\(x+\frac{5}{7}=\frac{7}{8}:\frac{1}{6}\)

\(\Leftrightarrow x+\frac{5}{7}=\frac{21}{4}\)

\(\Leftrightarrow x=\frac{127}{28}\)

\(\frac{72}{104}=\frac{72:8}{104:8}=\frac{9}{13}\)

\(\frac{3}{13}< \frac{4}{13}< \frac{5}{13}< \frac{6}{13}< \frac{7}{13}< \frac{8}{13}< \frac{72}{104}=\frac{9}{13}\)

Tìm x :

a ) \(x+\frac{5}{7}=\frac{7}{8}\div\frac{1}{6}=\frac{7\times6}{8\times1}=\frac{21}{4}\)

\(x=\frac{21}{4}-\frac{5}{7}=\frac{127}{28}\)

b ) \(\frac{15}{6}-x=\frac{5}{8}\times\frac{2}{15}=\frac{1}{12}\)

\(x=\frac{15}{6}-\frac{1}{12}=\frac{29}{12}\)

Rút gọn : \(\frac{72}{104}=\frac{72\div8}{104\div8}=\frac{9}{13}\)

Điền STN thích hợp :

\(\frac{3}{13}< \frac{4}{13}< \frac{5}{13}< \frac{6}{13}< \frac{7}{13}< \frac{8}{13}< \frac{9}{13}\left(\frac{72}{104}\right)\)Những số cần điền là : 4, 5, 6, 7, 8 .

==========> CHÚC HỌC GIỎI  NHỚ K MÌNH <==========

a) – 3 < x < 1 => x = 0

b) 0 < x < 3 => x ∈ {1;2}

c) -3 <  x < 8 => x ∈ {0;1;2;3;4;5;6;7}

13 - x + 72 = 60 x 2

13 - x + 72 = 120

12 - x = 120 - 72

12 - x = 48

x= 12 - 48

x= -36

13 - x + 72 =60 x 2

13 - x + 72 = 120 

13 - x = 120 - 72

13 - x = 48

x = 13 - 48

x = -35

Vậy: x = -35

13-x+72=60x2

13-x+72=120

13-x=120-72

13-x=48

x=13-48

x=-35

c nha 

72-7.(13-x)=14

=>7.(13-x)=72-14

=>7.(13-x)=58

=>13-x=58:7

=>13-x=\(\dfrac{58}{7}\)

\(=>x=13-\dfrac{58}{7}\)

\(=>x=\dfrac{33}{7}\)

Vậy ................

\(72-7(13-x)=14\)

\(7(13-x)=72-14\)

\(7(13-x)=58\)

\(13-x=58:7\)

\(13-x=\) \(\dfrac{58}{7}\)

\(x=13-\dfrac{58}{7}\)

\(x=\dfrac{33}{7}\)

\(72-7\left(13-x\right)=14\)

\(\Rightarrow72-91+7x-14=0\)

\(\Rightarrow7x=33\)

\(\Rightarrow x=\dfrac{33}{7}\)

\(72-7\left(13-x\right)=14\)
\(7\left(13-x\right)=58\)
\(13-x=\dfrac{58}{7}\)
\(x=13-\dfrac{58}{7}\)
\(x=\dfrac{91}{7}-\dfrac{58}{7}\)
\(x=\dfrac{33}{7}\)

`72-7(13-x)=14`

`=>7(13-x)=72-14`

`=>7(13-x)=58`

`=>13-x=58:7`

`=>13-x=58/7`

`=>x=13-58/7`

`=>x=33/7`

x=13−587�=13−587
x=337

Ta có: \(13\cdot\left(-47\right)-53\cdot13\)

\(=13\cdot\left(-47-53\right)\)

\(=13\cdot\left(-100\right)=-1300\)

Ta có: \(27\cdot\left(-67\right)+33\cdot\left(-27\right)\)

\(=27\cdot\left(-67\right)-33\cdot27\)

\(=27\left(-67-33\right)\)

\(=27\cdot\left(-100\right)=-2700\)

Ta có: \(-49\cdot65+36\cdot\left(-49\right)+49\)

\(=-49\cdot65+\left(-49\right)\cdot36+\left(-49\right)\cdot\left(-1\right)\)

\(=-49\cdot\left(65+36-1\right)\)

\(=-49\cdot100=-4900\)

Ta có: \(136\cdot\left(-47\right)+36\cdot47\)

\(=\left(-136\right)\cdot47+36\cdot47\)

\(=47\cdot\left(-136+36\right)\)

\(=47\cdot\left(-100\right)=-4700\)

Ta có: \(\left(-48\right)\cdot72+36\cdot\left(-304\right)\)

\(=-96\cdot36+36\cdot\left(-304\right)\)

\(=36\cdot\left(-96-304\right)\)

\(=36\cdot\left(-400\right)=-14400\)

2.

a, x-13=-46

=>x=(-46)+13

=>x=33

b, 4x-6=22

=>4x=22+6

=>4x=28

=>x=28:4

=>x=7

3.

a, 32=2⁵

48=2⁴.3

=>ƯCLN(32,48)=2⁴=16

16=2⁴

72=2³.3²

=>ƯCLN(16,72)=2³=8

b,

24=2³.3

60=2².3.5

=>BCNN(24,60)=2³.3.5=120

72=2³.3²

180=2².3².5

=>BCNN(72,180)=2³.3².5=360

a) x - 13  =  -   46 

    x         =  - ( 46 + 13 )                                

    x         =  - 59   

Chắc vậy

2a/ -33

2b/  7

3a/ 16

       8

3b/ 120

       360

a. (x + 5) - 15 . 13 = 15

(x + 5) - 195 = 15

x + 5 = 15 + 195

x = 210 - 5

x = 205

b. 6(28 - 8x) = 72

28 - 8x = 72 : 6

8x = 28 - 12

x = 16 : 8

x = 2

( X + 5) - 15 . 13 = 15

( x + 5 ) - 195 = 15

x + 5                = 210

x                     = 205

6 ( 28 - 8x )  = 72 

     28 - 8x    = 12

            8x   = 16

              x   = 2 

Study well 

Trả lời

(x+5)-15.13=15

=>(x+5)-195=15

=>x+5          =15+195

=>x+5          =210

=>x              =210-5

=>x              =205

6.(28-8.x)=72

=>28-8.x =72:6

=>28-8.x =12

=>8x       =28-12

=>8x       =16

=>x         =16:8

=>x         =2

a)x=72*x-x+x*29=2200

x*(72-1+29)=2200

x*100=2200

x=2200:100

X=22

b)Hình như bạn chép sai đề bài rồi mình học từ lớp 2 là không có số nào chia cho 0 bạn kiểm tra lại đề đi nếu muốn làm cũng như cách làm phần a)

a) 72 * x - x + 29 = 2000

x * (72 - 1 + 29) = 2000

x * 100 = 2000

x = 2000 : 100

x = 20

b) 13 * x - x * 12 - x = 190

x * (13 - 12 - 1) = 190

x * 0 = 190

x = 190 : 0

\(a,72\times x-x+x\times29=2200\)

      \(x\times\left(72-1+29\right)=2200\)

                            \(x\times100=2200\)

                                          \(x=2200:100\)

                                          \(x=22\)

\(b,13\times x-x\times12-x=190\)

      \(x\times\left(13-12-1\right)=190\)

                                  \(x\times0=190\)

=> ko có giá trị nào cả