\(4\frac{3}{4}\)+(-0,37)+\(\frac{1}{8}\)(-1,28)+(-2,5)+\(3\frac{1}{2}\)
tính theo 2 cách
\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{2}\)
tính theo 2 cách
\(\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{7}{2}=\left(\frac{19}{4}-\frac{37}{100}-\frac{32}{25}\right)+\left(\frac{7}{2}-\frac{5}{2}\right)+\frac{1}{8}=\frac{31}{10}+1+\frac{1}{8}=\frac{169}{40}\)
Tính một cách hợp lí :
\(4\frac{3}{4}+\left(0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{2}\)
\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
Tính một cách hợp lý:
3\(\frac{4}{4}\)+ (-0,37) +\(\frac{1}{8}\)+ (-1,28) + (-2,5) + 3\(\frac{1}{12}\)
\(\left(4\frac{3}{4}+\frac{1}{8}+3\frac{1}{12}\right)-\left(0,37+1,28+2,25\right)\)
\(=7\frac{23}{24}-4,15\)
\(=7\frac{23}{24}-4\frac{3}{20}\)
\(=3\frac{97}{120}\)
Tính bằng cách hợp lí :
a , \(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{2}\)
b ,\(\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{59\cdot61}\)
c,\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
tính 2 cách
a)\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{2}\)
b)\(\frac{\frac{22}{5}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
giúp mk nha
a: \(=\dfrac{17}{4}-\dfrac{37}{100}+\dfrac{1}{8}-\dfrac{32}{25}-\dfrac{5}{2}+\dfrac{7}{2}\)
\(=\dfrac{35}{8}+\dfrac{8}{8}-\dfrac{37}{100}-\dfrac{128}{100}\)
\(=\dfrac{43}{8}-\dfrac{165}{100}=\dfrac{149}{40}\)
b: \(=\left(\dfrac{22\cdot26+3\cdot10-65}{130}\right):\left(\dfrac{4\cdot22-2\cdot26+3\cdot143}{286}\right)\)
\(=\dfrac{537}{130}\cdot\dfrac{286}{465}=\dfrac{1969}{775}\)
\(4\frac{3}{4}\)+(-0,37)+\(\frac{1}{8}\)+(-1,28)+(-2,5)+\(3\frac{1}{12}\)
\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=4,75-0,37+0,125-1,28-2,5+\frac{37}{12}\)
\(=0,725+\frac{37}{12}\)
\(=\frac{457}{120}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)\)
\(4\frac{3}{4}+\left(-0,37\right)+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
(giải giúp mình với)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)=\frac{58}{7}-\frac{17}{12}=\frac{577}{84}\)
\(4\frac{3}{4}+\left(-0,37\right)+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=\frac{19}{4}+\left(-\frac{83}{20}\right)+\frac{37}{12}=\frac{3}{5}+\frac{37}{12}=\frac{221}{60}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)=\frac{58}{7}-\frac{17}{12}=\frac{577}{84}\)
\(8\frac{2}{7}-\left(1\frac{1}{6}+25\%\right)\)
\(=\frac{58}{7}-\left(\frac{7}{6}+\frac{1}{4}\right)\)
\(=\frac{58}{7}-\frac{17}{12}\)
\(=\frac{577}{84}\)
\(4\frac{3}{4}\)+ ( -0,37 ) + \(\frac{1}{8}\)+ ( -1,28 ) + ( - 2,5 ) + \(3\frac{1}{12}\)
GIÚP MIK NHANH VS..CẢM ƠN
\(=\frac{19}{4}+\left(-0.37\right)+\frac{1}{8}+\left(-1.28\right)+\left(-2.5\right)+\frac{37}{12}\)\(\frac{37}{12}\)
\(=\left(\frac{19}{4}+\frac{1}{8}+\frac{37}{12}\right)+\left(\left(-0.37\right)+\left(-1.28\right)+\left(-2.5\right)\right)\)
\(=\frac{191}{24}+\left(-\frac{83}{20}\right)\)
\(=\frac{457}{120}\)
4\(\frac{3}{4}\) -0,37+\(\frac{1}{8}\)-1,28-2,5+3\(\frac{1}{12}\)
caccau giup mik nha
= 19/4 - 0,37 + 1/8 - 1,28 - 2,5 + 37/12
= 19/4 - 37/100 + 1/8 - 32/25 - 5/2 + 37/12
= 219/50 + (-231/200) - 67/12
= 129/40 - 67/12
=(-283/120)
bạn k cho mình đi làm ơn đó
\(4\frac{3}{4}-0,37+\frac{1}{8}-1,28-2,5+3\frac{1}{12}\)
\(=\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{37}{12}\)
\(=\frac{4750}{1000}-\frac{370}{1000}+\frac{125}{1000}-\frac{1280}{1000}-\frac{2500}{1000}+\frac{37}{12}\)
\(=\frac{4750-370+125-1280-2500}{1000}+\frac{37}{12}\)
\(=\frac{29}{40}+\frac{37}{12}=\frac{87}{120}+\frac{370}{120}=\frac{457}{120}=3\frac{97}{120}\)
--Good luck--
\(4\frac{3}{4}-0,37+\frac{1}{8}-1,28-2,5+3\frac{1}{12}\)
= \(\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{37}{12}\)
= \(\frac{4750}{1000}-\frac{370}{1000}+\frac{125}{1000}-\frac{1280}{1000}-\frac{1500}{1000}+\frac{37}{12}\)
= \(\frac{4750-370+125-1280-2500}{1000}+\frac{37}{12}\)
=\(\frac{29}{40}+\frac{37}{12}=\frac{87}{120}+\frac{370}{120}=3\frac{97}{120}\)
Good luck