Leftrightarrow-12+2x-9+x=0.\Leftrightarrow3x=21.\Leftrightarrow x=7.\)

Vậy \(x=7.\)

\(4.11+\left(15-x\right)=1.\Leftrightarrow11+15-x=1.\Leftrightarrow26-x=1.\Leftrightarrow x=25.\)

Vậy \(x=25.\)

\(5.4-\left(27-3\right)=x-\left(13-4\right).\Leftrightarrow4-24=x-9.\Leftrightarrow-20=x-9.\Leftrightarrow x=-11.\)

Vậy \(x=-11.\)

\(6.8-\left(x-10\right)=23-\left(-4+12\right).\Leftrightarrow8-x+10=23-8.\Leftrightarrow18-x=15.\Leftrightarrow x=3.\)

Vậy \(x=3.\)

\(7.105-5\left(10-5x\right)=-20.\Leftrightarrow105-50+25x=-20.\Leftrightarrow25x=-75.\Leftrightarrow x=-3.\)

Vậy \(x=-3.\)

\(8.\left(x-1\right)\left(8-2x\right)\left(3x+123\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0.\\8-2x=0.\\3x+123=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.\\x=4.\\x=-41.\end{matrix}\right.\)

Vậy \(x\in\left\{1;4;-41\right\}.\)

\(9.\left(x^2-25\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left(x-5\right)\left(x+5\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0.\\x+5=0.\\x+10=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5.\\x=-5.\\x=-10.\end{matrix}\right.\)

Vậy \(x\in\left\{5;-5;-10\right\}.\)

\(10.x\left(x^2+5\right)=0.\Leftrightarrow x=0.\)

đặt 2x-15=t

=>t⁵=t³

=>t⁵-t³=0

=>t³(t²-1)=0

=>t³(t-1)(t+1)=0

=>t³=0;t-1=0 hoặc t+1=0

=>t=-1;0;1

=>2x=14;15;16

=>x=7;7,5;8

vậy x=7;7,5;8

Ta có : 

\(\left(2x-15\right)^3=\left(2x-15\right)^5\)

\(\Leftrightarrow\)\(\left(2x-15\right)^3=\left(2x-15\right)^3.\left(2x-15\right)^2\)

\(\Leftrightarrow\)\(\left(2x-15\right)^2=1\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}2x-15=1\\2x-15=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=16\\2x=14\end{cases}}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{16}{2}\\x=\frac{14}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8\\x=7\end{cases}}}\)

Vậy \(x=7\) hoặc \(x=8\)

Chúc bạn học tốt ~ 

a) \(3\left(x-1\right)^2\cdot3x\left(x-5\right)=0\)

\(\Rightarrow9x\left(x-1\right)^2\left(x-5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\\x-5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x=5\end{matrix}\right.\)

b) \(\left(x+3\right)^2-5x-15=0\)

\(\Rightarrow\left(x+3\right)^2-5\left(x+3\right)=0\)

\(\Rightarrow\left(x+3\right)\left(x+3-5\right)=0\)

\(\Rightarrow\left(x+3\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+3=0\\x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)

c) \(2x^5-4x^3+2x=0\)

\(\Rightarrow2x\left(x^4-2x^2+1\right)=0\)

\(\Rightarrow2x\left[\left(x^2\right)^2-2\cdot x^2\cdot1+1^2\right]=0\)

\(\Rightarrow2x\left(x^2-1\right)^2=0\)

\(\Rightarrow2x\left(x-1\right)^2\left(x+1\right)^2=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\)

\(\text{#}Toru\)

a) \(\left(2x-1\right)+\frac{3}{15}=\frac{3}{2}\)

\(\Rightarrow2x-1=\frac{3}{2}-\frac{3}{15}=\frac{13}{10}\)

\(\Rightarrow2x=\frac{13}{10}+1=\frac{23}{10}\)

\(\Rightarrow x=\frac{23}{20}\)

b) \(x+\frac{46}{15}=1,5\)

\(\Rightarrow x+\frac{46}{15}=\frac{3}{2}\)

\(\Rightarrow x=\frac{3}{2}-\frac{46}{15}\)

\(\Rightarrow x=\frac{-47}{30}\)

c) \(\left(-2x+1\right)+\frac{3}{15}=\frac{5}{3}\)

\(\Rightarrow-2x+1=\frac{5}{3}-\frac{3}{15}=\frac{22}{15}\)

\(\Rightarrow-2x=\frac{7}{15}\Rightarrow x=\frac{-7}{30}\)

a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow80x=480\Rightarrow x=6\)

b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)

\(\Rightarrow4x=0\Rightarrow x=0\)

c) \(\Rightarrow10x-16-12x+15=12x-16+11\)

\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)

- Mình có thể giúp bài 1 :)

 5^x +  5^ ( x + 2 ) = 650

5^x +  5^x . 5² = 650

 5^x .( 1 + 25 ) = 650

 5^x . 26 = 650 

5^x = 650 : 26

 5^x = 25

 5^x = 5² 

=> x = 2 

Vậy x = 2 

The Reflection Of Light~ Ủa đề  là 5^x-5^x+2= 650 sao ông lại đổi thành 5^x-5^(x+2) zậy

các bn oi dau / nay la gia tri tuyet doi day

a) 13 - ( 2x - 11 ) = -15

=>       2x - 11    = 13 - ( -15 )

=>       2x - 11    = 28

=>      2x           = 28 + 11

=>     2x            = 39

=>      x            = 39 : 2

=>      x            = 19,5

Mấy câu khác bn tự giải nha!Cũng tương tự như vậy thôi!

a/ \(13-\left|2x-11\right|=-15\)

\(\Leftrightarrow\left|2x-11\right|=28\)

\(\Leftrightarrow\orbr{\begin{cases}2x-11=28\\2x-11=-28\end{cases}}\) 

\(\Leftrightarrow\orbr{\begin{cases}x=19,5\\x=-8,5\end{cases}}\)

Vậy ...

b/ \(17-\left(13-2x\right)=x+11\)

\(\Leftrightarrow17-13+2x=x+11\)

\(\Leftrightarrow5+2x=x+11\)

\(\Leftrightarrow2x-x=11-5\)

\(\Leftrightarrow x=6\)

Vậy ,,,

b/ \(17-\left|3x-2\right|=7\)

\(\Leftrightarrow\left|3x-2\right|=10\)

\(\Leftrightarrow\orbr{\begin{cases}3x-2=10\\3x-2=-10\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}3x=12\\3x=-8\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-\frac{8}{3}\end{cases}}\)

Vậy ...

d/ \(\left|4x\right|=2x+2\)

\(\Leftrightarrow\orbr{\begin{cases}2x+2=4x\\2x+2=-4x\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-4x=2\\2x+4x=2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}-2x=2\\6x=2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-1\\x=\frac{1}{3}\end{cases}}\)