a)

 \(3x^2+10x-8\le0\\ \Leftrightarrow\left(3x^2+12x\right)-\left(2x+8\right)\le0\\ \Leftrightarrow\left(x+4\right)\left(3x-2\right)\le0\\ \Leftrightarrow\left(x+4\right)\left(x-\dfrac{2}{3}\right)\le0\)

Mà \(x+4>x-\dfrac{2}{3}\)

\(\Rightarrow x+4\ge0\ge x-\dfrac{2}{3}\\ \Leftrightarrow\dfrac{2}{3}\ge x\ge-4\)

b) ĐKXĐ \(x\ne0\)

\(\dfrac{2}{x}-1< 2\\ \Leftrightarrow\dfrac{2}{x}< 3\left(1\right)\)

TH1 : x > 0 , (1) tương đương:

\(2< 3x\Leftrightarrow x>\dfrac{3}{2}\left(t.m\right)\)

TH2: x< 0 , (1) tương đương:

\(2>3x\Leftrightarrow x< \dfrac{3}{2}\) , kết hợp điều kiện \(\Rightarrow x< 0\)

Vậy phương trình có tập nghiệm \(S=\left(\dfrac{3}{2};+\text{∞ }\right)\text{∪}\left(-\text{∞ };0\right)\)

50 is cooking

51 has learned

52 is trying

53 washes

54 caught

55 caught

56 was swimming

57 broke - hurt

58 is moving

59 Is your friend sitting

60 is lying

61 is reading

62 are we going to have

63 has

64 am going to stay

65 comes

66 begins

67 are you eating

68 is Sue going to do

69 don't work

70 is not studying - is watching

71 plays 

72 visited

73 am going to watch

74 is studying

75 are having

76 Are you going to visit

77 haven't finished

78 are going

79 was waiting

80 Did she go

81 has wanted

82 have you been waiting

83 have watched

a: =>31-x-39=-58

=>-8-x=-58

=>x+8=58

hay x=50

b: =>-129-35+x=55

=>x-164=55

hay x=219

c: =>|x-7|=-37+127=90

=>x-7=90 hoặc x-7=-90

=>x=97 hoặc x=-83

d: =>|x-14|<2

=>x-14>-2 và x-14<2

=>12<x<16

e: =>315-x-315=43-12

=>-x=31

hay x=-31

f: =>|x-4|=4

=>x-4=4 hoặc x-4=-4

=>x=8 hoặc x=0

a: =>25-25+x=12+42-65

=>x=-11

b: =>|x+3|=4

=>x+3=4 hoặc x+3=-4

=>x=1 hoặc x=-7

c: =>x+17=13

hay x=-4

d: =>x+25-x=13-x

=>13-x=25

hay x=-12

e: =>15-30-x=x-(27-8)

=>-15-x=x-19

=>-x-x=-19+15

=>-2x=-4

hay x=2

f: \(\Leftrightarrow\left(12x-64\right)=4\cdot8=32\)

=>12x=96

hay x=8

\(g,\left[119-\left(3^3-10\right)\right].x=2448\\ \Leftrightarrow\left[119-\left(27-10\right)\right].x=2448\\ \Leftrightarrow\left[119-27+10\right].x=2448\\ \Leftrightarrow102.x=2448\\ \Leftrightarrow x=\dfrac{2448}{102}=24\\ h,\left[\left(10-x\right).2+51\right]:3-2=3\\ \Leftrightarrow\left[\left(10-x\right).2+51\right]:3=3+2=5\\ \Leftrightarrow\left[\left(10-x\right).2+51\right]=5.3=15\\ \Leftrightarrow\left(10-x\right).2=15-51=-36\\ \Leftrightarrow10-x=\dfrac{-36}{2}=-18\\ \Leftrightarrow x=10-\left(-18\right)=28\\ i,\left(x-12\right)-15=20-\left(17+x\right)\\ \Leftrightarrow x-12-15=20-17-x\\ \Leftrightarrow x+x=20-17+12+15\\ \Leftrightarrow2x=30\\ \Leftrightarrow x=\dfrac{30}{2}=15\)

\(k,-12-\left|13-x\right|=-21\\ \Leftrightarrow\left|13-x\right|=-12-\left(-21\right)=-12+21=9\\ \Leftrightarrow\left[{}\begin{matrix}13-x=9\\13-x=-9\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=13-9=4\\x=13-\left(-9\right)=13+9=22\end{matrix}\right.\)

Banj tham khaỏ

Câu này mình làm r

https://olm.vn/hoi-dap/detail/4645291454370.html

e: =(2004-2004)+(54-54)+(-15)=-15

f: =(-45789x2)-(357-57)=-91578-300=-91878

g: =(1259+1259)-(1409-1409)-12=2506

h: =(2750x2)-1229+438+29+438

=5500-1200+876

=5176

i: =-5+(-37+37)+(151+151)-45

=-50+302

=252

k: =(53-53)+(-145+145)-(359+259)=-618

e)2004-15+54-2004-54=(2004-2004)+(54-54)-15=-15

f)-45789-357-45789+57=(-45789-45789)-(357-57)=-91578-300=-91878

g)1259-1409-12+1259+140=(1259+1259)+(-1409+1409)-12=2518-12=2506

h)2750-1229+2750-(-438-29-438)=(2750+2750)-1229+438+29+438=5500-(1229-29)+(438+438)=5500-1200+876=5176

i)-5+-37-45+151--37=-5-37-45+151+37=(-5-45)+(-37+37)+151=-50+151=101

k)53-145-359-53+145-259=(53-53)+(-145+145)+(-359-259)=-618

l)-81-132-547+181-132-53=(-81+181)-(547+53)-(132+132)=100-600-264=-764

m)50-2016+50-118+2016-18=(50+50)+(-2016+2016)-(118+18)=100-136=-36

\(a=\sqrt[3]{2-\sqrt{3}}+\sqrt[3]{2+\sqrt{3}}\)

=>\(a^3=2-\sqrt{3}+2+\sqrt{3}+3\cdot\left(\sqrt[3]{2-\sqrt{3}}+\sqrt[3]{2+\sqrt{3}}\right)\cdot\sqrt[3]{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}\)

=>\(a^3=4+3a\)

=>\(a^3-3a=4\)

\(\Leftrightarrow a^2-3=\dfrac{4}{a}\)

\(\left(a^2-3\right)^3\)

\(=\left(\dfrac{4}{a}\right)^3=\dfrac{64}{a^3}\)

\(C=\dfrac{64}{\left(a^2-3\right)^3}-3a\)

\(=64:\dfrac{64}{a^3}-3a\)

=a^3-3a

=4