Winter in Vietnam is from late October to February. While the central and south of Vietnam get the most sunlight, which offers tourists the perfect Vietnam beach vacation with (20) temperatures ranging from 23 to 26 degrees Celsius, the north region endures humid coldness. (21)   the coldness of Northern Vietnam in winter, tourism remains in full operation as many foreign travelers come to visit this area during the time.

Sapa is beautiful all year round, but winter provides a special charm that visitors will not want to miss. The fog creates an aura of mystery that also (22)   credence to Sapa’s reputation as Heaven’s Resort. Many people, especially photography lovers, visit the town in winter (23) the temperature can dip below the freezing point, (24)  an amazing look with snow. If you love peace and tranquility, Sapa is a must-see place on your tour of Vietnam.

Mai Chau in winter can be quite cold since it has high humidity at that time of year. The region is

(25)  different ethnic minorities and provides a culturally rich experience to any tourist. You can spend your time biking and trekking or taking in the sights of farmers tending to their paddy fields. Make your way to Chieu Cave as well, which boasts stunning stalactites that are breathtaking in their beauty.

Tam Dao is also a splendid sight to visit. Majestic mountains loom through clouds and invite visitors to marvel (26)  their beauty. One of the highlights of this area is Tam Dao National Park. It has a unique climate as the tall mountain range divides the region into two parts, which (27)

rich biodiversity. The park has eight types of forests and more than 800 species of animals.

Thời gian ô tô đi từ A đến B là:

11 giờ 20 phút - 6 giờ 20 phút = 5 giờ

Vận tốc của ô tô là:

VD2 : B

 Đặt A = 777...777 ( 1995 chữ số 7 )

Đặt A = B + C trong đó :

B = 777...000 (1992 chữ số 7, 3, 0 )

C = 777

a) A= \(\dfrac{x+5}{x+2}\)
   A = \(\dfrac{\left(x+2\right)+3}{x+2}\)
   A = \(1+\dfrac{3}{x+2}\)
Để A là số nguyên

=> \(\dfrac{3}{x+2}\) thuộc số nguyên
=>x+2 ∈ Ư(3)={1;-1;3;-3)

Vậy x ∈ {-1;-3;1;-5} thì A nguyên

b)  A= \(\dfrac{x+5}{x+2}\)
A = \(\dfrac{\left(x+2\right)+3}{x+2}\)
   A = \(1+\dfrac{3}{x+2}\)

Để A có GTLN thì \(\dfrac{3}{x+2}\) ∈ Ư(3) = {1,-1,3,-3}

Ta có

\(\dfrac{3}{1+2}\)  = \(\dfrac{3}{3}\) = 1

\(\dfrac{3}{-1+2}\) = \(\dfrac{3}{1}\)= 3

\(\dfrac{3}{3+2}\) = \(\dfrac{3}{5}\)

\(\dfrac{3}{-3+2}\) = \(\dfrac{3}{-1}\) = -3

=> A = -1 thì A là GTLN

Gọi số sản phẩm phân xưởng 1 làm được là: 1 phần

Số sản phẩm phân xưởng 2 làm được là: 2 phần

=> Số sản phẩm phân xưởng 2 làm được là:

405 : (2+1) . 2 = 270 (sản phẩm)

Số sản phẩm phân xưởng 1 làm được là

405 - 270 = 135 (sản phẩm)

                Đáp số: .....

sao hỏi

trong LQ ý

combo nakroth

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