Tìm X, biết:
\(\left|x-3\right|-2x=\left|x-4\right|\)
Những câu hỏi liên quan
Tìm x biết :a) left(x-2right)^3+6left(x+1right)^2-x^3+120b) left(x-5right)left(x+5right)-left(x+3right)^3+3left(x-2right)^2left(x+1right)^2-left(x+4right)left(x-4right)+3x^2c) left(2x+3right)^2+left(x-1right)left(x+1right)5left(x+2right)^2-left(x-5right)left(x+1right)+left(x+4right)^2d) left(1-3xright)^2-left(x-2right)left(9x+1right)left(3x-4right)left(3x+4right)-9left(x+3right)^2
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Tìm x biết :
a) \(\left(x-2\right)^3+6\left(x+1\right)^2-x^3+12=0\)
b) \(\left(x-5\right)\left(x+5\right)-\left(x+3\right)^3+3\left(x-2\right)^2=\left(x+1\right)^2-\left(x+4\right)\left(x-4\right)+3x^2\)
c) \(\left(2x+3\right)^2+\left(x-1\right)\left(x+1\right)=5\left(x+2\right)^2-\left(x-5\right)\left(x+1\right)+\left(x+4\right)^2\)
d) \(\left(1-3x\right)^2-\left(x-2\right)\left(9x+1\right)=\left(3x-4\right)\left(3x+4\right)-9\left(x+3\right)^2\)
a/ \(x=\dfrac{-5}{12}\)
b/ \(x\approx-1,9526\)
c/ \(x=\dfrac{21-i\sqrt{199}}{10}\)
d/ \(x=\dfrac{-20}{13}\)
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a) (x-2)3+6(x+1)2-x3+12=0
⇒ x3-6x2+12x-8+6(x2+2x+1)-x3+12=0
⇒ x3-6x2+12x-8+6x2+12x+6-x3+12=0
⇒ 24x+10=0
⇒ 24x=-10
⇒ x=-5/12
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a.
PT \(\Leftrightarrow x^3-6x^2+12x-8+6(x^2+2x+1)-x^3+12=0\)
\(\Leftrightarrow x^3-6x^2+12x-8+6x^2+12x+6-x^3+12=0\)
\(\Leftrightarrow 24x+10=0\Leftrightarrow x=\frac{-5}{12}\)
b. Bạn xem lại đề, nghiệm khá xấu không phù hợp với mức độ tổng thể của bài.
c.
PT $\Leftrightarrow (4x^2+12x+9)+(x^2-1)=5(x^2+4x+4)+(x^2-4x-5)+9(x^2+6x+9)$
$\Leftrightarrow 10x^2+42x+64=0$
$\Leftrightarrow x^2+(3x+7)^2=-15< 0$ (vô lý)
Do đó pt vô nghiệm.
d.
PT $\Leftrightarrow (1-6x+9x^2)-(9x^2-17x-2)=(9x^2-16)-9(x^2+6x+9)$
$\Leftrightarrow 11x+3=-54x-97$
$\Leftrightarrow 65x=-100$
$\Leftrightarrow x=\frac{-20}{13}$
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Xem thêm câu trả lời
26 tháng 10 2021 lúc 12:36
Tìm x biết :
\(\left|x-\dfrac{1}{2}\right|+\left|x-\dfrac{1}{3}\right|+\left|x-\dfrac{1}{4}\right|+....+\left|x-\dfrac{1}{10}\right|=2x\)
tìm x biết:
\(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
Tìm x biết:
\(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
(2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
<=.2x2-8x+3x-12+x2 -2x-5x+10=3x2-12x-5x+20
<=>5x=22
<=>x=22/5
vay
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Tìm x biết1) left(2x+3right)left(x-4right)+left(x-5right)left(x-2right)left(3x-5right)left(x-4right)2)left(8x-3right)left(3x+2right)-left(4x+7right)left(x+4right)left(2x+1right)left(5x+1right)-333)6xleft(3x+5right)-2xleft(9x-2right)+left(17-xright)left(x-1right)+xleft(x-18right)-17x^204)left(x-1right)left(x+2right)-left(x-3right)+5x-70Giúp mình nha. Camon nhiều
