BCNN=36
\(\dfrac{5}{36}=\dfrac{5}{36}>0>-\dfrac{7}{12}\)
\(\dfrac{-3}{5}và\dfrac{-2}{7}\) tìm mẫu chung rồi so sánh
cho A =\(\dfrac{3}{1^2.2^2}+\dfrac{5}{2^2.3^2}+\dfrac{7}{3^2.4^2}+...+\dfrac{19}{9^2.10^2}\) so sánh A với 1
So sánh N = \(\dfrac{2}{1.2}\)+\(\dfrac{2}{2.3}\)+\(\dfrac{2}{3.4}\)+...+\(\dfrac{2}{49.50}\) với 2
Bài 6: So sánh
a,\(\dfrac{1}{2}\)+\(\dfrac{1}{_{ }2^2}\)+\(\dfrac{1}{2_{ }^3}\)+...+\(\dfrac{1}{2^{2014}}\)và 1 b,\(\dfrac{10^{2018}+5}{10^{2018}-8}\)và \(\dfrac{10^{2019}+5}{10^{2019}-8}\)
c,\(\dfrac{1}{1.2.3}\)+\(\dfrac{1}{2.3.4}\)+\(\dfrac{1}{3.4.5}\)+...+\(\dfrac{1}{23.24.25}\)và\(\dfrac{1}{4}\)
C = \(\dfrac{3}{1^2.2^2}\) + \(\dfrac{5}{2^2.3^2}\)+\(\dfrac{7}{3^2.4^2}\) +...+ \(\dfrac{19}{9^2.10^2}\)
Bài 1: Rút gọn ( đưa vềphân sốtối giản, có mẫu dương)
a, \(\dfrac{36}{-42}\)
b,\(\dfrac{15.49}{-7.30}\)
c,\(\dfrac{\left(-7\right)^2.3^3}{3^2.\left(-7\right)^3}\)
Tìm x biết: (\(\dfrac{9}{2.3}\)+\(\dfrac{9}{3.4}\)+...+\(\dfrac{9}{199.200}\)).x=\(\dfrac{2}{5}\)
A=\(\dfrac{2}{1.2}\)+\(\dfrac{2}{2.3}\)+\(\dfrac{2}{3.4}\)+...+\(\dfrac{2}{99.100}\)
Giúp mình nhé😌
mình sắp thi rồi😫
a) \(\dfrac{2}{1.2.3}+\dfrac{2}{2.3.4}+\dfrac{2}{3.4.5}+...+\dfrac{2}{18.19.20}\)
b) \(\dfrac{4}{1.3.5}+\dfrac{4}{3.5.7}+\dfrac{4}{5.7.9}+...+\dfrac{4}{21.23.25}\)
c) \(\dfrac{3}{1.2}-\dfrac{5}{2.3}+\dfrac{7}{3.4}-\dfrac{9}{4.5}+...+\dfrac{39}{19.20}-\dfrac{41}{20.21}\)
d) \(\dfrac{8}{9}\cdot\dfrac{15}{16}\cdot\dfrac{24}{25}\cdot...\cdot\dfrac{99}{100}\cdot\dfrac{120}{121}\)
e) \(\left(1+\dfrac{7}{9}\right)\left(1+\dfrac{7}{20}\right)\left(1+\dfrac{7}{33}\right)\left(1+\dfrac{7}{48}\right)...\left(1+\dfrac{7}{180}\right)\)
Các bạn không nhất thiết phải làm hết, làm cho nó dễ hiểu được thì càng tốt để mk vận dụng
