Câu 5:

\(\dfrac{x}{y}=a\Rightarrow\dfrac{x}{a}=\dfrac{y}{1}=\dfrac{x-y}{a-1}=\dfrac{x+y}{a+1}\)

\(\Rightarrow\dfrac{x+y}{x-y}=\dfrac{a+1}{a-1}\)

Câu 6:

\(9x=5y\Rightarrow\dfrac{x}{5}=\dfrac{y}{9}\)

\(\Rightarrow\dfrac{x}{5}=\dfrac{y}{9}=\dfrac{3x}{15}=\dfrac{2y}{18}=\dfrac{3x-2y}{15-18}=\dfrac{12}{-3}=-4\)

\(\Rightarrow\left\{{}\begin{matrix}x=\left(-4\right).5=-20\\y=\left(-4\right).9=-36\end{matrix}\right.\)

Câu 7:

\(\dfrac{x}{-5}=\dfrac{y}{7}=\dfrac{x+y}{-5+7}=\dfrac{-10}{2}=-5\)

\(\Rightarrow\left\{{}\begin{matrix}x=\left(-5\right).\left(-5\right)=25\\y=\left(-5\right).7=-35\end{matrix}\right.\)

a b c c c a b c b b b c

1. a

2b

3c

4c

5. c

6,b

7. b

8. c

9b

10b

11b

12c

Bài 3:

\(A=\dfrac{10^9+1}{10^{10}+1}\Rightarrow10A=\dfrac{10^{10}+10}{10^{10}+1}\Rightarrow10A-1=\dfrac{9}{10^{10}+1}\)

\(B=\dfrac{10^8+1}{10^9+1}\Rightarrow10B=\dfrac{10^9+10}{10^9+1}\Rightarrow10B-1=\dfrac{9}{10^9+1}\)

\(Do\) \(\dfrac{9}{10^{10}+1}< \dfrac{9}{10^9+1}\Rightarrow10A-1< 10B-1\Rightarrow10A< 10B\Rightarrow A< B\)

\(A=7\left(1+7+7^2\right)+...+7^{118}\left(1+7+7^2\right)\)

\(=57\left(1+...+7^{118}\right)⋮57\)

1 friendly

2 orphanage

3 humorous

4 extremely

5 beautiful

6 luckily

7 peace

8 lovely

9 sociable

10 different

1, friendly

2, orphanage

3, humorous

4,extremely

5, beautiful

6, lucky

7 peace

8 lovely

9 sociable

10 different

2 inside

3 downstairs

4 in

5 outside

6 here

7 upstairs

8 on

9 over

10 out