Bài 1: Tìm x, biết     

a )24-(36+5)=x                              b)14-21=(13-x)-(15+8)                         

    24-41=x                                      (13-x)-23=-7 

    x=-17                                          13-x=(-7)+23

Vậy x=-17                                        13-x=16

                                                        x=13-16

                                                        x=-3                 Vậy x=-3

Bài 2:Tìm x, biết

a)17-x=-25+(-16+9)                           b)3x-21=-19-(-2x)                

   17-x=-25+(-7)                                   3x-21=-19+2x

    17-x=-32                                         3x-2x=-19+21

     x=17-(-32)                                       x=4

     x=49                                                    Vậy x=4

Vậy x=49

Bài 1:

a. 24 - (36+5) = x

=> 24 - 41 = x

=> -17 = x

=> x = -17

b. 14 - 21 = (13 - x) - (15 + 8)

=> -7 = 13 - x - 23

=> -7 - 13 + 23 = -x

=> 3 = -x

=> x = -3

Bài 2:

a. 17 - x = -25 + (-16 + 9)

=> 17 - x = -25 + (-7)

=> 17 - x = -32

=> 17 + 32 = x 

=> x = 49

b. 3x - 21 = -19 - (-2x)

=> 3x - 21 = -19 + 2x

=> 3x - 2x = -19 + 21

=> x = 2

Bài1

a)24-(36+5)=x\(\Rightarrow\)x=24-41=-17

b)14-21=(13-x)-(15+8)\(\Rightarrow\)(13-x)-(15+8)=-7\(\Rightarrow\)13-x=-7+23=16\(\Rightarrow\)x=13-16=-3

Bài2

a)17-x=-25+(-16+9)\(\Rightarrow\)17-x=-25+-7\(\Rightarrow\)17-x=-32\(\Rightarrow\)x=17-(-32)=17+32=49

b)3x-21=-19-(-2x)\(\Rightarrow\)3x-(-2x)=-19-21\(\Rightarrow\)3x+2x=-40\(\Rightarrow\)5x=-40\(\Rightarrow\)x=-8

Giải:

a) \(5< 5^x < 625\)

\(\Leftrightarrow5< 5^x< 5^4\)

Vì \(5=5=5\)

Nên \(1< x< 4\)

\(\Leftrightarrow x\in\left\{2;3\right\}\)

Vậy ...

b) \(2^{x-1}=16\)

\(\Leftrightarrow2^{x-1}=2^4\)

Vì \(2=2\)

Nên \(x-1=4\)

\(\Leftrightarrow x=4+1=5\)

Vậy ...

c) \(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+6}\)

\(\Leftrightarrow\dfrac{\left(x-1\right)^{x+2}}{\left(x-1\right)^{x+2}}=\dfrac{\left(x-1\right)^{x+6}}{\left(x-1\right)^{x+2}}\)

\(\Leftrightarrow1=\left(x-1\right)^{x+4}\)

\(\Leftrightarrow x-1=1\)

\(\Leftrightarrow x=1+1=2\)

Vậy ...

-5.(x+1/5) -1/2.(x-2/3)=3/2x-5/6

-5x + (-1) -1/2x -1/3=3/2x-5/6

-5x-1/2x-3/2x=1+1/3-5/6

x.(-5-1/2-3/2)= 6/6+2/6+(-5/6)

x.(-10/2+(-1/2)+(-3/2))=3/6

x.6/2=1/2

x=1/2:6/2

x=1/6

Vậy x = 1/6

\(b)\) \(\left(2x-1\right)^{2012}=\left(2x-1\right)^{2010}\)

\(\Leftrightarrow\)\(\left(2x-1\right)^{2010}.\left(2x-1\right)^2=\left(2x-1\right)^{2010}\)

\(\Leftrightarrow\)\(\left(2x-1\right)^2=1\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}2x-1=1\\2x-1=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=2\\2x=0\end{cases}}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{2}{2}\\x=\frac{0}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}}\)

Vậy \(x=0\) hoặc \(x=1\)

Chúc bạn học tốt ~ 

a)|3x-2|=|3x+5|

x<-5/3 or x>=2/3

3x-2=3x+5=> loai

-5/3<=x<2/3

3x-2=-3x-5

6x=-3;x=-1/2(n)

a) thay \(x-y=\frac{3}{10}\)vào \(y\left(x-y\right)=\frac{-3}{50}\)ta có\(\frac{3}{10}y=\frac{-3}{50}\)=>\(y=\frac{-3}{50}:\frac{3}{10}=\frac{-1}{5}\)=>\(x-y=\frac{3}{10}\Rightarrow x=\frac{3}{10}+\frac{-1}{5}=\frac{1}{10}\)

hôm sau mik giải tip cho

a: =>11(x-3)=6(x-5)

=>11x-33=6x-30

=>5x=3

=>x=3/5

b: =>(4/3-1/4x-5/12)-2x=8/5*5/3=8/3

=>-9/4x+11/12=8/3

=>-9/4x=32/12-11/12=21/12=7/4

=>x=-7/9

c: =>1/2x-1/3-2/3x-1=x

=>-1/6x-4/3=x

=>-7/6x=4/3

=>x=-4/3:7/6=-4/3*6/7=-24/21=-8/7

d: =>1-2x-3x+1=7/2

=>-5x=3/2

=>x=-3/10

a ) \(3x\left(x-1\right)-x\left(3x-2\right)=5\)

\(\Leftrightarrow3x^2-3x-3x^2+2x=5\)

\(\Leftrightarrow-x=5\)

\(\Leftrightarrow x=-5\)

Vậy phương trình có nghiệm x = - 5 .

a, \(3x\left(x-1\right)-x\left(3x-2\right)=5\)

\(\Rightarrow3x^2-3x-\left(3x^2-2x\right)=5\)

\(\Rightarrow3x^2-3x-3x^2+2x=5\)

\(\Rightarrow5x=5\Rightarrow x=1\)

Câu b,c làm tương tự! Cứ tách ra là làm được à!

b ) \(8x\left(2x+1\right)-4x\left(2x-3\right)=-40\)

\(\Leftrightarrow16x^2+8x-8x^2+12x=-40\)

\(\Leftrightarrow20x=-40\)

\(\Leftrightarrow x=-2\)

Vậy phương trình có nghiệm x = - 2