tính.
\(\sqrt[-0.4]{\left(-0,4\right)^2}\)
Những câu hỏi liên quan
Tính giá trị biểu thức :
\(M=\frac{7\ln\left(3+2\sqrt{2}\right)-64\ln\left(\sqrt{2}+1\right)-50\ln\left(\sqrt{2}-1\right)+2}{lg125^{-1}-lg0.8+6lg\sqrt[3]{0.4}+4lg50}\)
Ta có :
\(M=\frac{7\ln\left(\sqrt{2}+1\right)^2-64\ln\left(\sqrt{2}+1\right)-50\ln\left(\sqrt{2}+1\right)^{-1}+2}{-3lg5-lg\left(10^{-1}.2^3\right)+6lg\left(10^{-\frac{1}{3}}.2^{\frac{2}{3}}\right)+4lg\left(10.5\right)}\)
\(=\frac{2}{lg5+1-3lg2-2+4lg2+4}=\frac{1}{2}\)
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i,\(\sqrt{12,1.360}\)
k,\(\sqrt{0,4}.\sqrt{6,4}\)
l,-0,4\(\sqrt{\left(-0,4\right)^2}\)
m,\(\sqrt{2^4.\left(-7\right)^2}\)
\(i,\sqrt{12,1.360}=\sqrt{12,1}.6\sqrt{10}=6.\sqrt{12,1.10}=6.\sqrt{121}=6.\sqrt{11^2}=6.11=66\)
\(k,\sqrt{0,4}.\sqrt{6,4}=\sqrt{0,4.6,4}=\sqrt{\dfrac{64}{25}}=\dfrac{\sqrt{8^2}}{\sqrt{5^2}}=\dfrac{8}{5}\)
\(l,-0,4.\sqrt{\left(-0,4\right)^2}=-0,4.0,4=-0,16\)
\(m,\sqrt{2^4.\left(-7\right)^2}=\sqrt{4^2}.\sqrt{\left(-7\right)^2}=4.7=28\)
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i, \(\sqrt{12,1\cdot360}=\sqrt{4356}=\sqrt{66^2}=66\)
k, \(\sqrt{0,4}.\sqrt{6,4}=\sqrt{0,4\cdot6,4}=\sqrt{\dfrac{64}{25}}=\sqrt{\dfrac{2^6}{5^2}}=\dfrac{2^3}{5}=\dfrac{8}{5}\)
l, \(-0,4\sqrt{\left(-0,4\right)^2}=-0,4\cdot\left|-0,4\right|=-0,4\cdot0,4=-\dfrac{4}{25}\)
m, \(\sqrt{2^4\cdot\left(-7\right)^2}=2^2\cdot\left|-7\right|=4\cdot7=28\)
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i) \(\sqrt{12,1.360}=\sqrt{12,1}.\sqrt{360}=\sqrt{12,1}.\sqrt{36}.\sqrt{10}=\left(\sqrt{12,1}.\sqrt{10}\right)\sqrt{36}=\sqrt{121}.\sqrt{36}=11.6=66\)
k) \(\sqrt{0,4}.\sqrt{6,4}=\sqrt{0,4.6,4}=\sqrt{2,56}=1,6\)
l) \(-0,4\sqrt{\left(-0,4\right)^2}=-0,4\left|-0,4\right|=-0,4.0,4=0,16\)
m) \(\sqrt{2^4.\left(-7\right)^2}=\sqrt{2^2.2^2.\left(-7\right)^2}=\left|2.2.7\right|=28\)
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Tính:
a) \(\sqrt{\left(0,1\right)^2}\)
b) \(\sqrt{\left(-0,3\right)^2}\)
c) \(-\sqrt{\left(-1,3\right)^2}\)
d) \(-0,4\sqrt{\left(-0,4\right)^2}\)
Tính:
a. \(\sqrt{\left(0,1\right)^2};\) b. \(\sqrt{\left(-0,3\right)^2};\) c. \(-\sqrt{\left(-1,3\right)^2};\) d. \(-0,4\sqrt{\left(-0,4\right)^2}.\)
a, 0,1
b,0,3
c,-1,3
d,-0,16
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Bài 1: Thực hiện phép tính:
\(\sqrt{25}\)x\(\left(0,4-1\dfrac{1}{12}\right)\):\(\left[\left(-2\right)^3x\dfrac{11}{8}\right]\)
\(=5\cdot\left(\dfrac{2}{5}-\dfrac{13}{12}\right):\left[-8\cdot\dfrac{11}{8}\right]\)
\(=5\cdot\dfrac{-41}{60}\cdot\dfrac{-1}{11}=\dfrac{205}{60\cdot11}=\dfrac{41}{132}\)
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= 5. (0,4 - 13/12) : -11
= 5. -41/60 : -11
=-41/132
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Tính
A=\(\sqrt{0,36}-\left(\sqrt{25}-\sqrt{49}:\sqrt{4}\right).\sqrt{0,4}-\sqrt{10}^2\)
1.Tính :
a.\(-\frac{4}{3}.\sqrt[]{\left(-0.4\right)^2}\)
b.\(5.\sqrt{\left(-\frac{1}{5}\right)^2}\)
c.\(4.\sqrt[]{\left(-3\right)^6+5.\sqrt[]{\left(-2\right)^4}}\)
d.\(3.\sqrt[]{\left(-15\right)^2}-4.\sqrt[]{\left(-0.5\right)^2}\)
Tính:
\(a,\sqrt{0,1^2}\)
\(b,\sqrt{\left(-0,4\right)^2}\)
\(c,-\sqrt{\left(-1,7\right)^2}\)
\(d,-0,5\sqrt{\left(-0,5\right)^4}\)
\(e,\sqrt{\left(1-\sqrt{2}\right)^2}\)
\(g,\sqrt{\left(\sqrt{3}-1\right)^2}\)
\(a,\sqrt{0,1^2}=0,1\)
\(b,\sqrt{\left(-0,4\right)^2}=|-0,4|=0,4\)
\(c,-\sqrt{\left(-1,7\right)^2}=-|-1,7|=-1,7\)
\(d,-0,5\sqrt{\left(-0,5\right)^4}=\frac{-1}{2}\sqrt{[\left(\frac{-1}{2}\right)^2]^2}=-\frac{1}{2}.\left(\frac{1}{2}\right)^2=\frac{-1}{2}.\frac{1}{4}=\frac{-1}{8}\)
\(e,\sqrt{\left(1-\sqrt{2}\right)^2}=|1-\sqrt{2}|=\sqrt{2}-1\)
\(g,\sqrt{\left(\sqrt{3}-1\right)^2}=|\sqrt{3}-1|=\sqrt{3}-1\)
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f)\(\sqrt{\left(\sqrt{2}-\sqrt{3}\right)^2}\)- \(\dfrac{\sqrt{6}-3}{\sqrt{2}-\sqrt{3}}\)
g)\(\left(\sqrt{8}-3\sqrt{2}+\sqrt{10}\right).\left(\sqrt{2}-3\sqrt{0,4}\right)\)
giải chi tiết cụ thể giúp mk với ạ