Given the equation (x - m)(m - 1) + (x - 1)(m + 1) = -2m. Find all values of m such that this equation has no solution. Answer: m = ...........
Những câu hỏi liên quan
Given the equation (x - m)(m - 1) + (x - 1)(m + 1) = -2m.
Find all values of m such that this equation has no solution.
Answer: m = ...........
mọi người giúp minh nhé mình đang cần gấp Thanks trc
find the value of b and c for a quadratic function f(x) = x2+bx+c such that the solution of the equation f(x)=0 are \(\sqrt{3},-\sqrt{3}\)
Find the value of m such that x^4– mx^2 + 6 is divisible by x^2 – 1. Answer: m =
x4 - mx2 + 9 = (x2 -1)2
vây m =6 thì x4 -6x2 +9 chia hết cho x2 - 1
( ngâniq106)
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A solution to the equation (x+a)(x+b)(x+c)+5=0 is x=1 where a,b,c are differents integers Find the value of a+b+c
Thay x=1 vào pt, ta có: \(\left(a+1\right)\left(b+1\right)\left(c+1\right)=-5\left(1\right)\)
vì vai trò của a,b,c là như nhau, giả sử:\(a>b>c\Rightarrow a+1>b+1>c+1\left(2\right)\)
vì a,b,c là số nguyên nên a+1,b+1,c+1 cũng là số nguyên (3)
từ (1),(2),(3)\(\Rightarrow\hept{\begin{cases}a+1=5\\b+1=1\\c+1=-1\end{cases}\Leftrightarrow\hept{\begin{cases}a=4\\b=0\\c=-2\end{cases}}}\)
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1) ABC is a triangle where M is the midpoint of segment BC.
MD and ME are two bisectors of triangles AMB and AMC respectively.
If AM m; BC a . Then DE ???
2)dfrac{1}{left(x+29right)^2}+dfrac{1}{left(x+30right)^2}dfrac{5}{4}
What is the product of all real solutions to the equation above?
3) The sum of all possible natural numbers n such that
n^2+n+1589 is a perfect square is.....
4) Given that x is a positive integer such that x and x+99 are perfect squares
The sum of integer x is ....
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1) ABC is a triangle where M is the midpoint of segment BC.
MD and ME are two bisectors of triangles AMB and AMC respectively.
If AM= m; BC = a . Then DE = ???
2)\(\dfrac{1}{\left(x+29\right)^2}+\dfrac{1}{\left(x+30\right)^2}=\dfrac{5}{4}\)
What is the product of all real solutions to the equation above?
3) The sum of all possible natural numbers n such that
\(n^2+n+1589\) is a perfect square is.....
4) Given that x is a positive integer such that x and x+99 are perfect squares
The sum of integer x is ...
5)The operation @ on two numbers produces a number equal to their sum minus 2. The value of
(...((1@2)@3....@2017)
6) Given f(x)=\(\dfrac{x^2}{2x-2x^2-1}\)
=> \(f\left(\dfrac{1}{2016}\right)+f\left(\dfrac{2}{2016}\right)+f\left(\dfrac{3}{2016}\right)+...+f\left(\dfrac{2016}{2016}\right)\)
Các bn giúp mk vs >>> tks nha!!!
?????????????????????????????????????????????? Are you learning English or Math? I'm sure you are're mistake of English
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Find the integer solution of the equation \(x^2+xy+y^2=x^2y^2\)
x2+xy+y2=x2y2
=> x2+2xy+y2=x2y2-xy
=> (x+y)2=xy(xy+1)
Vi (x+y)2 chinh phuong , nen xy(xy+1) cung chinh phuong
Vay xy=xy+1 hoac xy=0
TH1 xy=xy+1 => 0=1 ( vo ly)
TH2 xy=0 => xy(xy+1)=0 => x+y=0 => x=y=0
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Given the equation \(\frac{3}{x-3}\)- \(\frac{5}{x-5}\) = \(\frac{4}{x-4}\)- \(\frac{6}{x-6}\). The average (arithmetic mean ) of all roots of this equation is.....
