Tìm x
x+7=135-(135 +89)
Tìm x ,biết: x+7=135-(135+89)
x+7=135-(135+89)
=>x+7=135-135-89
=>x+7=0-89=-89
=>x=-89-7
=>x=-96
x + 7 = 135 - 135 - 89
x + 7 = 0 -89
x + 7 = -89
x= -89 - 7
x= -96
bài1: tính nhanh
a, 89 + ( -36 ) + ( -8 ) + 29 + 15 + ( -34 )
b, -195 . 56 -43 . 195 - 195
c, 135 . ( -12 + 147 ) - 147 . ( 135 - 12 )
bài 2 : tìm x
a, 3-(17-x) = -12
b, -26-(x-7)= 0
c, /x+3/-7=13
d, /x-7/+15=23
e, (x+2)(x+3)=0
g, (x-1)( x^2+1)=0
b) -26 - ( x - 7 ) = 0
x - 7 = -26 - 0
x - 7 = -26
x = -26 + 7
x = -19
Bài 2 :
a) 3 - ( 17 - x ) = -12
( 17 - x ) = 3 - ( -12 )
( 17 - x ) = 15
x = 17 - 15
x = 2
b) -26 - ( x - 7)=0
x - 7 = -26 -0
x - 7 = -26
x = -26 + 7
x = -19
6< 89 -(73- X)=20
7<135 -5(X + 4)=35
8< 198-( X +4)=120
9< 420+ 654 = ( X +175 ) : 5+30
Tìm X
a. X x 7 = 4907
b. X : 4 = 135
a. X x 7 = 4907
X = 4907 : 7
X = 701
b. X : 4 = 135
X = 135 x 4
X = 540
1. tìm x
2x -3 = x + 1/2
2. tính bằng hai cách
A = ( 2008 - 2/135 +1/50) - ( 1 - 7/135 +4/50) - ( 5+ 5/135 +3/50)
cần gấp nha
Mk giải câu 1 nha
1) 2x - 3 = x + 1/2
➡️2x - x = 1/2 + 3
➡️x = 7/2
Hok tốt~
\(\dfrac{3}{x-7}=\dfrac{27}{135}\)
Tìm x
\(\dfrac{3}{x-7}=\dfrac{27}{135}\)
\(27\times\left(x-7\right)=3\times135\)
\(27\times x-189=405\)
\(27\times x=405+189\)
\(27\times x=594\)
\(x=594\div27\)
\(x=22\)
3/(x - 7) = 27/135
3 × 135 = (x - 7) × 27
(x - 7) × 27 = 405
x - 7 = 405 : 27
x - 7 = 15
x = 15 + 7
x = 22
@kiều vũ linh theo đề thì ta phải có:
\(3\cdot135=27\cdot\left(x-7\right)\)
Tìm x
3/x-7 = 27/135
3/x-7 = 27/135
3/x-7 = 3/15
x - 7 = 15
x = 15 + 7
x = 22
135 91 - 135 89 và 135 100 - 135 99
13591 - 13589 = 13589 x ( 1352 - 1 )
135100 - 13599 = 13599 x ( 135 - 1 ) = 13599 x 134 = 13589 x 13510 x 134 = 13589 x ( 13510 x 134 )
Có : 1352 - 1 < 13510 x 134
=> 13589 x ( 1352 - 1 ) < 13589 x ( 13510 x 134 )
=> 13591 - 13589 < 135100 - 13599
Ta có:
\(135^{91}-135^{89}=135^{89}\times\left(135^2-1\right)\)
\(135^{100}-135^{99}=135^{99}\times\left(135-1\right)=135^{99}\times134=135^{89}\times134=135^{89}\times\left(135^{10}\times34\right)\)
Có: \(135^2-1< 135^{10}\times134\)
\(\Rightarrow135^{89}\times\left(135^2-1\right)< 135^{89}\times\left(135^{10}\times134\right)\)
\(\Rightarrow135^{91}-135^{89}< 135^{100}-135^{99}\)
Vậy \(135^{91}-135^{89}< 135^{100}-135^{99}\)
Tìm x biết : x+ 135/25 = 116/15
a) x= 9/5
b) x= 7/5
c) x= 7/3
d) x= 11/3