a)88-3(7+x)=64                                  

=>3(7+x)=88-64

=>3(7+x)=24

=>7+x=24:3

=>7+x=8

=>x=8-7=1

tick nha

1. (7.x-15):3=2                               2. 12.(x+37)=504                                  3. 85-3.(7+x)=64

    7.x-15=2.3                                          x+37=504:12                                  3.(7+x)=85-64 

    7.x-15=6                                             x+37=42                                         3.(7+x)=21

    7.x=6+15                                            x=42-37                                           7+x=21:3

    7.x=21                                                x=5                                                 7+x=7

       x=21:7                                                                                                    x=7-7

       x=3                                                                                                        x=0

1. (7.x-15):3 = 2

(7.x-15)=2.3

(7.x-15)=6

7x=15+6

7x=21

x=21:7

x=3

2.12.(x+37=504

x+37=504:12

x+37=42

x = 42-37

x=5

3. 85-3.(7+x)=64

3.(7+x)=85-64

3.(7+x)=21

7+x=21:3

7+x=7

x=7-7

x=0

(7x-15):3 = 2

7x-15 = 2 x 3 =6

7x = 6+15=21

7x = 21:7=3

12(x+37)=504

x+37= 504 : 12 =42

x = 42-37

x = 5

85-3(7+x)=64

3(7+x) = 85-64

3(7+x) = 21

7+x = 21:3

7+x = 7

x = 0

a: \(4x^3+12=120\)

=>\(4x^3=108\)

=>\(x^3=27=3^3\)

=>x=3

b: \(\left(x-4\right)^2=64\)

=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)

c: (x+1)^3-2=5^2

=>\(\left(x+1\right)^3=25+2=27\)

=>x+1=3

=>x=2

d: 136-(x+5)^2=100

=>(x+5)^2=36

=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)

e: \(4^x=16\)

=>\(4^x=4^2\)

=>x=2

f: \(7^x\cdot3-147=0\)

=>\(3\cdot7^x=147\)

=>\(7^x=49\)

=>x=2

g: \(2^{x+3}-15=17\)

=>\(2^{x+3}=32\)

=>x+3=5

=>x=2

h: \(5^{2x-4}\cdot4=10^2\)

=>\(5^{2x-4}=\dfrac{100}{4}=25\)

=>2x-4=2

=>2x=6

=>x=3

i: (32-4x)(7-x)=0

=>(4x-32)(x-7)=0

=>4(x-8)*(x-7)=0

=>(x-8)(x-7)=0

=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)

k: (8-x)(10-2x)=0

=>(x-8)(x-5)=0

=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)

m: \(3^x+3^{x+1}=108\)

=>\(3^x+3^x\cdot3=108\)

=>\(4\cdot3^x=108\)

=>\(3^x=27\)

=>x=3

n: \(5^{x+2}+5^{x+1}=750\)

=>\(5^x\cdot25+5^x\cdot5=750\)

=>\(5^x\cdot30=750\)

=>\(5^x=25\)

=>x=2

1) 3x = 45 + 15 = 60

x = 60 : 3 = 20

2) 5x = 50 - 35 = 15

x = 15 : 5 = 3

3) (2x - 5) + 17 = 6

2x - 5 = 6 - 17

2x - 5 = -11

2x = -11 + 5

2x = -6

x = -6 : 2 = -3

4) 10 - 2(4 -3x) = -4

2(4 - 3x) = -4 - 10 = -14

4 - 3x = -14 : 2 = -7

3x = -7 - 4 = -18

x = -18 : 3 = -6

\(\left\{{}\begin{matrix}\left\{{}\begin{matrix}3x-15=45\Leftrightarrow3x=60\Leftrightarrow x=20\\35-5x=50\Leftrightarrow5x=-15\Leftrightarrow x=-3\end{matrix}\right.\\\left\{{}\begin{matrix}\left(2x-5\right)+17=6\Leftrightarrow2x+5=-11\Leftrightarrow2x=-16\Leftrightarrow x=-8\\10-2\left(4-3x\right)=-4\Leftrightarrow8-6x=14\Leftrightarrow6x=-6\Leftrightarrow x=-1\end{matrix}\right.\\\left\{{}\begin{matrix}-12+3\left(-x+7\right)=-18\Leftrightarrow-3x+21=-6\Leftrightarrow-3x=-27\Leftrightarrow x=9\\24:\left(3x-2\right)=-3\Leftrightarrow3x-2=-8\Leftrightarrow3x=-6\Leftrightarrow x=-2\end{matrix}\right.\\-45:5\left(-3-2x\right)=3\Leftrightarrow-15-10x=-15\Leftrightarrow10x=0\Leftrightarrow x=0\end{matrix}\right.\)

a) \(2^x=16\)

\(2^x=2^4\)

\(\Rightarrow x=4\)

vay \(x=4\)

b) \(4^x=64\)

\(4^x=4^3\)

\(\Rightarrow x=3\)

vay \(x=3\)

c) \(15^x=225\)

\(15^x=15^2\)

\(\Rightarrow x=2\)

vay \(x=2\)

d) \(2^x-15=17\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

vay \(x=5\)

e) \(2^x-64=2^6\)

\(2^x=2^6+64\)

\(2^x=128\)

\(2^x=2^7\)

\(\Rightarrow x=7\)

vay \(x=7\)

f) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

vay \(x=3\)

a, x=4

b, x=3

c, x=2

d, =2

a: =428(36+64)=42800

b: =512(47-37)=5120

c: =72x100=7200

\(428×(36+64)\)

\(=428×100\)

\(=42800\)

\(512×(47-37)\)

\(=512×10\)

\(=5120\)

\(72×(4×25)\)

\(=72×100\)

\(=7200\)

\(\left(\dfrac{4+5}{9}\right)\text{×}\dfrac{3}{7}\)

\(=1\text{×}\dfrac{3}{7}\)

\(=\dfrac{3}{7}\)

a, 428 x 36 + 64 x 428

=  428 x (36 + 64)

=  428 x 100

= 42800

b, 512 x 47 - 37 x 512

=  512 x (47 - 37)

= 512 x 10

= 5120

câu này mik bị lú nên hok lm

d) 4/9 x 3/7 + 5/9 x 3/7

= 3/7 x (4/9 + 5/9)

= 3/7 x 1

= 3/7