2(2.3)=
1, 4.3x-2 + 2.3x+1=4.34+2.37
2, 4.3x-1+2.3x+2=4.36+2.39
1:
\(\Leftrightarrow4\cdot3^x\cdot\dfrac{1}{9}+2\cdot3^x\cdot3=4\cdot3^4+2\cdot3^7\)
\(\Leftrightarrow3^x\cdot\left(\dfrac{4}{9}+6\right)=3^4\cdot\left(4+2\cdot3^3\right)\)
\(\Leftrightarrow3^x=729\)
hay x=6
2: \(\Leftrightarrow3^x\cdot4\cdot\dfrac{1}{3}+3^x\cdot2\cdot9=4\cdot3^6+2\cdot3^9\)
\(\Leftrightarrow3^x\cdot\dfrac{58}{3}=42282\)
=>3x=2187
hay x=7
4.3x-2+2.3x+1=4.34+2.37
b,4.3x-12.3x+2=4.36+2.39
tại vì nó ko có đề mà có đề gì mà dễ như ăn cháo dzậy
B=3^2016-2.3^2015-2.3^2014-......-2.3^2-2.3-1.2
Đứa nào ko biết cách làm đừng comment(trả lời)
đúng tao tick
1^2.2^2.3^2-2015/1.2.3+2^2.3^2.4^2-2015/2.3.4
12.22.32-\(\frac{2015}{1.2.3}\)+12.22.32.42-\(\frac{2015}{1.2.3.4}\)
=36 +576 - (\(\frac{2015}{1.2.3}\)+\(\frac{2015}{1.2.3.4}\))
= 612-\(\frac{10075}{24}\)
=\(\frac{4613}{24}\)
xin lỗi nhưng kq đâu giống vs mk rrrr
Cho S = 2.30 + 2.31 + 2.32 + .... + 2.32020. Tìm chữ số tận cùng
Giúp mk vs nha
\(\dfrac{5}{2^2.3^2}và\dfrac{-7}{2^2.3}\) \(\)tìm mẫu chung rồi so sánh
BCNN=36
\(\dfrac{5}{36}=\dfrac{5}{36}>0>-\dfrac{7}{12}\)
Tính : 5^2.3+2^2.{13+5[30/2.3-(3^3-30.2)]}
5.(2^2.3^2)^9.(2^2)^6-2.(2^2.3)^14.3^4/5.2^28.3^18-7.2^29.3^18
Tính M=5.(2^2.3^2)^9.(2^2)6-2.(2^2.3)^14.3^6/5.2^38.3^19-7.2^29.3^18
\(M=\dfrac{5\cdot2^{18}\cdot3^{18}\cdot2^{12}-2\cdot2^{28}\cdot3^{14}\cdot3^6}{5\cdot2^{38}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)
\(=\dfrac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}}=2\)
N=(5.(2^2.3^2)^9.(2^2)^6-2.(2^2.3)14.3^6)/5.2^28.3^19-7.2^29.3^18