\(7\cdot4^x=112\)

\(\Rightarrow4^x=\dfrac{112}{7}\)

\(\Rightarrow4^x=16\)

\(\Rightarrow4^x=4^2\)

\(\Rightarrow x=2\)

_____
\(2\cdot5^{x-3}=250\)

\(\Rightarrow5^{x-3}=\dfrac{250}{2}\)

\(\Rightarrow5^{x-3}=125\)

\(\Rightarrow5^{x-3}=5^3\)

\(\Rightarrow x-3=3\)

\(\Rightarrow x=3+3\)

\(\Rightarrow x=6\)

____

\(12:\left\{400:\left[500-\left(5^3+5^2\cdot7\right)\right]\right\}+10\)

\(=12:\left\{400:\left[500-\left(125+25\cdot7\right)\right]\right\}+10\)

\(=12:\left\{400:\left[500-\left(125+175\right)\right]\right\}+10\)

\(=12:\left[400:\left(500-300\right)\right]+10\)

\(=12:\left(400:200\right)+10\)

\(=12:2+10\)

\(=6+10\)

\(=16\)

\(7\cdot4^x=112\)

\(\Rightarrow4^x=112:7\)

\(\Rightarrow4^x=16\)

\(\Rightarrow4^x=4^2\)

\(\Rightarrow x=2\)

Vậy \(x=2.\)

\(---\)

\(2\cdot5^{x-3}=250\)

\(\Rightarrow5^{x-3}=250:2\)

\(\Rightarrow5^{x-3}=125\)

\(\Rightarrow5^{x-3}=5^3\)

\(\Rightarrow x-3=3\)

\(\Rightarrow x=3+3\)

\(\Rightarrow x=6\)

Vậy \(x=6.\)

\(---\)

\(12:\left\{400:\left[500-\left(5^3+5^2\cdot7\right)\right]\right\}+10\)

\(=12:\left\{400:\left[500-\left(125+175\right)\right]\right\}+10\)

\(=12:\left\{400:\left[500-300\right]\right\}+10\)

\(=12:\left\{400:200\right\}+10\)

\(=12:2+10\)

\(=6+10\)

\(=16\)

#\(Toru\)

\(2x=3y\text{⇒}\dfrac{x}{3}=\dfrac{y}{2}\text{⇒}\dfrac{x}{21}=\dfrac{y}{14}\)

\(5y=7z\text{⇒}\dfrac{y}{7}=\dfrac{z}{5}\text{⇒}\dfrac{y}{14}=\dfrac{z}{10}\)

⇒\(\dfrac{x}{21}=\dfrac{y}{14}=\dfrac{z}{10}\)⇒\(\dfrac{3x}{63}=\dfrac{7y}{98}=\dfrac{5z}{50}\)

Áp dụng tính chất dãy tỉ số bằng nhau, ta có:

\(\dfrac{3x}{63}=\dfrac{7y}{98}=\dfrac{5z}{50}=\dfrac{3x-7y+5z}{63-98+50}=\dfrac{30}{15}=2\)

⇒x=42,y=28,z=20

\(\dfrac{x}{3}=\dfrac{y}{2}\)⇒\(\dfrac{x}{15}=\dfrac{y}{10}\)

\(\dfrac{x}{5}=\dfrac{z}{7}\text{⇒}\dfrac{x}{15}=\dfrac{z}{21}\)

⇒\(\dfrac{x}{15}=\dfrac{y}{10}=\dfrac{z}{21}\)⇒\(\dfrac{x}{15}=\dfrac{2y}{20}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có:

\(\dfrac{x}{15}=\dfrac{2y}{20}=\dfrac{x+2y}{15+20}=\dfrac{-112}{35}=\dfrac{-16}{5}\)

⇒x=48,y=32,z=336/5

Lời giải:

1. Áp dụng tính chất dãy tỉ số bằng nhau:

$\frac{x}{3}=\frac{y}{2}=\frac{2y}{4}=\frac{x+2y}{3+4}=\frac{-112}{7}=-16$

$\Rightarrow x=-16.3=-48; y=-16.2=-32$

Đoạn $\frac{x}{5}=\frac{x}{7}$ là sao em? Em xem lại đề.

2. 

$2x=3y\Rightarrow \frac{x}{3}=\frac{y}{2}\Rightarrow \frac{x}{21}=\frac{y}{14}(1)$

$5y=7z\Rightarrow \frac{y}{7}=\frac{z}{5}\Rightarrow \frac{y}{14}=\frac{z}{10}(2)$

Từ $(1);(2)\Rightarrow \frac{x}{21}=\frac{y}{14}=\frac{z}{10}$

Áp dụng tính chất dãy tỷ số bằng nhau:

$\frac{x}{21}=\frac{y}{14}=\frac{z}{10}$

$=\frac{3x}{63}=\frac{7y}{98}=\frac{5z}{50}=\frac{3x-7y+5z}{63-98+50}=\frac{30}{15}=2$

$\Rightarrow x=2.21=42; y=2.14=28; z=2.10=20$

1122 x 19 = 21318

Lời giải:
Đặt \(\underbrace{111....1}_{100}=a\Rightarrow 9a+1=1\underbrace{000...0}_{100}\)

Khi đó:
\(\underbrace{1111....1}_{100}\underbrace{222....2}=\underbrace{111...1}_{100}\times 1\underbrace{00...0}_{100}+\underbrace{222....2}_{100}\)

\(a(9a+1)+2a=9a^2+3a=3a(3a+1)\) là tích của 2 số
 tự nhiên liên tiếp $3a, 3a+1$

Ta có đpcm.

Đáp số:

a) 4558

b) 1452

c) 3768

d) 21318

Máy tính nha bạn!^^

1/1113+1/1114*11/1122/45/5=1/1113+1/1114*11/1122/45/5

lấy máy tính

\(\frac{1}{1113}+\frac{1}{1114}.\frac{11}{1122}:\frac{45}{5}=8.994504463x10^{-4}\)

111...1222...2=333...3*444...4