x2+xy+y2=x2y2
=> x2+2xy+y2=x2y2-xy
=> (x+y)2=xy(xy+1)
Vi (x+y)2 chinh phuong , nen xy(xy+1) cung chinh phuong
Vay xy=xy+1 hoac xy=0
TH1 xy=xy+1 => 0=1 ( vo ly)
TH2 xy=0 => xy(xy+1)=0 => x+y=0 => x=y=0
x2+xy+y2=x2y2
=> x2+2xy+y2=x2y2-xy
=> (x+y)2=xy(xy+1)
Vi (x+y)2 chinh phuong , nen xy(xy+1) cung chinh phuong
Vay xy=xy+1 hoac xy=0
TH1 xy=xy+1 => 0=1 ( vo ly)
TH2 xy=0 => xy(xy+1)=0 => x+y=0 => x=y=0
Given the equation (x - m)(m - 1) + (x - 1)(m + 1) = -2m.
Find all values of m such that this equation has no solution.
Answer: m = ...........
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Answer : the smallest positive integer k is ......
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k/13= 11Rx
K=