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Tìm x biết
1) \(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
2)\(\left(8x-3\right)\left(3x+2\right)-\left(4x+7\right)\left(x+4\right)=\left(2x+1\right)\left(5x+1\right)-33\)
3)\(6x\left(3x+5\right)-2x\left(9x-2\right)+\left(17-x\right)\left(x-1\right)+x\left(x-18\right)-17x^2=0\)
4)\(\left(x-1\right)\left(x+2\right)-\left(x-3\right)+5x-7=0\)
Giúp mình nha. Camon nhiều
Bài 4 : Tìm x, biết :a ) left|4-2xright|+left|x+3right|8b ) left|x+1right|+left|x-2right|+left|x+3right|6c ) left|x-2right|+left|x-3right|+left|4-xright|2d ) 2left|x+2right|+left|4-3xright|11e ) left|2x-1right|+left|2x-5right|4g ) left|x-3right|+left|3x+4right|left|2x+1right|
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Bài 4 : Tìm \(x\), biết :
a ) \(\left|4-2x\right|+\left|x+3\right|=8\)
b ) \(\left|x+1\right|+\left|x-2\right|+\left|x+3\right|=6\)
c ) \(\left|x-2\right|+\left|x-3\right|+\left|4-x\right|=2\)
d ) \(2\left|x+2\right|+\left|4-3x\right|=11\)
e ) \(\left|2x-1\right|+\left|2x-5\right|=4\)
g ) \(\left|x-3\right|+\left|3x+4\right|=\left|2x+1\right|\)
tìm x biết
a.\(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)6\left(x+1\right)^2=49\)49
b.\(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2+2\right)=25\)
c.\(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)=28\)
Tìm x biết :\(\left(x-1\right)^3+\left(x-3\right)^3=\left(2x-4\right)^3\)
\(\left(x-1\right)^3+\left(x-3\right)^3=\left(2x-4\right)^3\)
\(\Leftrightarrow\left(x-1\right)^3+\left(x-3\right)^3-\left(2x-4\right)^3=0\)
\(\Leftrightarrow\left(x-1\right)^3+\left(x-3\right)^3+\left(4-2x\right)^3=0\)
Đặt \(\left(x-1\right)=a;\left(x-3\right)=b;\left(4-2x\right)=c\)ta có:
\(a^3+b^3+c^3=0\)
\(\Leftrightarrow\left(a+b+c\right)^3-3\left(a+b\right)\left(b+c\right)\left(c+a\right)=0\)
\(\Leftrightarrow\left(a+b+c\right)^3=3\left(a+b\right)\left(b+c\right)\left(c+a\right)\)
Thay lại, ta được:
\(\left(a+b+c\right)^3=\left(x-1+x-3+4-2x\right)^3=0\)
\(\Rightarrow3\left(a+b\right)\left(b+c\right)\left(c+a\right)=0\)
\(\Leftrightarrow\left(a+b\right)\left(b+c\right)\left(c+a\right)=0\)
\(\Leftrightarrow\left(x-1+x-3\right)\left(x-3+4-2x\right)\left(4-2x+x-1\right)=0\)
\(\Leftrightarrow\left(2x-4\right)\left(1-x\right)\left(3-x\right)=0\)
\(\Leftrightarrow2x-4=0\Leftrightarrow2x=4\Rightarrow x=2\)
hoặc \(1-x=0\Leftrightarrow x=1\)
hay \(3-x=0\Leftrightarrow x=3\)
Vậy \(x\in\left\{1;2;3\right\}\). Xong :))
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Tìm x biết:\(\left(x-1\right)^3-\left(x-3\right)^3=\left(2x+4\right)^{^3}\)
Tìm x,biết :
\(x.\left(x-5\right).\left(x+5\right)-\left(x+2\right).\left(x^2-2x+4\right)=3\)
\(x\left(x^2-5^2\right)-\left(x^3+2^3\right)=3\)
\(x^3-25x-x^3-8=3\)
\(-25x-8=3\)
\(-25x=3+8=11\)
\(x=\frac{-11}{25}\)
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