\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{26}{25}+\dfrac{17}{25}\\ \left(x+\dfrac{1}{5}\right)^2=\dfrac{43}{25}\\ x+\dfrac{1}{5}=\dfrac{\sqrt{45}}{5}\\ x=\dfrac{\sqrt{45}}{5}-\dfrac{1}{5}\\ x=\dfrac{-1+\sqrt{43}}{5}\)

⎡⎢ ⎢⎣x+15=35x+15=−35⇔⎡⎢ ⎢⎣x=25x=−45

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\frac{3}{5}^2\)

\(\Rightarrow x^2=\frac{3}{5}^2-\frac{1}{5}^2=\frac{2}{5}^2\)

\(\Rightarrow x=\frac{2}{5}\)

Mk nhanh nhất k mk nka!!!^_^^_^^_^

giúp mình nhanh với nhé. Mình cảm ơn

2/5

2/5

mk biet nhung mk khong muon lam

nói cho mình đi

quá dễ luôn

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}}\)

\(\Rightarrow x\in\left\{-\frac{4}{5};\frac{2}{5}\right\}\)

(x+1/5)² + 17/25= 26/25

(x+1/5)^{2                = 26/25- 17/25}

(x+1/5)²                      = 9/25

(x+1/5)²                  = (3/5)²

=>  x+1/5               = 3/5

      x                      = 3/5-1/5

     x                       =    2/5

Pls cho mk nha

(x+1/5)^2=26/25-17/25

(x+1/5)^2=9/25

x+1/5=3/25

x=3/25-1/5

x=-2/25

(x+1/5)²+17/25=26/25

(x+1/5)²           =26/25-17/25

(x+1/5)²           =9/25

⇒(x+1/5)²=(3/5)² hoặc (x+1/5)²=(-3/5)²

    x+1/5=3/5 hoặc x+1/5=-3/5

       x=2/5 hoặc x=-4/5

Chúc bạn học tốt!

Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=\dfrac{-3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=\dfrac{-4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};\dfrac{-4}{5}\right\}\)

(x+1/5)²+17/25=26/25

(x+1/5)²           =26/25-17/25

(x+1/5)²           =9/25

⇒(x+1/5)²=(3/5)² hoặc (x+1/5)²=(-3/5)²

    x+1/5=3/5 hoặc x+1/5=-3/5

       x=2/5 hoặc x=-4/5

nhìn thấy duy nhất một chữ rối!

(x+1/5)^2 =26/25-17/25

<=> (x +1/5)^2 =(3/5)^2

<=> x+1/5=3/5

=> x= 2/5

a) 
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(x+\frac{1}{5}=\frac{3}{5}\)

\(x=\frac{3}{5}-\frac{1}{5}\)

\(x=\frac{2}{5}\)
b) 
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+4+\frac{x+329}{5}=0\)

\(\left(x+329\right). \left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+4+\frac{1}{5}\right)=0\)
\(\Rightarrow\left(x+329\right)=0\)
\(\Rightarrow x=-329\)