Rut gon bieu thuc

A=(x+1)\(\left(x^2+1\right)\left(x^4+1\right)...\left(x^{256}+1\right)+1\)

rut gon bieu thuc sau P=\(2\left(x+y\right)\left(x-y\right)-\left(x-y\right)^2+\left(x+y\right)^2-4y^2\)

\(\dfrac{\left(x+2\right)^2}{x}\times\left(1-\dfrac{x^2}{x+2}\right)-\dfrac{x^2+6x+4}{x}\)

rut gon bieu thuc tren

rut gon bieu thuc: \(\frac{\sqrt{\sqrt{\frac{x-1}{x+1}}+\sqrt{\frac{x+1}{x-1}}-2}\left(2x+\sqrt{x^2+1}\right)}{\sqrt{\left(x+1\right)^3}-\sqrt{\left(x-1\right)^2}}\)

Cho bieu thuc: \(Q=\left(\dfrac{x^2-2x}{2x^2+8}+\dfrac{2x^2}{x^2.\left(x-2\right)}\right).\left(\dfrac{x^2-x-2}{x^2}\right)\)

a, Rut gon bieu thuc Q

b, Tim gia tri ca x de Q co gia tri bang \(\dfrac{1}{4}\)

rut gon bieu thuc

\(Q=\left(x-y\right)^3+\left(y+x\right)^3+\left(y-x\right)^3-3xy\left(x+y\right)\)

\(P=12\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

rut gon bieu thuc

B=  \(\frac{x^3-y^3-z^3-3xyz}{\left(x+y\right)^2+\left(y-z\right)^2+\left(x+z\right)^2}\)

rut gon bieu thuc

A=\(\left(\dfrac{\sqrt{X}+2}{X-9}-\dfrac{\sqrt{X}-2}{X+6\sqrt{X}+9}\right)\left(\sqrt{X}\dfrac{9}{\sqrt{X}}\right)\)

rut gon cac bieu thuc

a) \(4x^2\left(5x^2-2x+3\right)\)

b)\(\left(x+2\right)\left(x-2\right)-\left(x+2\right)^2\)

c)\(\left(3x-5\right)\left(2x+11\right)-\left(2x+3\right)\left(3x+7\right)\)