12^18 va 27^16*16^9
giup minh voi
26⋮XVA X≥13
16⋮X vaX<8
18⋮va 0<X<40
X⋮15 va 40 <x<30
x ⋮12 va 22≤5 x<50
x⋮4 va 16 ≤x ≤36
giup minh voi
\(\left\{{}\begin{matrix}26⋮x\\x\ge13\end{matrix}\right.\Rightarrow x\in\left\{13;26\right\}\)
\(\left\{{}\begin{matrix}16⋮x\\x< 8\end{matrix}\right.\Rightarrow x\in\left\{1;2;4\right\}\)
\(\left\{{}\begin{matrix}18⋮x\\0< x< 40\end{matrix}\right.\Rightarrow x\in\left\{1;2;3;6;9;18\right\}\)
\(\left\{{}\begin{matrix}x⋮15\\30< x< 40\end{matrix}\right.\Rightarrow x\in\varnothing\)
\(\left\{{}\begin{matrix}x⋮12\\22\le5x\le50\end{matrix}\right.\Rightarrow x\in\varnothing\)
\(\left\{{}\begin{matrix}x⋮4\\16\le x\le36\end{matrix}\right.\Rightarrow x\in\left\{16;20;24;28;32;36\right\}\)
giup minh voi
1+16+27-27-16.x=20
1+16+27-27-16.x=20
=> 1 .x=20
=> x=20:1
=> x=20
Vậy x= 20
27^16 . 16^9 và 12^18
so sanh 12 mu 8 va 27 mu 16 . 16 mu 9
Ta có:
12^8=(3.2^2)^8=3^8.2^16
27^16.16^9=(3^3)^16.(2^4)^9=3^48.2^36
<=>12^8<27^16.16^9
so sanh
(-1/16) mu 100 va (-1/2) mu 500
(1/81) mu 12 va (1/27) mu 16
(-2) mu 10 va 1000
2 mu 93 va 5 mu 35
a: \(\left(-\dfrac{1}{16}\right)^{100}=\left(\dfrac{1}{16}\right)^{100}=\left(-\dfrac{1}{2}\right)^{400}\)
\(\left(-\dfrac{1}{2}\right)^{500}=\left(-\dfrac{1}{2}\right)^{500}\)
mà \(400< 500\)
nên \(\left(-\dfrac{1}{16}\right)^{100}< \left(-\dfrac{1}{2}\right)^{500}\)
x+27=26-14 x-16=79+12
giup mik voi nha
x+27=26-14 x+27= 12 x=12-27 x=-15 x-16=79+12 x-16=91 x= 91+16 x=107
5/15 + 3/12 + 2/10 + 18/27 + 12/16 + 20/25
\(\dfrac{5}{15}+\dfrac{3}{12}+\dfrac{2}{10}+\dfrac{18}{27}+\dfrac{12}{16}+\dfrac{20}{25}\)
\(=\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{1}{4}+\dfrac{3}{4}+\dfrac{1}{5}+\dfrac{4}{5}\)
=3
Tính:
3/4-3/12
16/9-18/27
\(\dfrac{3}{4}-\dfrac{3}{12}=\dfrac{3\times3}{4\times3}-\dfrac{3}{12}=\dfrac{9}{12}-\dfrac{3}{12}=\dfrac{9-3}{12}=\dfrac{6}{12}=\dfrac{1}{2}\\ \dfrac{16}{9}-\dfrac{18}{27}=\dfrac{16}{9}-\dfrac{2}{3}=\dfrac{16}{9}-\dfrac{2\times3}{3\times3}=\dfrac{16}{9}-\dfrac{6}{9}=\dfrac{16-6}{9}=\dfrac{10}{9}\)
9/12 - 3/12 = 3/12
48/27 - 18/27 = 30/27
Học tốt nha. Nhớ tick cho tui nha
\(x+\dfrac{4}{9}+\dfrac{8}{18}+\dfrac{12}{27}+\dfrac{16}{36}=\dfrac{16}{9}\)
giúp mk với ạ
x + 4/9 + 8/18 + 12/27 + 16/36 = 16/9
x + (4/9+12/27)+(8/12+16/36) = 16/9
x + 8/9 + 10/9 = 16/9
x + 2 = 16/9
x = 16/9 - 2
x = -2/18
x+4/9+4/9+4/9+4/9=16/9
x+4/9.4=16/9
x+16/9=16/9
--> x = 0