Đáp án A

Độ lớn điện tích mỗi hạt bụi:

5 . 10 9 . 1 , 6 . 10 - 19 = 8 . 10 - 10 C .

Lực tương tác Cu lông

F = k q 1 q 2 r 2 = 9 . 10 9 8 . 10 - 10 2 0 , 02 2 = 1 , 44 . 10 - 5 N

a,186:(9:3)=186:3=62

b,152-29x5=152-145=7

c,224+476:7=224+68=292

d,128x3:8=48

e,(385-85):4=300:4=75

f,208:(4x2)=208:8=26

a 62

b 7

c 292

d 48

e 75

f 26

A

A

A

a. A = 2 / 3 . 5 + 2 / 5 . 7 + 2 / 7 . 9 + ... + 2 / 37 . 39

\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{37}-\frac{1}{39}=\frac{1}{3}-\frac{1}{39}\)

 \(=\frac{13}{39}-\frac{1}{39}=\frac{12}{39}\)

b. B = 4 / 5 . 8 + 4 / 8 . 11 + ... + 4 / 305 . 208 

\(=\frac{4}{3}.\left(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{305.308}\right)=\frac{4}{3}.\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{305}-\frac{1}{308}\right)\)

 \(=\frac{4}{3}.\left(\frac{1}{5}-\frac{1}{308}\right)=\frac{4}{3}.\frac{303}{1540}=\frac{101}{385}\)

2. a. \(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{37}-\frac{1}{39}\)

\(=\frac{1}{3}-\frac{1}{39}=\frac{4}{13}\)

b. \(B=\frac{4}{3}.\left(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{305.308}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{305}-\frac{1}{308}\right)\)

\(=\frac{4}{3}.\left(\frac{1}{5}-\frac{1}{308}\right)\)

\(=\frac{4}{3}.\frac{303}{1540}=\frac{101}{385}\)

a) \(A=\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+...+\frac{2}{37\cdot39}\)
\(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{37}-\frac{1}{39}\)
\(A=\frac{1}{3}-\frac{1}{39}\)
\(A=\frac{12}{39}\)

Đề bài sai ak ?

Mk nghĩ thế này mới đúng:

Tính nhanh:

1+2-3-4+5+6-7-8+...+206-207-208

Chúc bạn hok tốt!!!

a.

\(\left[3\times\left(-2\right)-\left(-8\right)\right]\times\left(-7\right)-\left(-2\right)\times\left(-5\right)=\left(-6+8\right)\times\left(-7\right)-10=2\times\left(-7\right)-10=-14-10=-24\)

b.

\(85\times\left(35-27\right)-35\times\left(85-27\right)=85\times35-85\times27-35\times85+35\times27=\left(85\times35-35\times85\right)-27\times\left(85-35\right)=-27\times50=-1350\)

c.

\(\left(20\times2^4-12\times2^3-48\times2^2\right)^2\div\left(-8\right)^2=\left(\frac{5\times4\times2^4-3\times4\times2^3-3\times16\times2^2}{-8}\right)^2=\left(\frac{5\times2^2\times2^4-3\times2^2\times2^3-3\times2^4\times2^2}{\left(-2\right)^3}\right)^2\)\(=\left(\frac{2^5\times\left(5\times2-3-3\times2\right)}{-\left(2^3\right)}\right)^2=\left(-2^2\right)^2=16\)

4³-7³:7²+20.2²