Bài 2:

b: \(=\left(x^2+x+4+3x\right)\left(x^2+x+4+5x\right)\)

\(=\left(x^2+4x+4\right)\left(x^2+6x+4\right)\)

\(=\left(x+2\right)^2\cdot\left(x^2+6x+4\right)\)

c: \(=25x^2-49y^2-\left(5x+7y\right)\)

=(5x+7y)(5x-7y-1)

d: \(8x^3-36x^2+54x-27=\left(2x-3\right)^3\)

\(\left(x-2\right)^3+\left(x+2\right)^3-x^3-8x^2+10\)

\(=x^3-6x^2+12x-8+x^3+6x^2+12x+8-x^3-8x^2+10\)

\(=x^3-2x^2+24x+10\)

\(\frac{3}{4}\cdot\frac{8}{5}\cdot\frac{5}{9}=\frac{2}{3}\)

\(\frac{3}{7}:\frac{3}{14}:\frac{1}{2}=4\)

cậu ghi lòi  giải ra được không

a) \(\frac{3}{4}x\frac{8}{5}x\frac{5}{9}=\frac{3x8x5}{4x5x9}=\frac{120}{180}=\frac{2}{3}\)

b) \(\frac{6}{7}:\frac{3}{14}:\frac{1}{2}=\frac{6}{7}x\frac{14}{3}x\frac{1}{2}=\frac{84}{42}=2\)

\(\dfrac{7}{2}\times\dfrac{3}{4}+\dfrac{17}{8}\times\dfrac{2}{3}+\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{7}{8}\times\dfrac{3}{3}\)

\(=\dfrac{7\times3}{2\times4}+\dfrac{17\times2}{8\times3}+\dfrac{3\times1}{4\times2}+\dfrac{7}{8}\times1\)

\(=\dfrac{21}{8}+\dfrac{17}{12}+\dfrac{3}{8}+\dfrac{7}{8}\)

\(=\left(\dfrac{21}{8}+\dfrac{3}{8}+\dfrac{7}{8}\right)+\dfrac{17}{12}\)

\(=\dfrac{31}{8}+\dfrac{17}{12}\)

\(=\dfrac{31\times3}{8\times3}+\dfrac{17\times2}{12\times2}\)

\(=\dfrac{93}{24}+\dfrac{34}{24}\)

\(=\dfrac{127}{24}\)

\(a,\dfrac{9}{5}+\dfrac{2}{5}\times\dfrac{4}{6}=\dfrac{9}{5}+\dfrac{4}{15}=\dfrac{27}{15}+\dfrac{4}{15}=\dfrac{31}{15}\\ b,\dfrac{3}{8}\times2-\dfrac{6}{7}\times\dfrac{1}{3}=\dfrac{3}{4}-\dfrac{2}{7}=\dfrac{21}{28}-\dfrac{8}{28}=\dfrac{13}{28}\)

A)=9/5 + 4/15

=27/15+4/15

=31/15

B)=3/4-2/14

=36/28-4/28

=32/28=?

Thu gọn và sắp xếp phải k ạ?

`F(x)= (x^4-x^4)+(5x^2-8x^2)-4x+x^5+3+2x^3+2`

`F(x) = -3x^2-4x+x^5+3+2x^3+2`

`F(x)= x^5+2x^3-3x^2-4x+3+2`

\(F\left(x\right)=x^4+5x^2-4x+x^5-x^4-8x^2+3+2x^3+2\)

\(F\left(x\right)=x^5+\left(x^4-x^4\right)+2x^3+\left(5x^2-8x^2\right)-4x+\left(3+2\right)\)

\(F\left(x\right)=x^5+2x^3-3x^2-4x+5\)

bạn tính vế trái,vế phải ra thì có:

33<x+2<35

x+2=34

x=32

mk chắc chắn với bn là x bằng 32

k mk nha

\(\text{Sửa đề : }A=\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{292\times294}\)

\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{292}-\frac{1}{294}\)

\(=\frac{1}{2}-\frac{1}{294}\)

\(=\frac{73}{147}\)

\(\text{Vậy }A=\frac{73}{147}\)