Question

\(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

Answer 1

\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Answer 2

\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{26}{25}+\dfrac{17}{25}\\ \left(x+\dfrac{1}{5}\right)^2=\dfrac{43}{25}\\ x+\dfrac{1}{5}=\dfrac{\sqrt{45}}{5}\\ x=\dfrac{\sqrt{45}}{5}-\dfrac{1}{5}\\ x=\dfrac{-1+\sqrt{43}}{5}\)

Answer 3

⎡⎢ ⎢⎣x+15=35x+15=−35⇔⎡⎢ ⎢⎣x=25x=−45