a: \(B=\left(4\cdot2^5\right):\left(2^3\cdot\frac{1}{16}\right)\)

\(=\left(4\cdot32\right):\left(\frac{8}{16}\right)\)

\(=128:\frac12=128\cdot2=256\)

b: \(B=3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}\)

\(=3^2\cdot\frac{1}{3^5}\cdot3^8\cdot\frac{1}{3^3}=\frac{3^8}{3^8}\cdot3^2=3^2=9\)

c: \(D=\left\lbrace\left(0,1\right)^2\right\rbrace^0+\left\lbrack\left(\frac17\right)^1\right\rbrack^2:\frac{1}{49}\cdot\left\lbrack\left(2^2\right)^3:2^5\right\rbrack\)

\(=1+\left(\frac17\right)^2\cdot49\cdot2^6:2^5\)

\(=1+49\cdot\frac{1}{49}\cdot2=1+2=3\)

d: \(C=\left(-0,5\right)^5:\left(-0,5\right)^3-\left(\frac{17}{2}\right)^7:\left(\frac{17}{2}\right)^6\)

\(=\left(-0,5\right)^{5-3}-\left(\frac{17}{2}\right)\)

\(=\left(-0,5\right)^2-\frac{17}{2}=0,25-\frac{17}{2}=\frac14-\frac{34}{4}=-\frac{33}{4}\)

mong các bạn giúp đỡ mình nhé! Mình đang cần gấp!

\(B=\left[\left(0,1\right)^2\right]^0+\left[\left(\frac{1}{7}\right)^{-1}\right]^2.\frac{1}{49}.\left[\left(2^2\right)^3.2^5\right]\)

\(=1+\left(\frac{1}{\frac{1}{7}}\right)^2.\frac{1}{49}.\left(2^6.2^5\right)\)

\(=1+7^2.\frac{1}{49}.2^{11}\)

\(\Rightarrow1+49.\frac{1}{49}.2^{11}\)

\(=1+2^{11}\)

Vậy \(B=1+2^{11}\)

a) \(\frac{81}{16}\)

b) \(\frac{-31}{8}\)

c) \(\frac{2417}{2401}\)

Bài 31:

a) \(\left(2^{-1}+3^{-1}\right):\left(2^{-1}-3^{-1}\right)+\left(2^{-1}.2^0\right):2^3\)

\(=\left(\frac{1}{2}+\frac{1}{3}\right):\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{2}.1\right):8\)

\(=\frac{5}{6}:\frac{1}{6}+\frac{1}{2}:8\)

\(=5+\frac{1}{16}\)

\(=\frac{81}{16}.\)

c) \(\left[\left(0,1\right)^2\right]^0+\left[\left(\frac{1}{7}\right)^1\right]^2.\frac{1}{49}.\left[\left(2^3\right)^3:2^5\right]\)

\(=1+\frac{1}{49}.\frac{1}{49}.16\)

\(=1+\frac{1}{2401}.16\)

\(=1+\frac{16}{2401}\)

\(=\frac{2417}{2401}.\)

Chúc bạn học tốt!

đây

đây

đây

nhanh lên nha mn

có là mik k lun(nhớ đúng nhé)

anh ơi đang kiểm tra anh tự làm đi đừng hỏi anh ạ

em khuyên chân thành để tốt cho anh đấy

anh?!!!