\(a,\left(4\sqrt{x}-\sqrt{2x}\right)\left(\sqrt{x}-\sqrt{2x}\right)=4x-4\sqrt{2}x-\sqrt{2}x+2x=6x-5\sqrt{2}x=\left(6-5\sqrt{2}\right)x\)

\(b,\left(2\sqrt{x}+\sqrt{y}\right)\left(3\sqrt{x}-2\sqrt{y}\right)=6x-4\sqrt{xy}+3\sqrt{xy}-2y=6x-4\sqrt{xy}-2y\)

a/ 6x

b/ 6x-2y-\(\sqrt{xy}\)

a> c1: \(=1-\sqrt{x^3}=1-\sqrt{x^2.x}=1-x\sqrt{x}\)

c2 \(=1+\sqrt{x}+x-\sqrt{x}-x-x\sqrt{x}=1-x\sqrt{x}\)

b> c1: \(=\sqrt{x}\left(4-\sqrt{2}\right)\sqrt{x-\sqrt{2x}=\sqrt{x\left(x-\sqrt{2x}\right)}}\left(4-\sqrt{2}\right)\)

c2: \(=4\sqrt{x\left(x-\sqrt{2x}\right)}-\sqrt{2x\left(x-\sqrt{2x}\right)}=\sqrt{x\left(x-\sqrt{2x}\right)}\left(4-\sqrt{2}\right)\)

a)\(\left(1-\sqrt{x}\right)\left(1+\sqrt{x}+x\right)=1-\sqrt{x^3}\)

b) \(\left(\sqrt{x}+2\right)\left(x-2\sqrt{x}+4\right)=\sqrt{x^3}+8\)

c)\(\left(\sqrt{x}-\sqrt{y}\right)\left(x+y+\sqrt{xy}\right)=\sqrt{x^3}-\sqrt{y^3}\)

d)\(\left(x+\sqrt{y}\right)\left(x^2+y-x\sqrt{y}\right)=x^3+\sqrt{y^3}\)

a: \(=1-\left(\sqrt{x}\right)^3=1-x\sqrt{x}\)

b: \(=\left(\sqrt{x}\right)^3+2^3=x\sqrt{x}+8\)

c: \(=\left(\sqrt{x}\right)^3-\left(\sqrt{y}\right)^3=x\sqrt{x}-y\sqrt{y}\)

d: \(=x^3+\left(\sqrt{y}\right)^3=x^3+y\sqrt{y}\)

\(\left(1-\sqrt{x}\right)\left(1+\sqrt{x}+x\right)=1-x\sqrt{x}\)

\(\left(\sqrt{x}+2\right)\left(x-2\sqrt{x}+4\right)=x\sqrt{x}+8\)

\(\left(\sqrt{x}-\sqrt{y}\right)\left(x+\sqrt{xy}+y\right)=x\sqrt{x}-y\sqrt{y}\)

\(\left(x+\sqrt{y}\right)\left(x^2-x\sqrt{y}+y\right)=x^3+y\sqrt{y}\)

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