tìm x :
450 - ( x : 7 + 8 ) . 2 - 16 = 24
2, Tìm x:
a) 45 + x = 79 + 2x
b) 15 - (x + 7) = (x - 8) +22
c) |x| = 5
d) x - ƯCLN(16; 24) = 7
Bài 2:
a: Ta có: \(2x+79=x+45\)
nên 2x-x=45-79
hay x=-24
b: Ta có: \(15-\left(x+7\right)=\left(x-8\right)+22\)
\(\Leftrightarrow8-x-x-14=0\)
\(\Leftrightarrow2x=22\)
hay x=11
Bài 1: Tìm x
x-7/12.x=5/24-3/8.x
(x-1/2).(-3-x/2)=0
x-3/-2=-8/x-3
=) (x-3).(x-3)=(-2).(-8)
(x-3) mũ 2 =16
\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)
\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)
Vậy x = 5/19
\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)
Vậy x = 1/2 hoặc x = -6
\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
\(\Leftrightarrow\left(x-3\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
Vậy x = 7 hoặc x = -1
Tìm x biết :
3 - ( 5 / 3 / 8 + x - 7 / 5 / 24) : 16 / 2 /3 = 2
\(3-\left(\frac{5}{\frac{3}{8}}+x-\frac{7}{\frac{5}{24}}\right):\frac{16}{\frac{2}{3}}=2\)
\(\Rightarrow3-\left(\frac{40}{3}+x-\frac{168}{5}\right):24=2\)
\(\Rightarrow\left(-\frac{304}{15}+x\right):24=1\)
\(\Rightarrow\frac{-304}{15}+x=24\)
\(\Rightarrow x=\frac{664}{15}\)
\(3-\left(\frac{5}{\frac{3}{8}}+x-\frac{7}{\frac{5}{24}}\right):\frac{16}{\frac{2}{3}}=2\)
\(\left(\frac{40}{3}+x-\frac{28}{5}\right):24=3-2\)
\(\left(\frac{40}{3}+x-\frac{28}{5}\right):24=1\)
\(\frac{40}{3}+x-\frac{28}{5}=1\cdot24\)
\(\frac{116}{15}+x=24\)
\(x=24-\frac{116}{15}\)
\(x=\frac{244}{15}\)
Tìm x biết:
1-(\(5\dfrac{3}{8}\)+x\(-7\dfrac{5}{24}\)):(\(-16\dfrac{2}{3}\))=0
`1-(5 3/8+x-7 5/24):(-16 2/3)=0`
`=>1-(5+3/8+x-7-5/24):(-50/3)=0`
`=>1=(x-2-11/6):(-50/3)`
`=>1=(x-11/6):(-50/3)`
`=>x-11/6=-50/3`
`=>x=-89/6`
Vậy `x=-89/6`
\(1-\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)=0\)
\(\Leftrightarrow1-\left(\dfrac{43}{8}+x-\dfrac{173}{24}\right):\dfrac{50}{3}=0\)
\(\Leftrightarrow1-\left(\dfrac{129}{24}-\dfrac{173}{24}+x\right).\dfrac{3}{50}=0\)
\(\Leftrightarrow1+\dfrac{11}{6}-x.\dfrac{3}{50}=0\)
\(\Leftrightarrow\dfrac{17}{6}-x.\dfrac{3}{50}=0\)
\(\Leftrightarrow x.\dfrac{3}{50}=\dfrac{17}{6}\)
\(\Leftrightarrow x=\dfrac{425}{9}\)
-Chúc bạn học tốt-
\(1-\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)=0\)
\(1-\left(\dfrac{43}{8}:\dfrac{-50}{3}+x:\dfrac{-50}{3}-\dfrac{173}{24}:\dfrac{-50}{3}\right)=0\)
\(1-\dfrac{-129}{400}-x:\dfrac{-50}{3}+\dfrac{-173}{400}=0\)
\(\left(1+\dfrac{129}{400}+\dfrac{-173}{400}\right)-x:\dfrac{-50}{3}=0\)
\(\dfrac{89}{100}-x:\dfrac{-50}{3}=0\)
\(x:\dfrac{-50}{3}=\dfrac{89}{100}-0\)
\(x:\dfrac{-50}{3}=\dfrac{89}{100}\)
\(x=\dfrac{89}{100}.\dfrac{-50}{3}\)
\(x=\dfrac{-89}{6}\)
2-(5 và 3/8 + x - 7 và 5/24) :16 và 2/3=0 tìm x
tìm x
a/ (5 3/8 + x - 7 5/24) : 16 2/3 = 1
Tìm x,y biết :
a) 1-(5/3/8+x-7/5/24): 16/2/3=0
b) (1/6+2/1/12-10,75).x-7= (2/5+3/8-2,225): 0,1
người ta ko bt thì hỏi , đừng có mak ns mấy câu vô văn hóa thế nhá
Tìm x
1-(5 3/8+X-7 5/24)=-16 2/3
/X+1/5/ -4=3/2
Tìm x
3-(5 3/8 : x - 7 5/24) : 16 2/3 = 23