ai giúp mình nhanh đc ko

\(a,3^{39}=\left(3^3\right)^{13}=9^{13}< 11^{13}< 11^{21}\\ b,2^{91}=\left(2^{13}\right)^7=8192^7< 3125^7=\left(5^5\right)^7=5^{35}\)

Đây bạn nhé! Chữ hơi xấu, thông cảm

2⁹¹ và 5³⁵

2⁹¹ = (2¹³)⁷ = 8192⁷

5³⁵ = (5⁵)⁷ = 3125⁷

Vì 8192⁷ > 3125⁷ => 2⁹¹ > 5³⁵

Vậy 2⁹¹ > 5³⁵

2⁹¹ <  5³⁵

2 mũ 21>5 mũ35

Ta có: 291 > 290 = (25)18 = 3218

535 < 536 = (52)18 = 2518.

Vì 32 > 25 nên 3218 > 2518, do đó ta có : 291 > 3218 > 2518 > 535.

Vậy 291 > 535.

291 < 535

291 < 535 

291 < 535

`2^{91}=(2^{13})^{7}=8192^{7}`

`5^{35}=(5^{5})^{7}=3125^{7}`

Vì `8192^{7}>3125^{7}`

`->2^{91}>5^{35}`

\(2^{91}=\left(2^{13}\right)^7=8192^7\)

\(5^{35}=\left(5^5\right)^7=3125^7\)

Mà \(8192^7>3125^7\Rightarrow2^{91}>5^{35}\)

\(2^{91}=\left(2^{13}\right)^7\)

\(5^{35}=\left(5^5\right)^7\)

mà \(2^{13}>5^5\)

nên \(2^{91}>5^{35}\)

Ta có : \(\dfrac{-23}{91}>\dfrac{-131}{91}\\ \dfrac{-131}{91}>\dfrac{-131}{535}\\ nên\dfrac{-131}{535}>\dfrac{-23}{91}\)

\(a=\left[\left(-\dfrac{1}{2}\right)^5\right]^{107}=\left(-\dfrac{1}{32}\right)^{107}\)

\(b=\left[\left(-\dfrac{1}{3}\right)^3\right]^{107}=\left(-\dfrac{1}{27}\right)^{107}\)

mà -1/32>-1/27

nên a>b

a>b

a) \(\dfrac{17}{20}< \dfrac{18}{20}< \dfrac{18}{19}\Rightarrow\dfrac{17}{20}< \dfrac{18}{19}\)

b) \(\dfrac{19}{18}>\dfrac{19+2024}{18+2024}=\dfrac{2023}{2022}\Rightarrow\dfrac{19}{18}>\dfrac{2023}{2022}\)

c) \(\dfrac{135}{175}=\dfrac{27}{35}\)

\(\dfrac{13}{17}=\dfrac{26}{34}< \dfrac{26+1}{34+1}=\dfrac{27}{35}\)

\(\Rightarrow\dfrac{13}{17}< \dfrac{135}{175}\)