\(\frac{x-1}{3}+\frac{3x-5}{2}+\frac{2x}{9}+\frac{-5x+3}{9}=\frac{210}{420}\)

\(\Leftrightarrow\frac{x-1}{3}+\frac{3x-5}{2}+\frac{-3x+3}{9}=\frac{1}{2}\)

\(\Leftrightarrow\frac{6\left(x-1\right)}{18}+\frac{9\left(3x-5\right)}{18}+\frac{2\left(-3x+3\right)}{18}=\frac{9}{18}\)

\(\Rightarrow6x-6+27x-45-6x+6=9\)

\(\Leftrightarrow6x+27x-6x=9+6+45-6\)

\(\Leftrightarrow27x=54\)

\(\Rightarrow x=2\)

cái này sai đề bài

\(\dfrac{x-1}{3}\)+\(\dfrac{3x-5}{2}+\dfrac{2x}{9}+\dfrac{-5x+3}{9}=\dfrac{210}{420}\)

\(\Leftrightarrow\)\(\dfrac{x-1}{3}+\dfrac{3x-5}{2}\)\(+\dfrac{-3x+3}{9}\)\(=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{6\left(x-1\right)}{18}+\dfrac{9\left(3x-5\right)}{18}\)\(+\dfrac{2\left(-3x+3\right)}{18}=\dfrac{9}{18}\)

\(\Rightarrow\)\(6x-6+27x-45-6x+6=9\)

\(\Leftrightarrow\)\(6x+27x-6x=9+6+45-6\)

\(\Leftrightarrow27x=54\)

\(\Rightarrow\)\(x=2\)

\(\left(X+5\right)-\left(X-9\right)=X+2\)\(2\)

\(=>X+5-X+9=X+2\)

\(=>\left(X-X\right)+\left(5+9\right)=X+2\)

 \(=>0+14=X+2\)

\(=>14=X+2\)

\(=>X=12\)

(x+5)-(x-9)=x+2

x+5-x+9=x+2

x-x+14=x+2

12=x(cũng bớt mới về đi 2 đơn vị)

hoặc x=14-2suy ra x=12

làm cau 2 đi mk tích

=>\(\frac{6\left(x-1\right)}{18}+\frac{9\left(3x-5\right)}{18}+\frac{2\left(2x\right)}{18}+\frac{2\left(-5x+3\right)}{18}=\frac{1}{2}\)

=>\(\frac{6x-6}{18}+\frac{27x-45}{18}+\frac{4x}{18}+\frac{-10x+6}{18}=\frac{1}{2}\)

=>\(\frac{\left(6x-6\right)+\left(27x-45\right)+4x+\left(-10x+6\right)}{18}=\frac{1}{2}\)

=>\(\frac{27x-45}{18}=\frac{1}{2}\)

=>54x-90=18

54x =108

=>x=2

quy đồng lên rồi nhân chéo rồi giải

x=2

x=2 nhớ k  cho mình nha

a: -x+5/9=-1/3

nên x=5/9+1/3=5/9+3/9=8/9

b: \(\Leftrightarrow\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{11}{15}< x< \dfrac{1}{2}+\dfrac{13}{12}+\dfrac{1}{3}\)

=>31/30<x<23/12

mà x là số nguyên

nên \(x\in\varnothing\)

c: x+5/3=1/81

nên x=1/81-135/81=-134/81

kh hiểu bn ơi

`4x=2+xx+1x<=>4x=2+3x<=>4x-3x=2<=>1x=2<=>x=2`

MSC:1260

(x - 1).420\1260 + (3x - 5).630\1260 + 2.x.140/1260 + (-5x + 3).140\1260 =630\1260

=>(x - 1).420 + (3x - 5).630 + 2.x.140 + (-5x + 3).140 = 630

x.420 -  420 + 1890.x - 3150 + x.280 + (-700).x +420 = 630

x.( 420 + 1890 + 280 + -700) - (420 + 3150 -420) = 630

x.1890 - 3150 = 630

x.1890            = 630 + 3150

x.1890            =3780

x                      =3780 : 1890

x                      =2

 Tíck cho mình nhé và chúc bạn học giỏi !

Sai chỗ nào thì bạn sửa cho mình nhé!

ta có:

\(1+\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+...+\frac{1}{x\left(x+3\right)}\)=1\(\frac{7}{24}\)\(=\frac{31}{24}\)

\(1+\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{x\left(x+3\right)}=\frac{31}{24}\)

\(3+\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{x\left(x+3\right)}=\frac{31}{3}\)

\(3+1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{31}{3}\)

\(3+1-\frac{1}{x+3}=\frac{31}{3}\)

\(4-\frac{1}{x+3}=\frac{31}{3}\)

\(\frac{1}{x+3}=4-\frac{31}{3}=\frac{-19}{3}\)

=>ko tìm được x

Nguyễn Minh Châu giải sai rồi