help ạ . mk cảm ơn
Hãy tưởng tượng mình là Bê-li-cốp để cảm nhận về cảm xúc và cuộc sống sau khi chết.
giúp mk vs m.n ơi mai mk kt r, mà ko có ý lm, cảm ơn ạ, help me.
What do you think people will use to communicate in the future ?
You should mention:
- what it is.
- how it works.
- how it can help people mk cần gấp mk cảm ơn ạ
Help ạ! Cảm ơn ạ
13 D
14 A
15 A
16 C
17 B
18 A
19 C
20 B
1 the cleverest
2 longer
3 the best
4 cleaner
5 more expensive
6 the most quickly
7 more dangerous
8 more sweetly
9 the most exciting
10 the fastest
1 beautifully
2 carefully
3 badly
4 quietly
5 loud
6 happily
7 fast
8 well
9 terribly
10 early
11 hard
12 late
Mn ưi, làm ơn giúp mk vs ạ mk cảm ơn chx ạ☺️
giúp mk ạ . mk cảm ơn ạ
giúp mk phần mk khoanh ạ . mk cảm ơn ạ
Does your father get to work by bicycle?
Does your father get to work by bicycle?
3. Does your father cycle to work?
Does your father get to work by bike?
Help mình với ạ, cảm ơn.
a) Từ trái qua phải
\(Na_2O+H_2O\rightarrow2NaOH\)
\(2NaOH+CO_2\rightarrow Na_2CO_3+H_2O\)
\(Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+CO_2\uparrow+H_2O\)
\(Na_2SO_4+BaCl_2\rightarrow2NaCl+BaSO_4\downarrow\)
b) Từ trái qua phải
\(Fe+2HCl\rightarrow FeCl_2+H_2\uparrow\)
\(FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2\downarrow+2NaCl\)
\(Fe\left(OH\right)_2\xrightarrow[]{t^o}FeO+H_2O\)
\(FeO+2HCl\rightarrow FeCl_2+H_2O\)
\(2FeCl_2+4H_2SO_{4\left(đ,n\right)}\rightarrow Fe_2\left(SO_4\right)_3+4HCl+SO_2\uparrow+2H_2O\)
help em vs ạ cảm ơn :3
Bài 2:
a: 3/8=81/216
5/27=40/216
b: -2/9=-50/225
4/25=36/225
c: 1/15=1/15
-6=-90/15
help em vs ạ . e cảm ơn
\(\Leftrightarrow\left\{{}\begin{matrix}2x-3y=3\sqrt{5}-1\\4x+\left(2\sqrt{5}+2\right)y=-4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x-6y=6\sqrt{5}-2\\4x+\left(2\sqrt{5}+2\right)y=-4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(-8-2\sqrt{5}\right)y=6\sqrt{5}+2\\2x-3y=3\sqrt{5}-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=1-\sqrt{5}\\x=\dfrac{3\sqrt{2}-3\sqrt{5}+2}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4x-6y=6\sqrt{5}-2\\3.\left(\sqrt{5}-1\right)x+6y=3-3\sqrt{5}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}\left(3\sqrt{5}+1\right)x=1+3\sqrt{5}\\y=\dfrac{3\sqrt{5}-1-2x}{-3}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=1\\y=\dfrac{3\sqrt{5}-1-2.1}{-3}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=1\\y=\dfrac{-3.\left(1-\sqrt{5}\right)}{-3}=1-\sqrt{5}\end{matrix}\right.\\ \Rightarrow\left(x;y\right)=\left(1;1-\sqrt{5}\right)\)