\(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)

\(=10101.\dfrac{5}{111111}+10101.\dfrac{5}{222222}-10101.\dfrac{4}{3.7.11.13.37}\)

\(=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}\)

\(=\dfrac{7}{22}\)

b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)

\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)

\(=5\)

c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)

\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)

\(I=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3\cdot7\cdot11\cdot13\cdot37}\right)\)

\(=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)

\(=10101\cdot\dfrac{1}{31746}\)

\(=7\cdot\dfrac{1}{22}\)

\(=\dfrac{7}{22}\)

\(I=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)

\(I=10101.\left(\dfrac{5}{111111}+\dfrac{1}{2}.\dfrac{5}{111111}-\dfrac{5}{111111}.\dfrac{4}{5}\right)\)

\(I=10101.\dfrac{5}{111111}.\left(1+\dfrac{1}{2}-\dfrac{4}{5}\right)\)

\(I=\dfrac{5}{11}.\dfrac{7}{10}=\dfrac{7}{22}\)

Chúc bạn học tốt!!!

\(I=10101\left(\dfrac{5}{111111}+\dfrac{5}{222222}+\dfrac{4}{3.7.11.13.37}\right)\)

\(I=10101\left(\dfrac{10}{222222}+\dfrac{5}{222222}+\dfrac{8}{222222}\right)\)

\(I=10101.\dfrac{1}{10582}=\dfrac{21}{22}\)

\(M=\dfrac{120-\dfrac{1}{2}.40.5.\dfrac{1}{5}.20.\dfrac{1}{4}-20}{1+5+....+41}\\ =\dfrac{120-20.5-20}{1+5+...+41}\\ =\dfrac{0}{1+5+...+41}\\ =0\)

\(N=10101\left(\dfrac{6}{3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}-\dfrac{7}{3.7.11.13.37}\right)\\ =10101\left(-\dfrac{2}{2.3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}\right)\\ =3.7.13.37\left(\dfrac{4}{2.3.7.11.13.37}\right)=\dfrac{4}{2.11}=\dfrac{2}{11}\)

\(C=10101.\left(\frac{5}{111111}+\frac{5}{222222}+\frac{4}{3.7.11.13.37}\right)\)

\(C=10101.\frac{23}{222222}\)

\(C=\frac{23}{22}.\)