\(x\ne\left\{3;4;5;6\right\}\)
\(\frac{3}{x-3}-\frac{5}{x-5}=\frac{4}{x-4}-\frac{6}{x-6}\)
\(\Leftrightarrow\frac{3}{x-3}+1-\frac{5}{x-5}-1=\frac{4}{x-4}+1-\frac{6}{x-6}+1\)
\(\Leftrightarrow\frac{x}{x-3}-\frac{x}{x-5}=\frac{x}{x-4}-\frac{x}{x-6}\)
\(\Leftrightarrow x\left(\frac{1}{x-3}+\frac{1}{x-6}-\frac{1}{x-4}-\frac{1}{x-5}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\\frac{1}{x-3}+\frac{1}{x-6}=\frac{1}{x-4}+\frac{1}{x-5}\left(1\right)\end{matrix}\right.\)
\(\left(1\right)\Leftrightarrow\frac{2x-9}{\left(x-3\right)\left(x-6\right)}=\frac{2x-9}{\left(x-4\right)\left(x-5\right)}\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-9=0\\\left(x-3\right)\left(x-6\right)=\left(x-4\right)\left(x-5\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{9}{2}\\18=20\left(l\right)\end{matrix}\right.\)
\(\Rightarrow\overline{x}=\frac{\frac{9}{2}+0}{2}=\frac{9}{4}\)
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Find all pairs of positive integers (x;y) satisfy the equation: 1!+2!+3!+.......x!=y2
Bài thi số 3
19:25
Câu 1:
A man drove a car from A to B at speed 60km/h. After arriving B, he took a rest for 30 minutes then turned back to A at speed 40km/h. Known that he started from A at 7:00 am and he reached A again at 3:15pm on the same day. The distance between A and B is km.
Câu 2:
The minimum of the expression is
Câu 3:
Given that is a positive integer such that and are perfect squares.
The sum of such integers is
Câu 4:
Given two triangles and...
Đọc tiếp
Bài thi số 3
A man drove a car from A to B at speed 60km/h. After arriving B, he took a rest for 30 minutes then turned back to A at speed 40km/h. Known that he started from A at 7:00 am and he reached A again at 3:15pm on the same day. The distance between A and B is km. Câu 2:
The minimum of the expression(x+2)(x+3)(x+6)$)
is
Câu 3:
Given that
is a positive integer such that and 
are perfect squares.
The sum of such integers is
Câu 4:
Given two triangles
and 
. Known that 
, 
and 
.
If
then 
Câu 5:
How many real numbers are there such that 
?
Answer: There are numbers.
Câu 6:
The operation
on two numbers produces a number equal to their sum minus 2.The value of @3\)...@2017\)$)
is
Câu 7:
ABC is a triangle. AM is the bisector of angle CAB. Given that AM = 4cm, AB = 6m and AC = 12cm.Then the measurement of angle BAC is degrees. Câu 8:
In the equation above, where 
is a constant.The greatest possible value of such that the equation has at least one solution is
Câu 9:
and 
are positive integers such that =n^2+1$)
, where 
is a prime number.
The number of pairs$)
is
Câu 10:
Given that=\frac{x^2}{2x-2x^2-1}$)
.
Calculate:
+f\(\frac{2}{2016}\)+f\(\frac{3}{2016}\)+...+f\(\frac{2015}{2016}\)+f\(\frac{2016}{2016}\)$)
=
(Input the answer as a decimal in its simplest form) Nộp bài
19:25 Câu 1:
A man drove a car from A to B at speed 60km/h. After arriving B, he took a rest for 30 minutes then turned back to A at speed 40km/h. Known that he started from A at 7:00 am and he reached A again at 3:15pm on the same day. The distance between A and B is km. Câu 2:
The minimum of the expression
Given that
The sum of such integers
Given two triangles
If
How many real numbers
Answer: There are numbers
The operation
ABC is a triangle. AM is the bisector of angle CAB. Given that AM = 4cm, AB = 6m and AC = 12cm.Then the measurement of angle BAC is degrees. Câu 8:
The number of pairs
Given that
Calculate:
(Input the answer as a decimal in its simplest form) Nộp bài
câu 7 mk bấm nhầm đáp án là 120
qua B kẻ đường thẳng song song với AM cắt AC ở N.
vì AM là phân giác góc BAC nên có :
\(\dfrac{AC}{AB}=\dfrac{CM}{BM}=\dfrac{12}{6}=2\) suy ra \(\dfrac{CM}{BC}=\dfrac{CM}{CM+BM}=\dfrac{12}{12+6}=\dfrac{2}{3}\)
vì AM song song với BN nên có :
1,\(\dfrac{CA}{AN}=\dfrac{CM}{BM}=\dfrac{12}{AN}=2\) suy ra AN=6
2,\(\dfrac{AM}{BN}=\dfrac{CM}{BC}=\dfrac{2}{3}=\dfrac{4}{BN}\)suy ra BN=6
vì AB=6 nên tam giác ABN đều
suy ra \(\widehat{NAB}\)=\(60^0\)
mà \(\widehat{NAB}+\widehat{BAC}=\)\(180^0\)
nên \(\widehat{BAC}=\)\(120^0\)
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Câu1 : 186
Câu2 :-36
Câu3 : 19
Câu4 : 20
Câu5 : 0
Câu6 : 2017
câu7 : 110
Câu8 : 2
Câu9 : 2
Cau10 : 1
Mình lm được có 80 thui ko bt sai chỗ nào.
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